Multiple BP relationships

Hi gurus,
I need help on the foll issue -
We are on SRM 5.0 having HR replication from ECC 6.0. Recently few users changed position. When these were replicated from back end, an additional 'Is Employee of ' relationship was created for new org unit. The problem is that earlier relationship did not get deleted. Thus we have multiple BP relationships for these users. As I understand ( and also mentioned in few threads) , we should have only 1 BP-BP relationship ( 'Is employee of').
I have gone through most of the relevant threads on this forum as well as OSS notes, but could not get an accurate resolution.
Please help at the earliest,
Regards,
SB

Hi Satish,
Thx for your reply. It is not possible to delete relationships in SRM as we have HR replication active.
Could you please specify how we can delete relationships in ECC- T code/prog?
also we do not want any new BPs to be created.
regds,
SB

Similar Messages

Multiple referenced relationships over the same intermediate dimension - generated processing query

Hi, I know the title is a bit confusing so let me try to explain it:
I have added 3 new dimensions do the AdventureWorks cube - RefA, RefB and RefC:
They are all related to the DimReseller table, and finally, to the FactResellerSales table. In the dimension usage chart, you can see that there are 4 referenced relationships using the Reseller dimension as the intermediate dimension. The Geography
was the existing one, and the other 3 were added.
Now, if I process a partition from the Reseller Sales measure group, the Profiler catches this generated query on the server:
SELECT [dbo_FactResellerSales].[dbo_FactResellerSalesSalesAmount0_0] AS [dbo_FactResellerSalesSalesAmount0_0]
,[dbo_FactResellerSales].[dbo_FactResellerSalesOrderQuantity0_1] AS [dbo_FactResellerSalesOrderQuantity0_1]
,[dbo_FactResellerSales].[dbo_FactResellerSalesExtendedAmount0_2] AS [dbo_FactResellerSalesExtendedAmount0_2]
,[dbo_FactResellerSales].[dbo_FactResellerSalesTaxAmt0_3] AS [dbo_FactResellerSalesTaxAmt0_3]
,[dbo_FactResellerSales].[dbo_FactResellerSalesFreight0_4] AS [dbo_FactResellerSalesFreight0_4]
,[dbo_FactResellerSales].[dbo_FactResellerSalesDiscountAmount0_5] AS [dbo_FactResellerSalesDiscountAmount0_5]
,[dbo_FactResellerSales].[dbo_FactResellerSalesUnitPrice0_6] AS [dbo_FactResellerSalesUnitPrice0_6]
,[dbo_FactResellerSales].[dbo_FactResellerSalesUnitPriceDiscountPct0_7] AS [dbo_FactResellerSalesUnitPriceDiscountPct0_7]
,[dbo_FactResellerSales].[dbo_FactResellerSalesTotalProductCost0_8] AS [dbo_FactResellerSalesTotalProductCost0_8]
,[dbo_FactResellerSales].[dbo_FactResellerSalesProductStandardCost0_9] AS [dbo_FactResellerSalesProductStandardCost0_9]
,[dbo_FactResellerSales].[dbo_FactResellerSales0_10] AS [dbo_FactResellerSales0_10]
,[dbo_FactResellerSales].[dbo_FactResellerSalesEmployeeKey0_11] AS [dbo_FactResellerSalesEmployeeKey0_11]
,[dbo_FactResellerSales].[dbo_FactResellerSalesPromotionKey0_12] AS [dbo_FactResellerSalesPromotionKey0_12]
,[dbo_FactResellerSales].[dbo_FactResellerSalesSalesTerritoryKey0_13] AS [dbo_FactResellerSalesSalesTerritoryKey0_13]
,[dbo_FactResellerSales].[dbo_FactResellerSalesResellerKey0_14] AS [dbo_FactResellerSalesResellerKey0_14]
,[dbo_FactResellerSales].[dbo_FactResellerSalesProductKey0_15] AS [dbo_FactResellerSalesProductKey0_15]
,[dbo_FactResellerSales].[dbo_FactResellerSalesCurrencyKey0_16] AS [dbo_FactResellerSalesCurrencyKey0_16]
,[dbo_FactResellerSales].[dbo_FactResellerSalesOrderDateKey0_17] AS [dbo_FactResellerSalesOrderDateKey0_17]
,[dbo_FactResellerSales].[dbo_FactResellerSalesShipDateKey0_18] AS [dbo_FactResellerSalesShipDateKey0_18]
,[dbo_FactResellerSales].[dbo_FactResellerSalesDueDateKey0_19] AS [dbo_FactResellerSalesDueDateKey0_19]
,[dbo_DimReseller_6].[GeographyKey] AS [dbo_DimResellerGeographyKey5_0] -- 1
,[dbo_DimReseller_22].[RefAKey] AS [dbo_DimResellerRefAKey7_0] -- 2
,[dbo_DimReseller_23].[RefBKey] AS [dbo_DimResellerRefBKey9_0] -- 3
,[dbo_DimReseller_24].[RefCKey] AS [dbo_DimResellerRefCKey11_0] -- 4
FROM (
SELECT [SalesAmount] AS [dbo_FactResellerSalesSalesAmount0_0]
,[OrderQuantity] AS [dbo_FactResellerSalesOrderQuantity0_1]
,[ExtendedAmount] AS [dbo_FactResellerSalesExtendedAmount0_2]
,[TaxAmt] AS [dbo_FactResellerSalesTaxAmt0_3]
,[Freight] AS [dbo_FactResellerSalesFreight0_4]
,[DiscountAmount] AS [dbo_FactResellerSalesDiscountAmount0_5]
,[UnitPrice] AS [dbo_FactResellerSalesUnitPrice0_6]
,[UnitPriceDiscountPct] AS [dbo_FactResellerSalesUnitPriceDiscountPct0_7]
,[TotalProductCost] AS [dbo_FactResellerSalesTotalProductCost0_8]
,[ProductStandardCost] AS [dbo_FactResellerSalesProductStandardCost0_9]
,1 AS [dbo_FactResellerSales0_10]
,[EmployeeKey] AS [dbo_FactResellerSalesEmployeeKey0_11]
,[PromotionKey] AS [dbo_FactResellerSalesPromotionKey0_12]
,[SalesTerritoryKey] AS [dbo_FactResellerSalesSalesTerritoryKey0_13]
,[ResellerKey] AS [dbo_FactResellerSalesResellerKey0_14]
,[ProductKey] AS [dbo_FactResellerSalesProductKey0_15]
,[CurrencyKey] AS [dbo_FactResellerSalesCurrencyKey0_16]
,[OrderDateKey] AS [dbo_FactResellerSalesOrderDateKey0_17]
,[ShipDateKey] AS [dbo_FactResellerSalesShipDateKey0_18]
,[DueDateKey] AS [dbo_FactResellerSalesDueDateKey0_19]
FROM (
SELECT [dbo].[FactResellerSales].[ProductKey]
,[dbo].[FactResellerSales].[OrderDateKey]
,[dbo].[FactResellerSales].[DueDateKey]
,[dbo].[FactResellerSales].[ShipDateKey]
,[dbo].[FactResellerSales].[ResellerKey]
,[dbo].[FactResellerSales].[EmployeeKey]
,[dbo].[FactResellerSales].[PromotionKey]
,[dbo].[FactResellerSales].[CurrencyKey]
,[dbo].[FactResellerSales].[SalesTerritoryKey]
,[dbo].[FactResellerSales].[SalesOrderNumber]
,[dbo].[FactResellerSales].[SalesOrderLineNumber]
,[dbo].[FactResellerSales].[RevisionNumber]
,[dbo].[FactResellerSales].[OrderQuantity]
,[dbo].[FactResellerSales].[UnitPrice]
,[dbo].[FactResellerSales].[ExtendedAmount]
,[dbo].[FactResellerSales].[UnitPriceDiscountPct]
,[dbo].[FactResellerSales].[DiscountAmount]
,[dbo].[FactResellerSales].[ProductStandardCost]
,[dbo].[FactResellerSales].[TotalProductCost]
,[dbo].[FactResellerSales].[SalesAmount]
,[dbo].[FactResellerSales].[TaxAmt]
,[dbo].[FactResellerSales].[Freight]
,[dbo].[FactResellerSales].[CarrierTrackingNumber]
,[dbo].[FactResellerSales].[CustomerPONumber]
FROM [dbo].[FactResellerSales]
WHERE OrderDateKey >= '20080101'
AND OrderDateKey <= '20081231'
) AS [FactResellerSales]
) AS [dbo_FactResellerSales]
/*** One JOIN per Referenced Relationship ***/
,[dbo].[DimReseller] AS [dbo_DimReseller_6] -- 1
,[dbo].[DimReseller] AS [dbo_DimReseller_22] -- 2
,[dbo].[DimReseller] AS [dbo_DimReseller_23] -- 3
,[dbo].[DimReseller] AS [dbo_DimReseller_24] -- 4
WHERE (
([dbo_FactResellerSales].[dbo_FactResellerSalesResellerKey0_14] = [dbo_DimReseller_6].[ResellerKey]) -- 1
AND ([dbo_FactResellerSales].[dbo_FactResellerSalesResellerKey0_14] = [dbo_DimReseller_22].[ResellerKey]) -- 2
AND ([dbo_FactResellerSales].[dbo_FactResellerSalesResellerKey0_14] = [dbo_DimReseller_23].[ResellerKey]) -- 3
AND ([dbo_FactResellerSales].[dbo_FactResellerSalesResellerKey0_14] = [dbo_DimReseller_24].[ResellerKey]) -- 4
As you can see in the comments, the generated query contains 1 join on the referenced table
per referenced relationship. This can slow down the processing if both the Fact table and the Referenced Dimension table are big (and they usually are, otherwise the design would be different). The thing is, all 4 tables are filtered in the
WHERE clause on the same condition, which makes perfect sense. This leads to the conclusion that all 4 columns could have been read from a single join.
I was quite surprised by this kind of query generation and I can't seem to find a reason why this would be so, or how it could be avoided. Naturally, the RefAKey, RefBKey, RefCKey columns could be added to the Fact table, eliminating the need for referenced
relationships, but this would add 3*4 bytes per row to the Fact table. The Fact table in my real example contains around 3 billion rows, so adding extra bytes is painful. (Yes, it's partitioned but still ... )
The referenced relationships could also be "dematerialized" by removing the famous Materialize check in the relationship settings. Then again, this would issue a join to the referenced tables at query time, slowing down the query.
Has anyone been profiling processing queries like this one and stopped to think about it?

I don't believe it's on the Essbase side, as it uses a fairly standard API to allow string input to such things, and it's limitation is well beyond 512 chars even for a direct formula input. I instead suspect that a carriage return/line feed is being inserted by the ODBC driver as part of it's output formatting, and this is causing the API to consider the input record "completed." I could be wrong, of course, but if you examine the Memo field closely, you may find the formatting to have migrated to the Access database, and even if not, you are still using ODBC to access it on the output side, so we're back to the same issue. Perhaps it really is an issue related to the ODBC drivers in Essbase, but it's not unique to dim build, to formulas, or Essbase for that matter. Allowing a single field to output more than 512 chars in a single field is where I believe you will find the real issue. Again, we need an ODBC expert to weigh in on this. <img src="i/expressions/face-icon-small-smile.gif" border="0">

One to many relationships

Hi I have a big problem :)
I want to use one to many relationships.
One yable with primary key, foreign key view_id. The second table on the many side with primary key view_id and another primary key.
The problem is that ejbc gives the followin error:
" [java] In relationship 'ViewType-SView', role 'ViewType-Has-SView', a weblogic-relationship-role element contains the wrong number of column mappings. A single column mapping must be given for each primary key column in the bean referenced by the mapping."
And that makes no sense for me. Any ideas?

weblogic-relationship-role element column mappings should be the same as defined in
<ejb-relationship-role>
<multiplicity></multiplicity>
</ejb-relationship-role>
Erno wrote:
Hi I have a big problem :)
I want to use one to many relationships.
One yable with primary key, foreign key view_id. The second table on the many side with primary key view_id and another primary key.
The problem is that ejbc gives the followin error:
" [java] In relationship 'ViewType-SView', role 'ViewType-Has-SView', a weblogic-relationship-role element contains the wrong number of column mappings. A single column mapping must be given for each primary key column in the bean referenced by the mapping."
And that makes no sense for me. Any ideas?

Group by reports

Hi
I am using Oracle Reoprts 6i. I have a report where I need to
group by using a single parent, multiple child relationship. For
example, taking Employee number as the single parent and
employee’s children’s names and the projects in which he has
worked as the child records of employee number. I am not able to
achieve this tree structure. i am trying to use a Group left
report format. Can u pls help.
Thanks in advance.
Prabhu S

hi all,
my problem is solved now...heres what i was suggested by monica
from oracle corp..tx monica.. i hope this mite be useful for
others too.
cheers,
prabhu.
Hello,
Lets say you have three tables -
Parent - ( A primary key)
Child1 - ( B foreign key references Parent(A))
Child2 - ( C foreign key references Parent(A))
and B and C are not related.
Create three queries in the data model -
Q_1 - Parent which will create group G_Parent
Q_2 - Child1 which will create group G_Child1
Q_3 - Child2 which will create group G_Child2
Create two data links -
One from G_Parent(A) to G_child1(B)
Other from G_Parent(A) to G_child2(C)
In the layout -
Select type as Group Left.
Select the groups G_A,G_B,G_C to display down.
Select the fields to display.
Select template and run report.
This will give you the desired result.
Regards,
Monica Samuel

Programmatically Controlling tab disclosure

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How to achieve this?
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Ajay

Changing country and you get locked out of your iTunes account?

Hi All,
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(its a case of I'm ****** if I do and ****** if I dont)
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Dom
OSX 10.6.8.
Itunes - latest version
app stiore - latest version
<Edited by Host>

Just to let you know that I DIDNT swear in the last post. It was bleeped for using non offensive language. Just letting you know. (And @moderator this subnote isnt "off topic", its just letting colleagues know I'm not in the habit of swearing - something that the search and replace word-bot actaully makes it look worse than it is!!)
Many thanks - please dont delet this footnote (again)
Dom

Map translation and ECXpert Performance

Hi All,
We have noticed translation of large document adversely affecting the performance of ECXpert and it is very resource hungry.
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Version 3.6.2 provided the ability to use memory for workfiles; previous versions had the flag in the ini file, but because of a bug, did not set the option correctly. This has made as much as a 2x difference in translation speed...
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MS Access equivalent for Mac

Hi there,
Does anyone know if there is a decent MS Access equivalent for Mac ... and please do not say FileMaker as it has a different interface and table management logic that I do not really understand (Is it good enough to make it worth trying to learn?)
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Cheers

Hi,
start from here:
http://guide.apple.com/
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How can I upload multiple files in a master detail relationship?

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Elizabeth,
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I can put an example on apex.oracle.com if that would be helpful.
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Assign multiple relationships at once

Hi everyone...I am working in Primavera P6 Project Management Release: 7.0 Service Pack 3 (Build #: 00033036)
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I am able to log into a co-workers machine with my credentials and perform this task, but not on my machine. Do you have any suggestions?
Thanks

Hello,
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Edit Project Activity
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Create, edit, and delete a project’s activity
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Create and edit a project’s activity information, except
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Display of relationships between nodes of multiple trees

Hello,
I am trying to develop a gui to display the relationship between multiple trees.
Tree1:------|---------------Tree2:----------------|--------Tree3:
------------|-------------------------------------|--------------
Root -------|----------------Root-----------------|--------Root
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---Leaf2----|-----------------------Leaf11--------|-----------LeafB
---Leaf3----|-----------------------Leaf12--------|-----------LeafC
---Leaf4----|--------------------Node2
------------|-----------------------Leaf21
------------|-----------------------Leaf22
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preview takes away the blanks. The | characters are intended to act as separators
between adjacent trees.)
All the trees are scrollable and have been added to three different scrollpanes
and are displayed on a window. The relationships can only be between leaves
of the trees.
The only way I can figure out to show such relationships is by drawing lines
e.g. a line from Tree1.Leaf1 to Tree2.Leaf21 etc. Users may define relationships
by drawing lines from one tree node to another by dragging the mouse.
The lines may criss cross and there might be a lot of lines etc.
I would like to know about alternative ways to show such relationships on the
screen in a neater way.
I would also like a way to make lines "full fledged objects" e.g. they will get mouse
events such that actions can be triggered by double clicking or right clicking on a
line.
I would appreciate your help in this very much.
Best Regards,
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However, the JGraph framework is available only on Jsdk 1.4 and not on Jsdk 1.3.
I saw an item in the FAQ about the possibility of porting JGraph to 1.3 but there were
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Multiple relationships between 2 tables in report model

if i have 2 relationships between the same two tables. how do i use one over the other?
for example, i have 2 tables order and ordeDate table , with the definition of:
order table:
orderid int,
qty int,
orderdate date)
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(id int,
endOfDay date,
endOfMonth date)
i created one relation ship as orderDate = endOfDay and anothe relationship as orderDate = endOfMonth. some of my reports would need to use the relationship between orderDate = endOfDay and the month end reports would need to use yhe relationship between
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Ideally the database should have been redesigned, which cannot be done at the moment as this will be done on the next project

Your table design is completly wrong. I am now sure how you are maintaining OrderDate table. SQL Server is RDBMS. Without relation how will you pick those rows from Order table whose order date is equal exactly equal to datefield in OrderDate table. The
only way is to derived endofDay and endofMonth in the select query directly. I understand endofMonth. But what is EndofDay ? And that too a date datatype ??
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SELECT * FROM [ORDER] WHERE
CONVERT(CHAR(10),ORDERDATE,101) IN (SELECT CONVERT(CHAR(10),endOfDay,101) FROM ORDERDATE)
SELECT * FROM [ORDER] WHERE
CONVERT(CHAR(10),ORDERDATE,101) IN (SELECT CONVERT(CHAR(10),endOfMonth,101) FROM ORDERDATE)
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Cisco ISE - multiple AD - trust relationships

Hello,
I have a customer who has multple AD forests and an ISE deployment running 1.1.3.
The customer scenario is as follows - there is an Internal AD forest (internal users) and an External AD forest (external users such as consultants). The objective is to use Cisco ISE to authenticate and authorize the users in both AD forests. CIsco ISE is connected to the Internal AD forest.
We know that multiple AD support is coming in 2014 with versioon 1.3 - other options such as LDAP/EAP-TLS are not a viable option for the customer.
1.       Currently – the Internal AD forest has an External, Non-transitive – one-way trust with the External Forest
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     b.      Preliminary testing has shown that a one way trust seems to work for Cisco ISE authentication/authorization
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Question : has any one used this and is this a supported method by Cisco (I know they mention a mutual trust relationship is required)?
2.       We are exploring a second scenario - the Internal AD forest will have an External, Non-transitive – two-way trust with the External Forest
     a.       Same objectives as in 1 – we would attempt to use the Selective Authentication in the following fashion (this is an example)
          i.      External Forest has outgoing filter to allow access to specific resources in Internal Forest, and for authentication
          ii.      Internal Forest has incoming filter to deny access to all resources in External Forest
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Thanks in advance for your replies.
Robert C.

Cisco has published a nice new guide on Active Directory integration with ISE 1.3. As noted there:
"Cisco ISE can connect with multiple Active Directory domains that do not have a two-way trust or have zero trust between them. Active Directory multi-domain join comprises a set of distinct Active Directory domains with their own groups, attributes, and authorization policies for each join."
I've setup one such deployment just recently and found it quite simple to just add the second domain and use it an en external identity source accordingly.

Multiple NSNotification, Changed only one object. In Notification getting notification of relationships.

Hi,
I have Entities like 'Alert' which has relationship to 'Company' and 'Company' has relationship to 'User'.
When i am saving something in Alert. In my observer of NsNotificationCenter, i am getting notification for 'Company', 'User (multipler users)' and Alert.
I am not able to figure out why i am getting Notifications of 'Company' and 'User'.
For example : I have Company name - XYZ and it has 7 Users - 'A to G' and i created Alert on 'A' then after changing in Alert. i am getting notification of 7 users, 1 Company and 1 Alert.
I dont know why i am getting Notification of Users and Company.
My Objects Hierarchy is :
Alert has relationship to Company.
User has relationships to Company.
Please help..
Thanks,
Amit

Amit,
First you should move this question to the webobjects mailing list:
WebObjects Development <[email protected]>
https://lists.apple.com/mailman/options/webobjects-dev/
So each users can have many companies? Each Company has one Alert? I don't understand the relationship(s)..
Alert => Company
User <=>> Company
it's not really clear what you want. (at least not to me).

Multiple relationship modeling

Hello,
I am hitting a bug/issues/misunderstanding on my side with data modeller 4.0.0.833 (I had this issue in the previous versions too).
I was trying to model multiple relationships from a entity to a detail entity and am hitting some problems. I have the following situation (simplified) :
Party Entity : Party ID (PID), Party Name
Transaction Entity : Trans ID (PID), cost (number)
I then create 2 1-to-many relationship from party to transaction:
Party -> Transaction (1 to many)
Party -> Transaction (1 to many)
This creates 2 FKs on the transaction entity called (Party ID and Party ID1). I rename this attributes in the transaction entity as "From Party" and "To Party"
I then do a engineer to relational model.
This then ignores the attribute names in the transaction entity I had given ("From party" and "to party") and creates 2 new columns - "Party_Party_ID" and "Party_Party_ID1".
Is there a way I can preserve the names I had given in the logical model for the FKs when engineered to Physical? Or is this a bug?
Secondly, Is it possible in the Relation properties dialog box (by double clicking the relationship lines in the logical model) in the target cardinality section to select the FKs I had created ("From Party" and "to Party") so that I could document correctly which is the "from" and which is the "to".
Thanks in advance.
AK

Hi AK,
you have 2 options:
1) clear "Apply name translation" check box in engineering dialog
2) use proper setting for naming template and names in your model (as Dimitar suggested) - naming templates are available in design properties dialog>"Settings>Naming standards">templates"
2.1 change naming template for "Column Foreign key" to {relationship}
2.2 Rename your relationships as "From Party" and "To Party"
3.1 Check "Apply name translation" check box in engineering dialog
Philip

Multiple BP relationships

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