Open (ExternalWindow or something else) new BrowserWindow

Question

Hello@all,
I have in a component two windows and I have stored a PDF File in src->mimes->Components--->"ComponentenPath".
In the View of the first Window, I have a LinkToAction. With the onAction I want to open the other Window in a new Browser-Window. In the View of the second window I have an Iframe with dataSource--->"PDFFile".
How can I open this window in a extra Browser-Window??
Thank you for help.
Best regards
Marcus

Answer 1

Hi,
    In the First View  :
  when the User clicks the LinkToAction Popup the window with the Pdf Form.
for eg :
   public void onActionShowPdfView(
          com.sap.tc.webdynpro.progmodel.api.IWDCustomEvent wdEvent )
   //@@begin onActionShowPdfView(ServerEvent)
   //get the repository content at runtime of the Web-Dynpro-
   // Window “PDFWindow”
   IWDWindowInfo windowInfo = (IWDWindowInfo)wdComponentAPI
                               .getComponentInfo()
                               .findInWindows("PDFWindow");
   //create the “PDFWindow”
   IWDWindow window = wdComponentAPI.getWindowManager()
                               .createWindow( windowInfo, true);
   //set the WindowPosition on the screen
   window.setWindowPosition(300, 150);
   //and show the window
   window.open();
   // Save WindowInstance in Context
   wdContext.currentPopupElement().setWindowInstance(window);
   //@@end
Here the Window Instance  is the Context Attribute of type com.sap.tc.webdynpro. services.session.api.IWDWindow
belongs to the component Controller.
and this will be holding the window Instance.
Now In the second Pdf View , when we close the window the window instance is destroyed as .
IWDWindow window = 
           wdContext.currentPopupElement().getWindowInstance();
   window.destroy();
Thanks and Regards
Fazal B