Need help interpreting an RFC Web dynpro exception

Hi,
The following code shows how I set the content of a wdp model:
Z_Zmm_Tax_Calc2_Input TaxCode2 = new Z_Zmm_Tax_Calc2_Input();
wdContext.nodeZ_ZMM_TAX_CALC2().bind(TaxCode2);
TaxCode2.addItems(new Zzz_Tax_Calc());
It's the last line of the code that causes the exception
When executing the model I get the following.
Error stacktrace:
java.lang.ClassCastException: com.sap.tc.webdynpro.modelimpl.dynamicrfc.WDDynamicRFCException: The Relation must reference ModelClass instances of Type , not of !
     at com.sap.tc.webdynpro.modelimpl.dynamicrfc.DynamicRFCModelClass.checkRelatedModelObject(DynamicRFCModelClass.java:727)
     at com.sap.tc.webdynpro.modelimpl.dynamicrfc.DynamicRFCModelClass.addRelatedModelObject(DynamicRFCModelClass.java:802)
     at com.alum.miromodel.Z_Zmm_Tax_Calc2_Input.addItems(Z_Zmm_Tax_Calc2_Input.java:170)
     at com.alum.miro.Cust.initTaxCalc2(Cust.java:911)
Can anyone tell me what it means?
BR
Olof Tronnberg

Hi Olof,
Z_Zmm_Tax_Calc2_Input TaxCode2 = new Z_Zmm_Tax_Calc2_Input();
wdContext.nodeZ_ZMM_TAX_CALC2().bind(TaxCode2);
These two lines of code will first create a object of the model node and bind it to the present view s context node.
I thnk this node Z_Zmm_Tax_Calc2_Input() has structures in it. When ur rfc needs inputs we hav to set them as
say
TaxCode2.set<some attribute in the model node>(its value);
If there is a structure
TaxCode2.set<structure name>(new <structure name>);
This is the correct way.
When u say TaxCode2.addItem(); the argument needed is of type Item . IS zzz_tax_calc of that type..
If its not of the type it will throw the classcast exception
AddItem is usually used when we have to add more than instance.
Bind creates one instance of the node and binds it.
I think its a gud practice to stick with bind and set rather than add when it comes to RFC s
Regards
Bharathwaj

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Your router has two IP addresses (that's what makes it a router): a WAN address and a LAN address. The WAN address is the address assigned by the ISP. It is a normal internet IP address. Everyone is able to send packets to this IP address. The WAN address is the one reported by whatismyipaddress.com, it should be listed in the dyndns record and it is the address that your router shows on the Status page. It's the public IP address of your router. Dyndns maps your dyndns.org name to that IP address.
Your router also has an IP address on the LAN side. You can configure it to be whatever you want. The default is 192.168.1.1 with netmask 255.255.255.0 and it is better to leave it like that or at least inside the network 192.168.*.*. 192.168 is a special, reserved IP address range for private networks. Basically, routers in the internet are not supposed to forward addresses in this range. That makes them suitable for private LANs as the packets never can get anywhere. Most people using Linksys routers have there LAN in 192.168.1.*.
The router acts as gateway, which means it forwards packets from PCs in the LAN to the internet and back. As all your PCs in your LAN share a single WAN IP address, the gateway does address translation (NAT). This works only in one direction: from the inside to the outside. The router remembers when a PC in your LAN sends something out and accepts the responses in and sending them back to the PC. If something comes in from the internet which cannot be associated with a ongoing communication the packet is dropped unless you use port forwarding.
All computers in your LAN either have a static IP address assigned or use DHCP to get it automatically. The router has a DHCP server as well which gives out IP address from 192.168.1.100-149 if not changed. With a router with default settings static IP addresses can be in the range of 192.168.1.2-99 and 150-254.
ipconfig /all reports your IP address in your LAN, i.e. an address 192.168.1.*. The gateway in this output should be 192.168.1.1 which is your router. And packet no in the LAN address range 192.168.1.* is send to the router which forwards the packets into the internet.
An address 192.168.1.* should not appear as internet address in the Status page of the router nor should it appear at dyndns.
Port forwarding is used to operate a server in the LAN. By default, a server in the LAN cannot be reached from the internet. You have to configure port forwarding for this. You configure that traffic bound for a specific port (e.g. TCP port 80 for http) on your WAN IP address is forwarded to the same port on a specific LAN IP address. If your server runs on 192.168.1.50 than traffic to your WAN IP address port 80 is forwarded to 192.168.1.50 port 80. That way your HTTP server can be reached from the internet. As you can only configure a fixed IP address in port forwarding it is recommended that the server uses a static IP address and not DHCP as in the latter case the IP address may change over time...
O.K. so much for networking. I hope that makes things a little clearer and you can verify that your setup is how it is intended to be.
I suggest the following: on the router's security page there is an option to block WAN requests. Remove the check if it is set (meaning: do not block). After you did that change you should be able to ping your WAN address (e.g. ping xxxx.dyndns.org) from the internet. That way we know that it is on the correct address.
Also on the Administration page make sure that remote management is disabled (should be like that per default) or that the management port is NOT 80 but for example 8080. What is your your UPnP settings on the same page?
O.K. that should be enough for the moment...

I need help sorting out how Web services work

I'm getting pretty darn confused with all the new terms I have to learn to develop a web service.
I want to deploy a simple java based web service on an IIS/ServletExec machine. To do so the documentation says I have to instal WSDP on the machine. Within a few seconds I get stuck.
When I try to install wsdp 1.6 it asks for a web container. I thought ServletExec is a web container, but it does not recognize it. What is a web container then? Should I just pick one of their options?
Sun Java System Application Server Platform Edition 8.1 Update 2 : What is this thingy? Doe it coem sith j2ee sdk already? If not, why?
Sun Java System Web Server 6.1 Service Pack 3 : What is this> How does it differ from the former thingy?
Tomcat 5.0 for Java WSDP 1.5 : Is this the Tomcat web app server? Does it stack on ServletExec?
I've deployed web pages on ServletExec, but am quite bewildered by the hoard of terms and tools thrown at me by the documentation for web services. What do I really need? It doesn't seem it should require much more than a jsp page would require, but I keep seeing the list of jar files and the like grow.
I need a web services for dummies that specifically deals with ServletExec and Java.
- Extremely confused

A Web container is a part of application server
i.e a web container is contained in application server.
So ServletExec already has a Web Container? All Web App Servers have a web container?
A Web Server is responsible only for web related
applications like JSP, Servlets, Web services, etc.
but an appliocation server can deploy EJB's also.
I thought the Web Server managed html and passed JSPs, Servlets, and Web Services on to the Web App Server. (With the exception of .NET type applications which run entirely on the front end Web Server). At least that is how we have our machine configured.
IIS, the Web Server, runs on a machine outside the firewall. It serves up all static html pages. All references to dynamic html (JSPs and Servlets) are forwarded to a Servlet Exec instance, the Web App Server, on a machine behind the firewall.
IIS can not process Web Services outside a .NET-type configuration. The documentation has led me to believe that I have to deploy a Java web service on a Web App Server like ServletExec.
>
Sun Java System Application Server Platform Edition 8.1 Update 2
is an application server provided by sun.
But the installation called it a web container. You just called it an applciation server. But you also said earlier that an applciation server is not a web container, but rather contains a web container. Should they have called it an applciation server.
(Just to make sure - application server = web app server, right?)
You can download bundle which contains j2eesdk
and application server together or you can download
seperately. Both these options are available on Sun's website.
I do believe ServletExec comes with j2eesdk, as I was able to run servlets without installing it. Though I did install jdk 1.5 and use it as my virtual machine when running Java, including any servlets.
Sun Java System Web Server 6.1 is responsible only
for web related applications like JSP, Servlets, Web services
etc but Sun application server 8.2 can deploy EJB's also.
So Web Server 6.1 is a front end web server which also serves up JSPs without having to call an application server? You only need an application server if you want to do EJBs?
Tomcat 5.0 for Java WSDP 1.5 : Is this the Tomcat web app server?WSDP containts several library files and other files
which are necessary for running a web service.
( lib files for sending and recieving SOAP request and
response i.e mail.jar activation.jar, saaj .jar ....etc).
It is not an application server. It acts as a supportive
role for creating and deploying web services.
That's what I thought. But I also thought Tomcat 5.0 IS a web app server (wheras Apache is the Web Server). It says "Tomcat 5.0 for Java WSDP 1.5" which does not make sense to me. Iwould think it would say "Java WSDP 1.5 for Tomcat 5.0" instead. What exaclty are they offering to download? WSDP or Tomcat? And if Tomcat, why are they calling it a web container when it is an application server? WSDP is not a web container, right? just some lib files for supporting web services.
Regards,
Piyush- still quite confused but grateful for your comments

Need help interpreting an Apache error message

I hope my Apache/Tomcat questions of late aren't off topic - I am trying to get them to work together so that Tomcat will handle Java servlet.
I'm one of collection of newbies trying to troubleshoot the fact that we can't do anything with servlets even though everything seems to be set up OK. I need to verify that my interpretation of an Apache error message is correct (or not).
Anyway, whenever someone types in the URL of a servlet in the form http:/myURL/mydomainname.com/servlet/HelloWorld (where URL is in the form ##.#.###.###, since the domain name officially "assigned" to the URL yet) The browser displays an error message saying that /myURL/mydomainname.com/servlet/HelloWorld was not found on the server.
Upon looking at the Apache error log, the following statement is found::
[Sat Jul 23 17:54:10 2005] [error] [client XX.X.XXX.XXX] File does not exist: /home/virtual/site1/fst/var/www/html/servlet
(this is a virtual site; all that extra /virtual/site1/fst/ is supposed to be in there.
Note the fact that the error message stops at the word "servlet" and does not say "/servlet/HelloWorld". That makes me think that Apache does not realize that "/servlet" means "send what comes next over to Tomcat" and instead thinks that the browser is trying to get into a DIRECTORY called "/servlet" which does not exist.
Am I correct in this? Does that error message imply that is what is going wrong?

Your note is making me think that you've got the
Apache Web server running on Linux, and you've tried
to make Tomcat the servlet/JSP engine that Apache
forwards all servlet/JSP requests to. Apache is
listening on port 80, of course. All correct?All correct.
I'm not sure that you've got Tomcat bolted onto
Apache properly, Probably not. My question is, basically, is that what the aforementioned error message is implying??
or if you've deployed your servlet
correctly. Again - does the aforementioned error message indicate that Apache simply isn't calling Tomcat in the first place, in which case nothing is even looking for the servlet? Yes or no? I've experimented and found that Apache error messages always stop at the first thing that they don't recognize. For example, if someone types in http://URL/domainame/totally/bogus/vaporware, the Apache error message will say: "File does not exist: /home/virtual/site1/fst/var/www/html/totally" because the directory "/totally/" is the first thing it comes accross that does not exist. I'm trying to verify that possibility so that I know better where to look for the error. Or is it possible that Apache DOES recognize what /servlet/ means, is succesfully getting to Tomcat, but something else is going wrong that causes Apache to sned that error message?
Also, there is no sign of activity in Tomcat's Catalina.out log file since the day
I last turned Tomcat on (successfully). Since that's the only thing in Tomcat's log folder, I assumed it was where Tocmat's error messages would show up (if not, where are they? Havn't been able to find anything else). If that is the case, Tomcat has indeed not been contacvted by Apache.

Need help interpreting an RFC Web dynpro exception

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