Order By Two Different Fields

Dear All,
I have a Table Like this,
CREATE TABLE test_d (c_id VARCHAR2(10),i_no NUMBER,i_date DATE)
which contains the data as,
C_ID     I_NO     I_DATE
1     2     19-Jan-2007
1     3     19-Dec-2006
1     4     19-Nov-2006
1     5     19-Oct-2006
1     6     19-Sep-2006
1     1     19-Feb-2007
2     6     19-Feb-2007
2     5     19-Jan-2007
2     4     19-Dec-2006
2     3     19-Nov-2006
2     2     19-Oct-2006
2     1     19-Sep-2006
Now, I want to write a Sql to find the records,for which i_no "1" i_date is greater than i_no "2" i_Date and respectively.

SQL> select * from test_d
2 /
C_ID             I_NO I_DATE
1                   2 19-01-2007 00:00:00
1                   3 19-12-2006 00:00:00
1                   4 19-11-2006 00:00:00
1                   5 19-10-2006 00:00:00
1                   6 19-09-2006 00:00:00
1                   1 19-02-2007 00:00:00
2                   6 19-02-2007 00:00:00
2                   5 19-01-2007 00:00:00
2                   4 19-12-2006 00:00:00
2                   3 19-11-2006 00:00:00
2                   2 19-10-2006 00:00:00
2                   1 19-09-2006 00:00:00
12 rijen zijn geselecteerd.
SQL> select c_id
2       , i_no
3       , i_date
4    from ( select test_d.*
5                , max(i_date) over (partition by i_no) max_i_date
6                , min(i_date) over (partition by i_no) min_i_date
7             from test_d
8         )
9   where max_i_date > min_i_date
10     and ( (   c_id = 1
11            and i_date = max_i_date
12            )
13         or (   c_id = 2
14            and i_date = min_i_date
15            )
16         )
17   order by i_no
18       , c_id
19 /
C_ID             I_NO I_DATE
1                   1 19-02-2007 00:00:00
2                   1 19-09-2006 00:00:00
1                   2 19-01-2007 00:00:00
2                   2 19-10-2006 00:00:00
1                   3 19-12-2006 00:00:00
2                   3 19-11-2006 00:00:00
6 rijen zijn geselecteerd.Regards,
Rob.

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