Name of the file in a directory

There is a file in a directory say C:\abcd
I want to find the name of the file in that directory.
There is only one file in that directory
How to proceed with this

Sarma,
That was a little abrupt and rude of you. Oracle_Friend was only asking if anyone knew of a way to detect the existence of a file in a directory, not exactly asking the world of us. And for all you know he probably has already searched in documentation, but probably isn't quite sure what to look for.
Remember : The manual has every damn thing that you want. We can only help you when you are stuck somewhere after having treid many options.a) sometimes people don't know what options to try so how can they have tried many options before posting on here.
b) The manual doesn't have every damn thing that you want. I want a lot of money and some lunch cos I'm getting hungry, but it doesn't have that. On a serious note though, the manuals do miss things and can't possibly cater for everybody's business requirements.
Chill out man, and help rather than hinder.

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Is there a simple way to get all names of the files in a directory and put them in an array of Strings? Sounds simple, but I don't have a clue how to do this. Thanks.

Hi Kindoo,
Create a instance of File object using the path of the Directory
File fileDir = new File(directoryPath);
To get the List of all the files in the directory use
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Hi
I am trying to copy a file uploaded by the user to a new directory. the dir structure is
/data/temp/username/. The username dir is created at the time of upload. so if any user with the username say "bob" logs in, a directory bob is created under /data/temp.
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Hi there
Thanx for you reply.
I read the snippet, but it says about Windows, I am working on Linux. Wont that make a diference when i getAbsoluetpath.. Coz the print statement shows me the path as /data/temp/username
Also i ran a prototype of the code on windows and it seems to work fine ... like it creates a user directory under C:/Java/temp and then stores the file under the new created user directory.
If the code would help to think in a better way heres it:
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hi zymus,
check this code u will get the solution for ur problem..
import java.io.*;
public class files {
public static void main(String[] args) {
File f = new File("c://");// specify ur directory name here
String[] n = f.list();
System.out.println("ALL FILES.....");
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                              if (n2 != null)
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for (int i = 0; i < n2.length; i++)
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class myJavaFileFilter implements FilenameFilter
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Getting names of all files in a directory.

import java.io.*;
import java.util.*;
public class dir{
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That is the code that I am using, what I am trying to do with it is read all the files in a directory. So I can open them and calculate all the data in all of the files at the same time.
These are the file names that are in the directory when I run the program.
L0519013.log
L0331001.log
I have the code out put the file names in a file called dir.txt
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[Ljava.io.File;@70ccc4b2
[Ljava.io.File;@70ccc4b2
[Ljava.io.File;@70ccc4b2
Any clue waht this means?
also I am passing in the director as args[0]

if possible as well...
I could not get the FileFilter to work, could not get the syntax down to get it to work when I was initializing it so for the moment it is remed out. all files in the given directory will be of type .log so there really is no need for the FileFilter. But any help on how to include that in the code would be greatly helpful.
Thankxs
Korbin

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Message Edited by JoeLabView on 04-18-2007 03:43 PM
Attachments:
copy folder contents.PNG ‏10 KB

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http://abaplovers.blogspot.com/2008/05/function-module-sap-logged-in-users-to.html
http://www.saptechies.com/abap-function-modules/
http://sap.ittoolbox.com/groups/technical-functional/sap-dev/function-module-to-get-data-and-time-of-file-576751
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Name of the file in a directory

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