Numbers range overlap

Range overlapping
the problem I'd like to solve :
given a table ranges (range_id#,external_key, from, to)
I need to detect overlapping grouping by external key, ie:
range_id external_key from to
------------------------+----
1 A 1 5
     2 A 8 10
     3          A 12 15
     4 A 3 9
     5 B 2 12
     6 B 13 24
     7 B 25 50
I need to detect the overlap in group A because the row #4 overlaps #1
The table contains 10 millions rows and I would like it to be fast, I think a good solution could be coding a aggregation function and use it as follows:
select external_key
from ranges r
group by external_key
having overlaps(from,to) = 1
I am in the process of coding function overlaps and I'll post it here , any ideas about the function overlaps? can you think about a different approach that would perform better?
thanks you for reading.
Miguel Corrales.

Good one Sergey.
To make the concept of read consistency even more clear:
SQL> select count(*),
2         to_char(min(dt1),'dd.mm.yyyy hh24:mi:ss.ff') as min_dt1,
3         to_char(max(dt1),'dd.mm.yyyy hh24:mi:ss.ff') as max_dt1,
4         to_char(min(dt2),'dd.mm.yyyy hh24:mi:ss.ff') as min_dt2,
5         to_char(max(dt2),'dd.mm.yyyy hh24:mi:ss.ff') as max_dt2,
6         to_char(min(dt3),'dd.mm.yyyy hh24:mi:ss.ff') as min_dt3,
7         to_char(max(dt3),'dd.mm.yyyy hh24:mi:ss.ff') as max_dt3,
8         to_char(min(dt4),'dd.mm.yyyy hh24:mi:ss.ff') as min_dt4,
9         to_char(max(dt4),'dd.mm.yyyy hh24:mi:ss.ff') as max_dt4
10   from (select systimestamp as dt1, systimestamp as dt2, systimestamp as dt3, systimestamp as dt4
11           from dual connect by level <= 1000000)
12 /
                              COUNT(*)
MIN_DT1
MAX_DT1
MIN_DT2
MAX_DT2
MIN_DT3
MAX_DT3
MIN_DT4
MAX_DT4
                               1000000
18.07.2008 11:24:49.029804
18.07.2008 11:24:49.029804
18.07.2008 11:24:49.029804
18.07.2008 11:24:49.029804
18.07.2008 11:24:49.029804
18.07.2008 11:24:49.029804
18.07.2008 11:24:49.029804
18.07.2008 11:24:49.029804
1 row selected.Regards,
Rob.

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HI Friends
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제품 : SQL*PLUS
작성날짜 : 2003-07-30
TIPS(46) : ROWNUM(ORDERING 순으로 NUMBERING, RANGE SELECT)
=========================================================
PURPOSE
Explanation
SQL*PLUS에서 ORDERING 순으로 NUMBERING하기를 원하는 경우가 많으나,
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ALLEN 1
JONES 2
BLAKE 3
CLARK 4
KING 5
ADAMS 6
JAMES 7
FORD 8
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CLARK 4
FORD 8
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JONES 2
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Example
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1) RECORD를 COUNT하는 방법 (DATA가 많은 경우 부적절)
SQL> select A.ename, count(*) position
2 from emp A, emp B
3 where A.ename > B.ename
4 or A.ename = B.ename and A.empno >= B.empno
5 group by A.empno, A.ename
6 order by A.ename, A.empno;
ENAME POSITION
ADAMS 1
ALLEN 2
BLAKE 3
CLARK 4
FORD 5
JAMES 6
JONES 7
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SQL> create index sort_ix on emp (ename);
Index created.
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ADAMS 1
ALLEN 2
BLAKE 3
CLARK 4
FORD 5
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JONES 7
KING 8
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select /*+ index_desc(emp ename_ix) */
ename, rownum from emp
where ename > ' ' and rownum < 4;
3) OPTIMIZER를 이용하는 방법
SQL> select rownum, ename
2 from emp , dual
3 where emp.ename = dual.dummy (+);
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1 ADAMS
2 ALLEN
3 BLAKE
4 CLARK
5 FORD
6 JAMES
7 JONES
8 KING
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rownum 1을 포함하는 range(예 : 'where rownum <= 100')에 대해서만
정상적인 조회가 가능하다.
만약 rownum 1을 포함하지 않는 range(예 : 'where rownum between 50 and 100')
에 대한 자료 조회를 원한다면 다음과 같이 in-line view를 이용하는 방법을
사용할 수 있다.
select rn, ename
from ( select rownum rn, ename
from emp)
where rn between 3 and 5 ;
RN ENAME
3 BLAKE
4 CLARK
5 KING
Execution Plan
0 SELECT STATEMENT Optimizer=CHOOSE
1 0 VIEW
2 1 COUNT
3 2 TABLE ACCESS (FULL) OF 'EMP'
* 이 때 in-line view의 rownum에는 반드시 alias를 이용해야 한다.
in-line view에 의해서 선택되어지는 data가 많다면 performance가
떨어질 수 있다.
Reference Documents
-------------------

제품 : SQL*PLUS
작성날짜 : 2003-07-30
TIPS(46) : ROWNUM(ORDERING 순으로 NUMBERING, RANGE SELECT)
=========================================================
PURPOSE
Explanation
SQL*PLUS에서 ORDERING 순으로 NUMBERING하기를 원하는 경우가 많으나,
ORDERING이 되기 전에 RANDOM ACCESS 시
ROWNUM이 ASSIGN되기 때문에, 다음과 같은 결과가 나타날 것이다.
SQL> select ename, rownum from emp;
ENAME ROWNUM
ALLEN 1
JONES 2
BLAKE 3
CLARK 4
KING 5
ADAMS 6
JAMES 7
FORD 8
SQL> select ename, rownum from emp order by ename;
ENAME ROWNUM
ADAMS 6
ALLEN 1
BLAKE 3
CLARK 4
FORD 8
JAMES 7
JONES 2
KING 5
Example
다음의 몇 가지 방법을 이용하여 ORDERING 순으로 NUMBERING을 나타내어 보자.
1) RECORD를 COUNT하는 방법 (DATA가 많은 경우 부적절)
SQL> select A.ename, count(*) position
2 from emp A, emp B
3 where A.ename > B.ename
4 or A.ename = B.ename and A.empno >= B.empno
5 group by A.empno, A.ename
6 order by A.ename, A.empno;
ENAME POSITION
ADAMS 1
ALLEN 2
BLAKE 3
CLARK 4
FORD 5
JAMES 6
JONES 7
KING 8
2) INDEX를 이용하는 방법
SQL> create index sort_ix on emp (ename);
Index created.
SQL> select ename, rownum from emp where ename > ' ';
ENAME ROWNUM
ADAMS 1
ALLEN 2
BLAKE 3
CLARK 4
FORD 5
JAMES 6
JONES 7
KING 8
cf) descending인 경우 아래처럼 hint 사용 바람
select /*+ index_desc(emp ename_ix) */
ename, rownum from emp
where ename > ' ' and rownum < 4;
3) OPTIMIZER를 이용하는 방법
SQL> select rownum, ename
2 from emp , dual
3 where emp.ename = dual.dummy (+);
ROWNUM ENAME
1 ADAMS
2 ALLEN
3 BLAKE
4 CLARK
5 FORD
6 JAMES
7 JONES
8 KING
위에서 언급한 내용에 더해서 rownum을 where 절에 사용함에 있어서는
rownum 1을 포함하는 range(예 : 'where rownum <= 100')에 대해서만
정상적인 조회가 가능하다.
만약 rownum 1을 포함하지 않는 range(예 : 'where rownum between 50 and 100')
에 대한 자료 조회를 원한다면 다음과 같이 in-line view를 이용하는 방법을
사용할 수 있다.
select rn, ename
from ( select rownum rn, ename
from emp)
where rn between 3 and 5 ;
RN ENAME
3 BLAKE
4 CLARK
5 KING
Execution Plan
0 SELECT STATEMENT Optimizer=CHOOSE
1 0 VIEW
2 1 COUNT
3 2 TABLE ACCESS (FULL) OF 'EMP'
* 이 때 in-line view의 rownum에는 반드시 alias를 이용해야 한다.
in-line view에 의해서 선택되어지는 data가 많다면 performance가
떨어질 수 있다.
Reference Documents
-------------------

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I have this problem it really so complex to solve for me
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hi ?Q>
Solved!
Go to Solution.

alexderjuengere wrote:
just for fun, here's a numeric approach. the u8 arrays are limited to 0 and 1.
Alex, I think the idea was a binary representation, not a decimal array of 1's or zeros:
CLA, LabVIEW Versions 2010-2013
Attachments:
checkbits.png ‏8 KB

Numbers range overlap

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