OATM : number of commands differs between runs

In testing OATM, first run generated 27000 commands.
Another test run generated many fewer commands.
Is this normal?
Are there something different to be done using OATM for 11gR2?
thx

Hi,
In testing OATM, first run generated 27000 commands.
Another test run generated many fewer commands.
Is this normal?Please elaborate more.
Are there something different to be done using OATM for 11gR2?There should be no difference across the different database versions.
Thanks,
Hussein

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Capture11.JPG ‏24 KB

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start:
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Last edited by progandy (2013-02-21 13:25:03)

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Why parition table is different between S10 3/05 and S10 6/06?

I want to set up RAID 1 (mirroring) using the Solaris Volume Manager (SVM) on my Solaris 10 6/06 x86 machine. I have 2 identical Seagate 40GB HDD's (model ST340016A).
The partition table on the primary disk was already defined by Solaris 10 3/05 OS before I reinstalled the OS (Solaris 10 6/06). The partition table of the primary disk is as follows:
leopard $ prtvtoc /dev/rdsk/c0d0s2
* /dev/rdsk/c0d0s2 partition map
* Dimensions:
* 512 bytes/sector
* 63 sectors/track
* 32 tracks/cylinder
* 2016 sectors/cylinder
* 38771 cylinders
* 38769 accessible cylinders
* Flags:
* 1: unmountable
* 10: read-only
* Unallocated space:
* First Sector Last
* Sector Count Sector
* 20984544 57173760 78158303
* First Sector Last
* Partition Tag Flags Sector Count Sector Mount Directory
0 2 00 6048 8390592 8396639 /
1 3 01 8396640 2098656 10495295
2 5 00 0 78158304 78158303
3 7 00 10495296 2098656 12593951 /var
4 0 00 12593952 4195296 16789247 /opt
5 8 00 16789248 4195296 20984543 /home
8 1 01 0 2016 2015
9 9 01 2016 4032 6047
It has 38771 cyclinders.
Now I want to create exactly the same partition table on the secondary disk, but it refuses to match the same partition table to the primary disk. It stills gives 40GB, but the number of cycliners is not the same. Below is the partition table of the secondary disk.
leopard $ prtvtoc /dev/rdsk/c0d1s2
* /dev/rdsk/c0d1s2 partition map
* Dimensions:
* 512 bytes/sector
* 63 sectors/track
* 255 tracks/cylinder
* 16065 sectors/cylinder
* 4864 cylinders
* 4862 accessible cylinders
* Flags:
* 1: unmountable
* 10: read-only
* Unallocated space:
* First Sector Last
* Sector Count Sector
* 48195 78059835 78108029
* First Sector Last
* Partition Tag Flags Sector Count Sector Mount Directory
2 5 01 0 78108030 78108029
8 1 01 0 16065 16064
9 9 00 16065 32130 48194
leopard $
It has 4864 cyclinders not 38771. Why?
You can see the disk dimension is different between these 2 disks. I tried to redefine it to match the primary disk, but it keeps coming back to the different table.
Do you know why the partition table defined by Solaris 10 6/06 differs to what Solaris 10 3/05 had defined? How do I force the parition table to match with the primary disk? Both disks must match so that SVM would work.
Can anyone shed any light as to why it happens? Thank you for your help.
Trevor

I want to set up RAID 1 (mirroring) using the Solaris Volume Manager (SVM) on my Solaris 10 6/06 x86 machine. I have 2 identical Seagate 40GB HDD's (model ST340016A).
The partition table on the primary disk was already defined by Solaris 10 3/05 OS before I reinstalled the OS (Solaris 10 6/06). The partition table of the primary disk is as follows:
leopard $ prtvtoc /dev/rdsk/c0d0s2
* /dev/rdsk/c0d0s2 partition map
* Dimensions:
* 512 bytes/sector
* 63 sectors/track
* 32 tracks/cylinder
* 2016 sectors/cylinder
* 38771 cylinders
* 38769 accessible cylinders
* Flags:
* 1: unmountable
* 10: read-only
* Unallocated space:
* First Sector Last
* Sector Count Sector
* 20984544 57173760 78158303
* First Sector Last
* Partition Tag Flags Sector Count Sector Mount Directory
0 2 00 6048 8390592 8396639 /
1 3 01 8396640 2098656 10495295
2 5 00 0 78158304 78158303
3 7 00 10495296 2098656 12593951 /var
4 0 00 12593952 4195296 16789247 /opt
5 8 00 16789248 4195296 20984543 /home
8 1 01 0 2016 2015
9 9 01 2016 4032 6047
It has 38771 cyclinders.
Now I want to create exactly the same partition table on the secondary disk, but it refuses to match the same partition table to the primary disk. It stills gives 40GB, but the number of cycliners is not the same. Below is the partition table of the secondary disk.
leopard $ prtvtoc /dev/rdsk/c0d1s2
* /dev/rdsk/c0d1s2 partition map
* Dimensions:
* 512 bytes/sector
* 63 sectors/track
* 255 tracks/cylinder
* 16065 sectors/cylinder
* 4864 cylinders
* 4862 accessible cylinders
* Flags:
* 1: unmountable
* 10: read-only
* Unallocated space:
* First Sector Last
* Sector Count Sector
* 48195 78059835 78108029
* First Sector Last
* Partition Tag Flags Sector Count Sector Mount Directory
2 5 01 0 78108030 78108029
8 1 01 0 16065 16064
9 9 00 16065 32130 48194
leopard $
It has 4864 cyclinders not 38771. Why?
You can see the disk dimension is different between these 2 disks. I tried to redefine it to match the primary disk, but it keeps coming back to the different table.
Do you know why the partition table defined by Solaris 10 6/06 differs to what Solaris 10 3/05 had defined? How do I force the parition table to match with the primary disk? Both disks must match so that SVM would work.
Can anyone shed any light as to why it happens? Thank you for your help.
Trevor

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for example：
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if i delete “-statful” and “timeout", then what‘s will happen，any performance issue or something else？

Looking up the PowerShell command in TechNet will explain each parameter. As will the PowerShell command Help
Add-VMNetworkAdapterExtendedAcl -parameter Stateful.
http://technet.microsoft.com/en-us/library/dn464289.aspx
If you do not understand the explanation provided by TechNet or Help, please post your question about its definition back here.
. : | : . : | : . tim

Different between "iostat 5" and "zpool iostat 5"

Hi,
if using ZFS, is it recommended to use zpool iostat over the normal iostat?
Basically what is the different between both?
In normal iostat, what is the most valuable info we need to look into to measure the performance? a_svc, b%, w%?
where in zpool iostat, what is the most valuable info we need to look into to measure the performance? and how to determine it is slow or fast? since, there are no a_svc, b%, w%??
in the following info in http://docs.oracle.com/cd/E19253-01/819-5461/gammt/index.html?
# zpool iostat
capacity operations bandwidth
pool alloc free read write read write
rpool 6.05G 61.9G 0 0 786 107
tank 31.3G 36.7G 4 1 296K 86.1K
what does 786 and 107 for rpool refer to? kilobyte?bytes? bit?
Thanks

if using ZFS, is it recommended to use zpool iostat over the normal iostat?I like both of them, but I'd recommend 'zpool iostat -v' because it will also give you per-device statistics through zpool.
Basically what is the different between both?iostat displays statistics for all devices, zpool iostat will only give statistics for devices in a zpool. When you have cache and log devices and mirrors and stuff configured, iostat may not be very easy to read. But iostat has information on service time that zpool iostat does not have
In normal iostat, what is the most valuable info we need to look into to measure the performance? a_svc, b%, w%?I usually look at number of operations (read and write), service time (svc_t) and sometimes the throughbut (kread, kwrite). I don't trust %b or %w because I nerver really understood how they are calculated, I also suspect they may be calculated differently on different platforms (linux and solaris) and I have seen cases where they have just been wrong. So I go by rules of thumb for operations and service times:
A single disk should be able to provide ~100 random read operations per second. Maybe 150, maybe 75 but definitely somewhere in that region. If the reported number gets close to that (or bigger), I start to get worried.
The service time of a random read request should be about 4-6ms. Maybe 7 or 8. But if the service time is reported in double-digits, I start to get worried.
Everything else will depend on your application and your threshold for nervousness. Some of my customers feel ok until %b reaches 80%, some may think that service times of 12ms are ok. The best way is to compare these numbers to baselines from when the system is performing OK.
where in zpool iostat, what is the most valuable info we need to look into to measure the performance? and how to determine it is slow or fast? since, there are no a_svc, b%, w%??again, reads and writes is usually what I look for.
in the following info in http://docs.oracle.com/cd/E19253-01/819-5461/gammt/index.html?
# zpool iostat
capacity operations bandwidth
pool alloc free read write read write
rpool 6.05G 61.9G 0 0 786 107
tank 31.3G 36.7G 4 1 296K 86.1K
what does 786 and 107 for rpool refer to? kilobyte?bytes? bit?bandwidth is reported in bytes. In this case, zpool iostat was called without a repeat-interval so only the average since system boot is reported. So in this case 786 bytes have been read per second on average since system start. Quite a useless number.
Bjoern

OATM : number of commands differs between runs

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