Number of days.
BKPF-BUDAT + [BSEG-ZBD1T u2013 day of today = days in arrears (invoice was due)
above logic how i will put in my sap script using subroutine.
BKPF-BUDAT + [BSEG-ZBD1T u2013 day of today = days in arrears .
EX: 20.04.2009 + 30 - 15.05.2005 = 24
How can i show above logic in my script using subroutines.
HI,
/: PERFORM <form> IN PROGRAM <prog>
/: USING &BKPF-BUDAT&
/: USING &BSEG-ZBD1T &
/: CHANGING &W_DATE&
/: ENDPERFORM
FORM <form> TABLES IN_TAB STRUCTURE ITCSY
OUT_TAB STRUCTURE ITCSY.
DATA :
BUDAT TYPE SY-DATUM,
ZBD1T TYPE SY-DATUM,
W_DATE TYPE I.
READ TABLE IN_PAR WITH KEY u2018BKPF-BUDATu2019.
CHECK SY-SUBRC = 0.
BUDAT = IN_PAR-VALUE.
READ TABLE IN_PAR WITH KEY u2018BSEG-ZBD1T' .
CHECK SY-SUBRC = 0.
ZBD1T = IN_PAR-VALUE.
w_date = BUDAT + ZBD1T - SY-DATUM.
READ TABLE IN_PAR WITH KEY u2018W_DATE' .
CHECK SY-SUBRC = 0.
MODIFY OUT_PAR INDEX SY-TABIX
ENDFORM.
For more help refer to this link..http://help.sap.com/saphelp_40b/helpdata/en/d1/803279454211d189710000e8322d00/content.htm
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How to get total number of days
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Pls Try to search before posting general questions.
Try this,
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EXCEPTIONS
days_method_not_defined = 1
OTHERS = 2
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Sunil kairam. -
FM to get the number of days in Year,month and days by giving number of day
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start date :01.01.2009
number of days as 32
then i should get
years:0
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days :1
Pleas help me out.hi Anusha,
first u pass the date and the days to the following fm you will get the result date....
data:date type sy-datum,
r_date(10) type c.
date = sy-datum.
CALL FUNCTION 'CALCULATE_DATE'
EXPORTING
DAYS = '32'
MONTHS = '0'
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then you need to pass the result date and the date to the following fm to get the required output...
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date2 = date
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years = v_years
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days = v_days
EXCEPTIONS
invalid_dates_specified = 1
OTHERS = 2.
IF sy-subrc <> 0.
MESSAGE ID sy-msgid TYPE sy-msgty NUMBER sy-msgno
WITH sy-msgv1 sy-msgv2 sy-msgv3 sy-msgv4.
ENDIF.
here u will get the difference in days, months and year...
i hope u wil get help from this...
regards
Ashu Singh -
How to get the number of days of a month belonging to a date interval
Hi, i am getting mad around a problem, i have 2 dates and a month, i wanto to retrieve the number of days belonging to the month that are in the interval.
eg:
month january 2011 . begin_date = 11/JAN/2011, END_DATE 30/MAY/2011 result is 21
month january 2011 . begin_date = 11/DEC/2010, END_DATE 10/JAN/2011 result 10
month january 2011 .begin_date = 02/FEB/2011 , END_DATE 25/may/2011 result 0
month january 2011. begin_date = 03/JAN/2011 , END DATE 05/JAN/2011 result 3
and so on ...
i appreciate any suggestion
thank you
AndreaOh, I didnt see your result.
SQL> with t as
2 (select to_date('11/01/11','dd/mm/yy') from_dt,
3 to_date('30/05/11','dd/mm/yy') to_dt,
4 'Jan-11' mnth from dual
5 union all
6 select to_date('11/12/10','dd/mm/yy') from_dt,
7 to_date('10/01/11','dd/mm/yy') to_dt,
8 'Jan-11' mnth from dual
9 union all
10 select to_date('02/02/11','dd/mm/yy') from_dt,
11 to_date('25/05/11','dd/mm/yy') to_dt,
12 'Jan-11' mnth from dual
13 union all
14 select to_date('03/01/11','dd/mm/yy') from_dt,
15 to_date('05/01/11','dd/mm/yy') to_dt,
16 'Jan-11' mnth from dual
17 )
18 select from_dt,to_dt,mnth,
19 greatest(
20 least(last_day(to_date(mnth,'Mon-yy')),to_dt)
21 -
22 greatest(to_date(mnth,'Mon-yy'),from_dt)+1
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24 from t;
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