[SOLVED] grep output matching parts only

Question

I want grep to output only what it matched, but according the man page, it will put each matching part on a separate line, which does not work for me. I am matching two numbers, but they don't get output together, but each on a separate line. Any idea how to fix this?
Here is my code:
[x@arch ~]$ sudo hddtemp /dev/sda|cut -f4 -d" "|grep [[:digit:]+] -o
4
6
Last edited by awayand (2012-03-31 05:08:06)

Answer 1

awayand wrote:
genius. thanks, dev/zero!
sudo hddtemp /dev/sda |cut -f4 -d" "|tr -cd [:digit:]
Haha, the actual solution you found is more elegant than the one I had in mind!
sudo hddtemp /dev/sda | cut -f4 -d" " | grep [[:digit:]+] -o | tr '\n' ' ' | sed 's| ||g'