Mdls + grep + output

Question

Hi Folks,
I have a large directory of images whose dimensions and filename I need to output to a text file.
Using the following from the command line, I can get the results of one of the fields:
#mdls filename.jpg | grep kMDItemPixelHeight > ~/Desktop/mdls.out
However, I'd like to grab three fields from each file, and separate them each on a row (separated/delimited by comma or tab), so they will look like this:
filename.jpg 500 300
filename2.jpg 515 301
filename3.jpg 503 299
etc, etc
The fields I need to grep from mdls are:
kMDItemPixelHeight
kMDItemPixelWidth
kMDItemDisplayName
Any help, suggestions most appreciated.
Best, Doug

Answer 1

Camelot wrote:
Once you have the mdls command giving you the output you want, there are a number of tools that will convert it into the format you want.
Here's one example that uses awk:
<pre class=command>mdls -name kMDItemPixelHeight -name kMDItemPixelWidth -name kMDItemDisplayName *jpg| awk '/jpg/ {name=$3;getline;height=$3;getline;width=$3;print (name, height, width)}'</pre>
Hmm. I can't get that to work on my computer. I get this:
"Blanca-PowerBookBW.jpg" 900
"Blanca-PowerBookColor.jpg" 900
"TL-BlackCanyon.jpg" 341
But if I mess with it a bit, I can do it all in one line like this (using part of what you posted):
mdls -name kMDItemPixelHeight -name kMDItemPixelWidth -name kMDItemDisplayName *jpg | sed 's/"//g' | awk '/=/ {name=$3;getline;height=$3;getline;width=$3;printf("%s     %s     %s
",name, height, width)}' > ~/Desktop/mdls.out