Need help on xslt transformation

Question

Hi ,
I am working on a xslt transformation and  I am finding it difficult to implement the transformation. The scenario is as below.
Input format :-
A
B
B
B
4
5
A
B
B
A
B
B
B
Output format :-
A
B
B
B (since after A there were 3 B’s before the next A)
A
B
B(since after A there were two B’s before the next A)
A
B
B
B
I don't need type 4,5 records in the output xml,output should have repetition of (A followed by B’s(till the next occurrences of A)).
if some one encountered a similar transformation kindly let me know.

Answer 1

Hi,
You can use "Call" and "Apply" template.
1st thing to do:
e.g.
<xsl:template name="Check_Decimal">
    <xsl:param name="Xpath"/>
    <xsl:choose>
      <xsl:when test="($Xpath) and ($Xpath)!='4'">
        <xsl:value-of select="$Xpath"/>
      </xsl:when>
      <xsl:otherwise>
        <xsl:value-of select="' ' '"/>
      </xsl:otherwise>
    </xsl:choose>
  </xsl:template>
            <xml_Target_Element_1>
              <xsl:call-template name="Check_Decimal">
                <xsl:with-param name="Xpath"
                                select="/x/y/z/xml_Target_Element_1"/>
              </xsl:call-template>
            </xml_Target_Element_1>
This means, it will display the value in xpath if value is not equal to 4. And if it is equal to 4, it displays nothing.
2nd thing to do:
Apply for-each to xpath till the String element reaches to "A".
Regards,
Richa