Need to get result in vertical way

Question

Hi,
declare
string_to_parse varchar2(2000) := 'abcdefg,hiklmnopqrst';
l_count number;
l_value varchar2(2000);
begin
string_to_parse := string_to_parse||',';
l_count := length(string_to_parse) - length(replace(string_to_parse,',',''));
-- In oracle 11g use regexp_count to determine l_count
for i in 1 .. l_count loop
select regexp_substr(string_to_parse,'[^,]+',1,i) into l_value from dual;
dbms_output.put_line(l_value);
end loop;
end;
if i run this i get ans as
abcdefg
hiklmnopqrst
but i need the answer like
a
b
c
could any one help me to get like this

Answer 1

To add something to Lee's code
declare
     string_to_parse varchar2(2000) := 'abcdefg,hiklmnopqrst';
     l_count number;
     l_value varchar2(2000);
     i number := 1;
begin
     l_count := length(string_to_parse);
     l_value := substr(string_to_parse,1,instr(string_to_parse,',')-1);
     l_value := l_value || substr(string_to_parse,instr(string_to_parse,',')+1,l_count);
     l_count := length(l_value);
     while i <= l_count loop
          dbms_output.put_line(substr(l_value,i,1));
          i := i + 1;
     end loop;
end;
/I know I missed out the comments, if you want me to explain, I can do it.