Negating awk command

Question

I would like to find out how to negate my nawk command.
This pulls all files with <TITLE> in the file:
#!/bin/ksh
find . \( -name "*.htm" -o -name "*.html" \) -print |
xargs awk '/<TITLE>/ {printf("%s\t%s\n", FILENAME, $0)}'
OUTPUT:
./fir.html <TITLE> fir title </TITLE>
./tr.html <TITLE> third title </TITLE>
./four.html <TITLE> four title </TITLE>
I tried several ways to pull up files with no <TITLE> in the file:
#!/bin/ksh
find . \( -name "*.htm" -o -name "*.html" \) -print |
xargs awk '!/<TITLE>/ {printf("%s\t%s\n", FILENAME, $0)}'
and tried this with no luck:
#!/bin/ksh
find . \( -name "*.htm" -o -name "*.html" \) -print |
xargs awk '$2 !~ /<TITLE>/ {printf("%s\t%s\n", FILENAME, $0)}'
Both did not work.
Any suggestions???

Answer 1

Hi,
I tried your first script and it worked fine for me.
I noticed that these are script files rather than commands - is it possible you are executing something else in your path?
Can you provide a little more detail?
Thanks,
     -Steve