Need help with HR_INFOTYPE_LOG_GET_DETAIL, before/after tables

Greetings experts:
I've searched SDN for assistance with this question before posting but haven't been able to find anything to address my specific question which is, how do I "convert" the data that is in the before and after tables returned by this FM into the appropriate structure?
I tried concatenating all of the data in DATA1-DATA7 into a string and then using ASSIGN to CAST it into a structure of type P0167 (the particular record I was looking at in PCL4 was a change to this infotype). I noticed, however, in debug that the data just didn't look right, i.e., the DATA1 began with BAREA but there are many other fields ahead of this in P0167 so it's no wonder when this code executed I got garbage in my data object typed as P0167.
Any advice would be appreciated!

Hi Jamie
Just check that 'FIELD' table is optional/mandatory.
Also cross-check for 'type' of Exporting/tables parameters with the parameters that you are supplying
Regards
Ashish Jain

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what i have:
tableA:
puid, task
id0, task0
id1, task1
id2, task2
tableB:
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id0, 1, bar
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Edited by: user9979830 on Mar 29, 2011 10:53 AM
Edited by: user9979830 on Mar 29, 2011 10:58 AM

Hi,
Welcome to the forum!
user9979830 wrote:
what i have:...Thanks for posting that so clearly!
Whenever you have a question, it's even better if you post CREATE TABLE and INSERT statements for your sample data, like this:
CREATE TABLE     tablea
(       puid     VARCHAR2 (5)
,     task     VARCHAR2 (5)
INSERT INTO tablea (puid, task) VALUES ('id0', 'task0');
INSERT INTO tablea (puid, task) VALUES ('id1', 'task1');
INSERT INTO tablea (puid, task) VALUES ('id2', 'task2');
CREATE TABLE     tablec
(       puid     VARCHAR2 (5)
,     seq     NUMBER (3)
,     dt     DATE          -- DATE is not a good column name
INSERT INTO tablec (puid, seq, dt) VALUES ('id0', 0, DATE '2010-12-21');
INSERT INTO tablec (puid, seq, dt) VALUES ('id0', 1, DATE '2010-12-22');
INSERT INTO tablec (puid, seq, dt) VALUES ('id0', 2, DATE '2010-12-22');
INSERT INTO tablec (puid, seq, dt) VALUES ('id1', 0, DATE '2010-12-23');
INSERT INTO tablec (puid, seq, dt) VALUES ('id2', 0, DATE '2010-12-22');
INSERT INTO tablec (puid, seq, dt) VALUES ('id2', 1, DATE '2010-12-23');This way, people can re-create the problem and test their ideas.
It doesn't look like tableb plays any role in this problem, so I didn't post it.
Explain how you get the results from that data. For example, why do you want this row in the results:
PUID TASK DT1        DT2        DT3
id0   task0 12/21/2010 12/22/2010 12/22/2010rather than, say
PUID TASK DT1        DT2        DT3
id0   task0 12/22/2010 12/21/2010 12/22/2010? Does 12/21 have to go in the first column because it is the earliest date, or is it because 12/21 is related to the lowest seq value? Or do you even care about the order, just as long as all 3 dates are shown?
Always say what version of Oracle you're uisng. The query below will work in Oracle 9 (and up), but starting in Oracle 11, the SELECT ... PIVOT feature could help you.
i can get output like below through several joins, however i was hoping to condense each "id" into a single line... Condensing the output, so that there's only one line for each puid, sounds like a job for "GROUP BY puid":
WITH     got_r_num     AS
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     ,     dt
     ,     ROW_NUMBER () OVER ( PARTITION BY puid
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     FROM    tablec
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SELECT       a.puid
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,       MIN (CASE WHEN r.r_num = 4 THEN r.dt END)     AS dt4
FROM       tablea    a
JOIN       got_r_num r ON   a.puid = r.puid
GROUP BY a.puid
,            a.task
ORDER BY a.puid
;I'm guessing that you want the dates arranged by seq; that is, for each puid, the date related to the lowest seq comes first, regardless of whther that date is the earliest date for that puid or not. If that's not what you need, then change the analytic ORDER BY clause.
This does not assume that the seq values are always consecutive integers (0, 1, 2, ...) for each puid. You can skip, or even duplicate values. However, if the values are always consecutive integers, starting from 0, then you could simplify this. You won't need a sub-query at all; just use seq instead of r_num in the main query.
Here's the output I got from the query above:
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id0   task0 12/21/2010 12/22/2010 12/22/2010
id1   task1 12/23/2010
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If there are more than 4 dts for a puid, the query will still work. It will display the first 4, and ignore the others.
There's nothing special about the number 4; you could make it 3, or 5, or 35, but whatever number you choose, you have to hard-code that many columns into the query, and always get that many columns of output.
For various ways to deal with a variable number of pivoted coolumns, see the following thread:
PL/SQL
This question actually doesn't have anything to do with SQL*Plus; it's strictly a SQL question, and SQL questions are best posted on the "SQL and PL/SQL" forum:
PL/SQL
If you're not sure whether a question is more of a SQL question or a SQL*Plus question, then post it on the SQL forum. Many more people pay attention to that forum than to this one.

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Need help with HR_INFOTYPE_LOG_GET_DETAIL, before/after tables

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