Overriden - Signature in functions

Question

Hi,
I have a generic question about function overriden. If I have:
abstract public class A {...}
public class A1 extends A {...}
public class A2 extends A {...}
abstract public class B {
   abstract public <T extends A> void function(T t);
public class B1 extends B {
   @Override
   public <T extends A1> void function(T t);
public class B2 extends B {
   @Override
   public <T extends A2> void function(T t);
}why it does not work. I know functions should have the same signature, but why it is not the case in this example?
And how is it possible to have the same result?
Thanks,

Answer 1

Ok, but
abstract public class A {...}
public class A1 extends A {...}
public class A2 extends A {...}
abstract public class B {
   abstract public void function(A t);
public class B1 extends B {
   @Override
   public void function(A1 t);
public class B2 extends B {
   @Override
   public void function(A2 t);
}does not work either...