Metadata property as Details Property in Details Screen

Question

Hi,
is there any way (java class) to display a metadata property as a details property in a details screen (I think the default details area is overview_description).
Thanks in advance.
Regards
Ray

Answer 1

Hi,
you can create a class that extends AbstractResourceDetailsProperties and renders a metadata property, similiar to the standard ModifiedDetailsProperty, for example, that renders the Modified Property.
For example if I have a property named Customer I would create a class called CustomerDetailsProperty something like this:
public class CustomerDetailsProperty extends AbstractResourceDetailsProperties {
     public CustomerDetailsProperty() {
     public boolean isPropertyAvailable(IResource resource) {
          com.sapportals.wcm.repository.IProperty tempProperty = null;
          try {
               if (getPropertyName() != null)
                    tempProperty = resource.getProperty(getPropertyName());
          } catch (ResourceException rEx) {
               log.errorT("Could not check property availability for resource < "
                         + resource
                         + " > "
                         + LoggingFormatter.extractCallstack(rEx));
               return false;
          return tempProperty != null;
     public Component renderDetailsProperty(IResource resource) {
          try {
               com.sapportals.wcm.repository.IProperty customerProp = null;
               com.sapportals.wcm.repository.IProperty tempProperty = null;
               if (getPropertyName() != null) {
                    tempProperty = resource.getProperty(getPropertyName());
                    customerProp =     resource.getProperty(PropertyName.getPN("http://sapportals.com/xmlns/cm", "Customer"));
               if (tempProperty != null) {
                    String header =     getPropertyLabel(tempProperty, resource.getContext());
                    GridLayout grid = new GridLayout();
                    grid.addComponent(1, 1,     renderShortDateProperty(tempProperty, resource));
                    if (customerProp != null) {
                         Component customer = PropertyRenderUtil.renderProperty(customerProp , resource,     0);
                         Link userLink = null;
                         if (customer instanceof Link) {
                              userLink = (Link) customer;
                              userLink.setLinkDesign(LinkDesign.RESULT);
                              grid.addComponent(2, 1, userLink);
                              grid.getCell(2, 1).setWidth(";padding-bottom:3px;");
                         } else {
                              grid.addComponent(2, 1, customer);
                              grid.getCell(2, 1).setWidth(";padding-bottom:3px;");
                    return render(header, grid);
               } else {
                    return null;
          } catch (WcmException wcmEx) {
               log.errorT(
                    "Could not render lock property for resource < "
                         + resource
                         + " > "
                         + LoggingFormatter.extractCallstack(wcmEx));
          return null;
     public IResourceDetailsProperty getNewInstance(int priority) {
          CustomerDetailsProperty detailsProperty = new CustomerDetailsProperty();
          detailsProperty.setPriority(priority);
          return detailsProperty;
     public IPropertyName getPropertyName() {
          try {
               return PropertyName.getPN("http://sapportals.com/xmlns/cm", "Customer");
          } catch (ResourceException e) {
               e.printStackTrace();
               return null;
     static Class _mthclass$(String x0) {
          try {
               return Class.forName(x0);
          } catch (ClassNotFoundException x1) {
               throw new NoClassDefFoundError(x1.getMessage());
     private static Location log =
          Location.getLocation((com.mycompny.CustomerDetailsProperty.class).getName());
Best regards,
Avishai Zamir