Messy One to Many Joins and Grouping

I manage websites for a large state agency in Texas. I have a
need to redo
queries that list the Local intake numbers for Long term
support services
(LTSS), Area Agencies on Aging (AAA), and Mental Retardation
Authorities
(MRA) by county for each of the state's 254 counties -- in
the past there
was only one intake number per county for each AAA and MRA,
with there being
the possibility for multiple LTSS intake numbers. Now there
are counties
that have multiple numbers for MRA intake.
Basic Structure of Database Tables:
CountyCenter Table
County (text)
CountyNumber (integer)
AAA_ID (integer)
MRA_ID (integer)
LTSS Table
County (text)
CountyNumber (integer)
City (text) -- optional used when there are multiple offices
for a county
IntakeNumber (text)
Region (text)
AAA Table
AAA_ID (integer)
AAAName (text)
AAAPhone (text)
MRA Table
MRA_ID (integer)
MRAName (text)
MRAPhone
MRAOffices
MRA_ID (integer)
IntakePhone (text)
City (Text)
CountyNumber (integer)
My goal is for each county to list in a combined table:
Column 1 = County Name
Column 2 = LTSS Office (Number(s))
Column 3 = MRA Intake Number
Column 4 = AAA Intake Number(s)/City if not main
Do I need a separate table for county that simply has the
CountyNumber and
CountyName to use as a control table?
I'd like to do this as efficiently as possible -- thankfully
the query won't
be accessed by the general public and will be run only when
updated
information is received. Any suggestions as to order of the
joins and
groupings in CFOUTPUT? (what I have now creates a lot of
duplication)
Thanks in advance for your help,
Michael Brown
Webmaster, Texas Department of Aging and Disability Services

Phil,
Thanks for taking a look. You're definitely right. The data
structures are a mess. What was originally intended to be on
three
separate pages has been requested to be "available at a
glance."
With both the LTSS Offices and MRAs having the possiblity of
multiple offices for a given county what would be the best
way to
normalize the data? The tables for MRA, AAA, and LTSS have
CountyNumber (county exists only in those tables to provide
context for those who update the information manually (not my
choice/decision)).
So to break it down 254 Counties, each can have one or
multiple
LTSS numbers (and the number's city), only one AAA number,
and one
MRA with the possiblity for multiple intake numbers (and note
containing location information).
Hopefully, there is a graceful way of getting the output the
way
it has been requested. I'm open to suggestions.
Thanks again,
Michael
"paross1" <[email protected]> wrote in
news:[email protected]:
> After taking a quick glance, it looks like you already
have
> normalization issues with your data model, since LTSS
Table and
> CountyCenter Table both contain County (text), and
MRAOffices
and LTSS
> Table both have City (text), etc. It is hard to tell
which
fields are
> primary keys and which are foreign keys to which tables.
Some of
these
> that may have a one-to-many relationship that now
changes to a
> many-to-many will require a link table (associative
entity) and
the
> foreign keys migrated to them.
>
> You need to resist creating actual "combined tables",
spreadsheet
> style, and
> instead normalize your database, so that you can create
your
"combined
> table" virtually using SQL. It is hard to offer
specifics, since
I
> would need more information to do so, but the bottom
line is
that you
> do have some obvious data model issues that need to be
resolved
before
> you can get much further. Otherwise, you are going to
have to
write
> some very kludgey SQL to solve your problem with your
current
model.
>
> Phil
>
>

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SELECT "NUMBER" as danumber,
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SMINCREQ.ASSIGNMENT,
SMOPERATOR.PRIMARY_ASSIGNMENT_GROUP,
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Hi,
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Since you didn't post CREATE TABLE and INSERT statements for your sample data, I'll use tables from the scott schema to show how this is done.
Say you have a query like this:
SELECT       d.dname
,       e.empno, e.ename, e.job, e.sal
FROM       scott.dept d
JOIN       scott.emp   e ON   d.deptno = e.deptno
ORDER BY dname
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ACCOUNTING           7839 KING       PRESIDENT       5000
ACCOUNTING           7782 CLARK      MANAGER         2450
RESEARCH             7876 ADAMS      CLERK           1100
RESEARCH             7902 FORD       ANALYST         3000
RESEARCH             7566 JONES      MANAGER         2975
RESEARCH             7369 SMITH      CLERK            800
RESEARCH             7788 SCOTT      ANALYST         3000
SALES                7521 WARD       SALESMAN        1250
SALES                7844 TURNER     SALESMAN        1500
SALES                7499 ALLEN      SALESMAN        1600
SALES                7900 JAMES      CLERK            950
SALES                7698 BLAKE      MANAGER         2850
SALES                7654 MARTIN     SALESMAN        1250Now say you want to change the query so that it only returns one row per department, like this:
DNAME               EMPNO ENAME      JOB              SAL
ACCOUNTING           7782 CLARK      MANAGER         2450
RESEARCH             7876 ADAMS      CLERK           1100
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One way to do it is to use the analytic ROW_NUMBER function to assign a sequence of unique numbers (1, 2, 3, ...) to all the rows in each department. Since each sequence startw with 1, and the numbers are unique within a department, there will be exactly one row per departement that was assigned the numebr 1, and we''ll display that row.
Here's how to code that:
WITH     got_r_num     AS
     SELECT     d.dname
     ,     e.empno, e.ename, e.job, e.sal
     ,     ROW_NUMBER () OVER ( PARTITION BY d.dname
                               ORDER BY         e.ename
                       )         AS r_num
     FROM     scott.dept d
     JOIN     scott.emp   e ON   d.deptno = e.deptno
SELECT       dname
,       empno, ename, job, sal
FROM       got_r_num
WHERE       r_num     = 1
ORDER BY dname
;Notice that he sub-query got_r_num is almost the same as the original query; only it has one additional column, r_num, in the SELECT clause, and the sub-qeury does not have an ORDER BY clause. (Sub-queries almost never have an ORDER BY clause.)
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I was asked many times how to resolve many to many relationship between two tables. I read to use 2 one -to- many relationships to resolve this. Can some expalin me when many to many relationship occurs between two tables and how to reslove them with practicle examples. Is there any article on this?
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Hi,
Please check below link.
http://www.forumtopics.com/busobj/viewtopic.php?p=859029&sid=20d79e3df07b0d8b41aadfbd902bb6b2
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Need help in optimizing the query with joins and group by clause

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(FILE_ID VARCHAR2(14),
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TOT_REC NUMBER,
TOT_SUCC NUMBER);
CREATE TABLE COMM
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STATUS CHAR(1));
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INSERT INTO COMM VALUES ('12345678', 3, 'T');
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I get 2 rows if I use my query with your new criteria. Did you commit the record if you are using a second connection to query? Did you remove the criteria for file_id?
select carr_cd, file_name, file_id, tot_rec, tot_succ, tot_trans
from (select fs.carr_cd,
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CARR_CD FILE_NAME            FILE_ID           TOT_REC   TOT_SUCC TOT_TRANS
LIBM    CM_LIBM.TXT          12345678                5          4          2
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from file_status fs
left join comm c
on c.src_file_id = fs.file_id
where carr_cd = 'LIBM';
CARR_CD FILE_NAME            FILE_ID           TOT_REC   TOT_SUCC TOT_TRANS         RN
LIBM    CM_LIBM.TXT          12345678                5          4          2          1
LIBM    CM_LIBM.TXT          12345678                5          4          2          2
LIBM    CM_LIBM.TXT          12345678                5          4          2          3
LIBM    CM_LIBM.TXT          12345678                5          4          2          4
LIBM    CM_LIBM.TXT          12345677               10          0          0          1

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What is the best way to do this ?
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Another way to explain my case:
how to do this in UnitOfWork ?
function modifyAVectorOfB(A, vectorOfC)
AClone = uow.registerObject(A);
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uow.commit;
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Something like this?
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3 SELECT 'title 2' FROM dual UNION ALL
4 SELECT 'title 3' FROM dual ),
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title 1                                                           14
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Please help folks,
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// Systematically generate combinations.
import java.math.BigInteger;
public class CombinationGenerator {
private int[] a;
private int n;
private int r;
private BigInteger numLeft;
private BigInteger total;
// Constructor
public static void main(String[] args)
String[] elements = {"a", "b", "c", "d", "e", "f", "g"};
int[] indices;
CombinationGenerator x = new CombinationGenerator (elements.length, 3);
StringBuffer combination;
while (x.hasMore ()) {
combination = new StringBuffer ();
indices = x.getNext ();
for (int i = 0; i < indices.length; i++) {
combination.append (elements[indices[i]]);
System.out.println (combination.toString ());
public CombinationGenerator (int n, int r) {
if (r > n) {
throw new IllegalArgumentException ();
if (n < 1) {
throw new IllegalArgumentException ();
this.n = n;
this.r = r;
a = new int[r];
BigInteger nFact = getFactorial (n);
BigInteger rFact = getFactorial (r);
BigInteger nminusrFact = getFactorial (n - r);
total = nFact.divide (rFact.multiply (nminusrFact));
reset ();
// Reset
public void reset () {
for (int i = 0; i < a.length; i++) {
a[i] = i;
numLeft = new BigInteger (total.toString ());
// Return number of combinations not yet generated
public BigInteger getNumLeft () {
return numLeft;
// Are there more combinations?
public boolean hasMore () {
return numLeft.compareTo (BigInteger.ZERO) == 1;
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public BigInteger getTotal () {
return total;
// Compute factorial
private static BigInteger getFactorial (int n) {
BigInteger fact = BigInteger.ONE;
for (int i = n; i > 1; i--) {
fact = fact.multiply (new BigInteger (Integer.toString (i)));
return fact;
// Generate next combination (algorithm from Rosen p. 286)
public int[] getNext () {
if (numLeft.equals (total)) {
numLeft = numLeft.subtract (BigInteger.ONE);
return a;
int i = r - 1;
while (a[i] == n - r + i) {
i--;
System.out.println("inside while");
a[i] = a[i] + 1;
for (int j = i + 1; j < r; j++) {
a[j] = a[i] + j - i;
numLeft = numLeft.subtract (BigInteger.ONE);
return a;

Next time you post, see the formatting guidelines [url http://forum.java.sun.com/features.jsp#Formatting]here. //--------------------------------------
// Systematically generate combinations.
import java.math.BigInteger;
public class CombinationGenerator {
private int[] a;
private int n;
private int r;
private BigInteger numLeft;
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combination.append (elements[indices]);
System.out.println (combination.toString ());
public CombinationGenerator (int n, int r) {
if (r > n) {
throw new IllegalArgumentException ();
if (n < 1) {
throw new IllegalArgumentException ();
this.n = n;
this.r = r;
a = new int[r];
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BigInteger nminusrFact = getFactorial (n - r);
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reset ();
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public void reset () {
for (int i = 0; i < a.length; i++) {
a = i;
numLeft = new BigInteger (total.toString ());
// Return number of combinations not yet generated
public BigInteger getNumLeft () {
return numLeft;
// Are there more combinations?
public boolean hasMore () {
return numLeft.compareTo (BigInteger.ZERO) == 1;
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public BigInteger getTotal () {
return total;
// Compute factorial
private static BigInteger getFactorial (int n) {
BigInteger fact = BigInteger.ONE;
for (int i = n; i > 1; i--) {
fact = fact.multiply (new BigInteger (Integer.toString (i)));
return fact;
// Generate next combination (algorithm from Rosen p. 286)
public int[] getNext () {
if (numLeft.equals (total)) {
numLeft = numLeft.subtract (BigInteger.ONE);
return a;
int i = r - 1;
while (a == n - r + i) {
i--;
System.out.println("inside while");
a = a + 1;
for (int j = i + 1; j < r; j++) {
a[j] = a + j - i;
numLeft = numLeft.subtract (BigInteger.ONE);
return a;
}

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Child Class Positionen
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7 select distinct ED.iIdExpedicion, ED.iIdExpedicionDiaria,
8 MAX(PT.iOrdenEnTrayecto) + 1 as iNumParadas,
9 MAX(HPP.iOrden) as iOrdenUltimaParada,
10 MIN(dtHora_LlegadaReal + iTiempoEnParada/(24*60*60)) as dtHoraInicioReal,
11 MAX(dtHora_LlegadaReal) as dtHoraFinReal,
12 100 * cast ((MAX(HPP.iOrden) + 1) as float) / cast ((MAX(PT.iOrdenEnTrayecto) + 1) as float) as fPorcentajeRealizado
13 from HISTORICOS_AVANZA.HSAE_HIS_EXPEDICIONDIARIA ED
14 left join HISTORICOS_AVANZA.HSAE_HIS_HORAPASOPARADA HPP
15 on ED.iIdExpedicion = HPP.iIdExpedicion and ED.dtJornada = HPP.dtJornada
16 left join AVANZA.SAE_URB_PARADASTRAYECTO PT on ED.iIdLinea = PT.iIdLinea and ED.iIdTrayecto = PT.iIdTrayecto
17 where ED.dtJornada = TO_DATE('14/01/2013', 'DD/MM/YYYY') and ED.iIdExpedicion in (-131076)
18 group by ED.iIdExpedicion, ED.iIdExpedicionDiaria, ED.dtHoraInicioReal, ED.dtHoraFinReal
19 having ED.dtHoraInicioReal <> min(dtHora_LlegadaReal + iTiempoEnParada/(24*60*60))
20 or ED.dtHoraFinReal <> max(dtHora_LlegadaReal)
21 ) ED_Query
22 on ED_Update.iIdExpedicionDiaria = ED_Query.iIdExpedicionDiaria;
ERROR at line 5:
ORA-00933: SQL command not properly ended
The subquery (ED_Query) work fine in Oracle, so I suspect that the problems are when I mix it with the update clause.
SQL> select distinct ED.iIdExpedicion, ED.iIdExpedicionDiaria,
2 MAX(PT.iOrdenEnTrayecto) + 1 as iNumParadas,
3 MAX(HPP.iOrden) as iOrdenUltimaParada,
4 MIN(dtHora_LlegadaReal + iTiempoEnParada/(24*60*60)) as dtHoraInicioReal,
5 MAX(dtHora_LlegadaReal) as dtHoraFinReal,
6 100 * cast ((MAX(HPP.iOrden) + 1) as float) / cast ((MAX(PT.iOrdenEnTrayecto) + 1) as float) as fPorcentajeRealizado,
7 ED.dtHoraInicioReal as ED_dtHoraInicioReal, ED.dtHoraFinReal as ED_dtHoraFinReal, ED.fPorcentajeRealizado as ED_fPorcentajeRealizado
8 from HISTORICOS_AVANZA.HSAE_HIS_EXPEDICIONDIARIA ED
9 left join HISTORICOS_AVANZA.HSAE_HIS_HORAPASOPARADA HPP
10 on ED.iIdExpedicion = HPP.iIdExpedicion and ED.dtJornada = HPP.dtJornada
11 left join AVANZA.SAE_URB_PARADASTRAYECTO PT on ED.iIdLinea = PT.iIdLinea and ED.iIdTrayecto = PT.iIdTrayecto
12 where ED.dtJornada = TO_DATE('14/01/2013', 'DD/MM/YYYY') and ED.iIdExpedicion in (-131076)
13 group by ED.iIdExpedicion, ED.iIdExpedicionDiaria, ED.dtHoraInicioReal, ED.dtHoraFinReal, ED.fPorcentajeRealizado
14 having ED.dtHoraInicioReal <> min(dtHora_LlegadaReal + iTiempoEnParada/(24*60*60))
15 or ED.dtHoraFinReal <> max(dtHora_LlegadaReal);
IIDEXPEDICION IIDEXPEDICIONDIARIA INUMPARADAS IORDENULTIMAPARADA DTHORAINI
DTHORAFIN FPORCENTAJEREALIZADO ED_DTHORA ED_DTHORA ED_FPORCENTAJEREALIZADO
-131076 5662 406 15-JAN-13
15-JAN-13 15-JAN-13 15-JAN-13 0
-131076 5663 406 15-JAN-13
15-JAN-13 15-JAN-13 15-JAN-13 0
-131076 5664 406 15-JAN-13
15-JAN-13 15-JAN-13 15-JAN-13 0
After reading this forum, I change the query and try the next one:
SQL> UPDATE
2 (
3 select distinct ED.iIdExpedicion, ED.iIdExpedicionDiaria,
4 MAX(PT.iOrdenEnTrayecto) + 1 as iNumParadas,
5 MAX(HPP.iOrden) as iOrdenUltimaParada,
6 MIN(dtHora_LlegadaReal + iTiempoEnParada/(24*60*60)) as dtHoraInicioReal,
7 MAX(dtHora_LlegadaReal) as dtHoraFinReal,
8 100 * cast ((MAX(HPP.iOrden) + 1) as float) / cast ((MAX(PT.iOrdenEnTrayecto) + 1) as float) as fPorcentajeRealizado,
9 ED.dtHoraInicioReal as ED_dtHoraInicioReal, ED.dtHoraFinReal as ED_dtHoraFinReal, ED.fPorcentajeRealizado as ED_fPorcentajeRealizado
10 from HISTORICOS_AVANZA.HSAE_HIS_EXPEDICIONDIARIA ED
11 left join HISTORICOS_AVANZA.HSAE_HIS_HORAPASOPARADA HPP
12 on ED.iIdExpedicion = HPP.iIdExpedicion and ED.dtJornada = HPP.dtJornada
13 left join AVANZA.SAE_URB_PARADASTRAYECTO PT on ED.iIdLinea = PT.iIdLinea and ED.iIdTrayecto = PT.iIdTrayecto
14 where ED.dtJornada = TO_DATE('14/01/2013', 'DD/MM/YYYY') and ED.iIdExpedicion in (-131076)
15 group by ED.iIdExpedicion, ED.iIdExpedicionDiaria, ED.dtHoraInicioReal,ED.dtHoraFinReal, ED.fPorcentajeRealizado
16 having ED.dtHoraInicioReal <> min(dtHora_LlegadaReal + iTiempoEnParada/(24*60*60))
17 or ED.dtHoraFinReal <> max(dtHora_LlegadaReal)
18 )
19 SET ED_dtHoraInicioReal = dtHoraInicioReal,
20 ED_dtHoraFinReal = dtHoraFinReal,
21 ED_fPorcentajeRealizado = fPorcentajeRealizado;
ERROR at line 2:
ORA-01732: data manipulation operation not legal on this view
Some help?
Thanl in advance.
Edited by: 984483 on 28-ene-2013 1:48

Thanks for your answer. I tried to rewrite my question.
SQL> select * from v$version;
BANNER
Oracle9i Enterprise Edition Release 9.2.0.3.0 - Production
PL/SQL Release 9.2.0.3.0 - Production
CORE 9.2.0.3.0 Production
TNS for 32-bit Windows: Version 9.2.0.3.0 - Production
NLSRTL Version 9.2.0.3.0 - Production
I have 2 tables. I like to update one of them (ED_Update) with the data from the another one (ED_Query).
This example is equivalent:
create table ED_Query (id number,
     date01 date,
number01 number)
insert into ED_Query values (1, to_date('01/01/2013','DD/MM/YYYY'), 10);
insert into ED_Query values (2, to_date('01/01/2013','DD/MM/YYYY'), 20);
insert into ED_Query values (3, to_date('01/01/2013','DD/MM/YYYY'), 30);
insert into ED_Query values (4, to_date('02/01/2013','DD/MM/YYYY'), 40);
insert into ED_Query values (5, to_date('03/01/2013','DD/MM/YYYY'), 50);
create table ED_Update (date01 date,
          numberMax number,
          numberSum number)
insert into ED_Update values (to_date('01/01/2013','DD/MM/YYYY'), 0, 0);
insert into ED_Update values (to_date('02/01/2013','DD/MM/YYYY'), 0, 0);
insert into ED_Update values (to_date('03/01/2013','DD/MM/YYYY'), 0, 0);
The next update query fails with ORA-00933: SQL command not properly ended.
update ED_Update
set ED_Update.date01 = ED_Query.date01,
     ED_Update.numberMax = ED_Query.numberMax,
     ED_Update.numberSum = ED_Query.numberSum
inner join
     select date01, max (number01) as numberMax, sum(number01) as numberSum
     from ED_Query
     where date01 = TO_DATE('01/01/2013', 'DD/MM/YYYY')
     group by date01
) ED_Query
on ED_Update.date01 = ED_Query.date01
I think the problem is in the update clause because the next query work:
select * from
ED_Update
inner join
     select date01, max (number01) as numberMax, sum(number01) as numberSum
     from ED_Query
     where date01 = TO_DATE('01/01/2013', 'DD/MM/YYYY')
     group by date01
) ED_Query
on ED_Update.date01 = ED_Query.date01
Thank in advance.

Inner join and group by

Hi Friends,
My code is;
SELECT T1~NUMBER SUM( T2~QUANT )
INTO (ZTABLE1-NUMBER, ZTABLE2-QUANT)
FROM ZTABLE1 AS T1
INNER JOIN ZTABLE2 AS T2
ON T1~NUMBER = T2~NUMBER
GROUP BY T2~VBELN.
ENDSELECT.
I am getting an error as;
The field T1~NUMBER from SELECT is missing in the GROUP BY clause. addition INTO wa or INTO(g1,...,gn) is required. fields of type "" or "T2-VBELN".
I couldn't understand anything from the error message. Can you help what the error message says and how can I do my desire on above query.
Thanks.

Usually GROUP BY Is used to get only aggregated fields.
It is not meant for regular selection of fields.
Instead do a regular selection of all the fields without group by and do your aggregation in program logic as per your requirement.
In that way your performance will be better.
Regards
Sudhir Atluru

Help with exercise on joins and group by

Could someone help me with an exercise I'm working on? This isn't "homework", per se, as it's not an assignment, I'm just doing my own personal research.
I have the usual tables "DEPARTMENT" and "EMPLOYEE", with the following columns:
Department:
* NAME
* ID
Employee:
* SSN
* NAME
* DEPT_ID
* SALARY
I'm able to build a query that summarizes the departments with total employee salary > 30000, like this:
select dept_id, sum(salary) from employee group by dept_id having sum(salary) > 30000;
What I'd like to extend this to is a summary of departments with total employee salary > 30000 OR no employees at all (or total salary = 0, conceptually).
I imagine this will include a left outer join, but I can't get this to work.

http://download.oracle.com/docs/cd/B19306_01/server.102/b14223/aggreg.htm#sthref1670
http://www.oracle.com/technology/products/oracle9i/daily/oct10.html
http://www.dba-oracle.com/t_sql99_with_clause.htm
http://www.psoug.org/reference/with.html
WITH clause is used for reusability of sub queries within a query. And in this case it is useful to build the query without having to create a table with data and show the results.
SQL> select 1 dept_id, 'ABC' dept_name from dual;
   DEPT_ID DEP
         1 ABCHere I am selecting some static values from dual table where I say I want 1 as dept_id and its name as ABC.
SQL> select 1 dept_id, 'ABC' dept_name from dual union all
2      select 2 dept_id, 'XYZ' dept_name from dual union all
3      select 3 dept_id, 'MNO' dept_name from dual;
   DEPT_ID DEP
         1 ABC
         2 XYZ
         3 MNOIn the above query I am selecting 3 static department ids and names in three separate queries and combining them using union all. Thus I am getting them as three rows.
SQL> with dept as(
2      select 1 dept_id, 'ABC' dept_name from dual union all
3      select 2 dept_id, 'XYZ' dept_name from dual union all
4      select 3 dept_id, 'MNO' dept_name from dual )
5 --
6 select * from dept;
   DEPT_ID DEP
         1 ABC
         2 XYZ
         3 MNOHere, In the above query, I just named the previous query as "dept" and I am just selecting all from "dept". You can say it something like a virtual table which has data based on a query, that can be reused in other/main query. The limitations, uses and elaborate descriptions are available in the links I provided.

HT1212 my daughter has a brand new ipod touch - never used - she entered a passcode then immediately forgot it and now she has tried to enter one too many times and ipod is locked for 1 hour - she has never synced with itunes HELP

my daughter has a brand new ipod touch - latest one - she started to input a passcode then didn't finish the process then turned off ipod. she turned it back on and it is asking for a passcode - she doesn't remember what she typed. Ipod is now disabled for one hour. Can we override the disable. How do we reset passcode when we don't klnow the original. It has never been synced to Itunes. I am completely lost.

If You Are Locked Out Or Have Forgotten Your Passcode
iTunes 10 for Mac- Update and restore software on iPod, iPhone, or iPad
iPhone, iPad, iPod touch: Wrong passcode results in red disabled screen
iOS- Understanding passcodes
     If you have forgotten your Restrictions code, then follow the instructions
     below but DO NOT restore any previous backup. If you do then you will
     simply be restoring the old Restrictions code you have forgotten. This
     same warning applies if you need to restore a clean system.
A Complete Guide to Restore or Recover Your iDevice (if You Forget Your Passcode)
If you need to restore your device or ff you cannot remember the passcode, then you will need to restore your device using the computer with which you last synced it. This allows you to reset your passcode and re-sync the data from the device (or restore from a backup). If you restore on a different computer that was never synced with the device, you will be able to unlock the device for use and remove the passcode, but your data will not be present. Refer to Updating and restoring iPhone, iPad and iPod touch software.
Try restoring the iOS device if backing up and erasing all content and settings doesn't resolve the issue. Using iTunes to restore iOS devices is part of standard isolation troubleshooting. Restoring your device will delete all data and content, including songs, videos, contacts, photos, and calendar information, and will restore all settings to their factory condition.
Before restoring your iOS device, Apple recommends that you either sync with iTunes to transfer any purchases you have made, or back up new data (data acquired after your last sync). If you have movie rentals on the device, see iTunes Store movie rental usage rights in the United States before restoring.
Follow these steps to restore your device:
     1. Verify that you are using the latest version of iTunes before attempting to update.
     2. Connect your device to your computer.
     3. Select your iPhone, iPad, or iPod touch when it appears in iTunes under Devices.
     4. Select the Summary tab.
     5. Select the Restore option.
     6. When prompted to back up your settings before restoring, select the Back Up
         option (see in the image below). If you have just backed up the device, it is not
         necessary to create another.
     7. Select the Restore option when iTunes prompts you (as long as you've backed up,
         you should not have to worry about restoring your iOS device).
     8. When the restore process has completed, the device restarts and displays the Apple
         logo while starting up:
           After a restore, the iOS device displays the "Connect to iTunes" screen. For updating
          to iOS 5 or later, follow the steps in the iOS Setup Assistant. For earlier versions of
          iOS, keep your device connected until the "Connect to iTunes" screen goes away or
          you see "iPhone is activated."
     9. The final step is to restore your device from a previous backup. If you do not have a
          backup to restore, then restore as New.

Messy One to Many Joins and Grouping

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