Parsing a text file using regular expression

hi all,
i have a text file which is delimited by a pipe symbol.
eg.|4| |2| |1| |abcde| 345 |2000|...................
can anyone help me writing the regular expression for the above case.
Thanks

Would splitting the string into tokens help you?
String s = "|4| |2| |1| |abcde| 345 |2000|";
String[] token = s.split("\\|");
int len = token.length;
for (int i=0; i<len; i++) {
 String t = token.trim();
 if (!t.equals("")) {
 System.out.println(t);

Similar Messages

I need help renaming a file using regular expressions in Bridge.

Hi,
I work at a university, and we are working through files for our Thesis and Dissertations. We have been renaming them to make them more consistent. I am just wondering if there is a regular expression that could help with this process?
Here is come examples of current file names;
THESIS 1981 H343G
Thesis 1981 g996e
THESIS-1981-A543G
I don't need to change the actual names of the files. just how they are formatted.
Proper case on Thesis.
Hyphens(-) in all white space.
First letter capital, last letter lowercase on the call no (H343g)
So the list above should look like;
Thesis-1981-H343g
Thesis-1981-G996e
Thesis-1981-A543g
I have seen people do some pretty cool things with regular expressions! Any help would be greatly appreciated. Thanks!

You would be better off using a script to do this as an example as I don't think it would be possible in the Bridge re-name.
Using ExtendScript Toolkit or a Plain text editor copy the code into either and save it out as Filename.jsx
This needs to be saved into the correct folder. this is found by going to the preferences in Bridge, selecting Startup Scripts, this will open the folder where the script is to be saved.
Once this is done close and re-start Bridge.
To Use: Goto the Tools Menu and select Rename PDFs
Make sure you test the code with a few copied files into a seperate folder first to make sure it does what you want.
The script will do all PDF files in the selected folder.
#target bridge
if( BridgeTalk.appName == "bridge" ) {
renamePDFs = MenuElement.create("command", "Rename PDFs", "at the end of Tools");
renamePDFs.onSelect = function () {
app.document.deselectAll();
var thumbs = app.document.getSelection("pdf");
for( var z in thumbs){
var Name = decodeURI(thumbs[z].spec.name);
var parts = Name.toLowerCase().replace(/\s/g,'-').match(/(.*)(-)(.*)(-)(.*)(\.pdf)/);
var NewName = parts[1].replace(/^[a-z]/, function(s){ return s.toUpperCase() });
NewName += parts[2]+parts[3]+parts[4]+parts[5].toUpperCase().replace(/[A-Z]$/, function(s){ return s.toLowerCase() });
NewName += parts[6];
thumbs[z].spec.rename(NewName);

Find text using regular expression and add highlight annotation

Hi Friends
Is it possible to find text using regular expression and add highlight annotation using plugin

A plugin can use the PDWordFinder to get a list of the words on a page, and their location. That's all that the API offers for searching. Of course, you can use a regular expression library to work with that word list.

Rplacing space with &nbsb; in html using regular expressions

Hi
I want to replace space with &nbsb; in HTML.
I used the below method to replace space in my html file.
var spacePattern11:RegExp =/(\s)/g;
str= str.replace(spacePattern," "
Here str varaible contains below html file.In this html file i want to replace space present between " What number does this represents" with &nbsb;
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title>
</head>
<body>
<TEXTFORMAT LEADING="2"></TEXTFORMAT><TEXTFORMAT LEADING="2"> What number does this Roman numeral represents MDCCCXVIII ?</TEXTFORMAT>
</body>
</html>
But by using the above regular expression i am getting like this.
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title>
</head><body>
<TEXTFORMAT LEADING="2"></TEXTFORMAT><TEXTFORMAT LEADING="2"> What number does this represents</TEXTFORMAT>
</body>
</html>
Here what happening means it was replacing space with &nbsb; in HTML tags also.But want to replace space with &nbsb; present in the outside of the HTML tags.I want like this using regular expressions in FLEX
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title>
</head>
<body>What number does this represents</body>
</html>
Hi,Please give me the solution to slove the above problem using regular expressions
Thanks in Advance to all
Regards
ssssssss

sorry i missed some information in above,The modified information was in red color
Hi
I want to replace space with &nbsb; in HTML.
I used the below method to replace space in my html file.
var spacePattern11:RegExp =/(\s)/g;
str= str.replace(spacePattern," "
Here str varaible contains below html file.In this html file i want to replace space present between " What number does this represents" with &nbsb;
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title>
</head>
<body>
<TEXTFORMAT LEADING="2"></TEXTFORMAT><TEXTFORMAT LEADING="2"> What number does this Roman numeral represents MDCCCXVIII ?</TEXTFORMAT>
</body>
</html>
But by using the above regular expression i am getting like this.
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title>
</head><body>
<TEXTFORMAT LEADING="2"></TEXTFORMAT><TEXTFORMAT LEADIN G="2"> What number does this represents</TEXTFORMAT>
</body>
</html>
Here what happening means it was replacing space with &nbsb; in HTML tags also.But want to replace space with &nbsb; present in the outside of the HTML tags.I want like this using regular expressions in FLEX
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title>
</head>
<body>What&nbsb;number&nbsb;does&nbsb;this&nbsb;represents</body>
</html>
Hi,Please give me the solution to slove the above problem using regular expressions
Thanks in Advance to all
Regards
ssssssss

Attaching text file using SO_NEW_DOCUMENT_ATT_SEND_API1

hello guys, i'm a newbie here.
I'm having trouble attaching an existing text file using function 'SO_NEW_DOCUMENT_ATT_SEND_API1'. It seems i can't find the right combination of parameters that are being passed to this function.
first, i'm using WS_UPLOAD to upload the text file to an internal table then i'm creating all the neccessary internal tables that will be use by this function..
By the way, i'm trying to send mail w/ attachments to external mail and SAPids. Below is my code.
REPORT ZHR_TESTEMAIL .
TABLES: USR02, PA0105, SOSU, SOUC, RLGRAP, IBIPPARMS, DYNPREAD, RSCSEL.
DATA: FOLD_YR(2) TYPE C,
 FOLD_TYPE(3) TYPE C,
 G_HEADER LIKE SOOD2,
 G_FOLMAM LIKE SOFM2,
 METHOD1 LIKE SY-UCOMM,
 G_DOCUMENT LIKE SOOD4,
 G_USER LIKE SOUDNAMEI1,
 FOLD_NUMBER(12) TYPE C,
 G_NEW_PARENT LIKE SOODK,
 G_OWNER LIKE SOUD-USRNAM,
 G_REF_DOCUMENT LIKE SOOD4,
 G_USER_DATA LIKE SOUDATAI1,
 G_AUTHORITY LIKE SOFA-USRACC,
 G_OBJCNT LIKE SOLI OCCURS 0 WITH HEADER LINE,
 G_OBJHEAD LIKE SOLI OCCURS 0 WITH HEADER LINE,
 G_OBJPARA LIKE SELC OCCURS 0 WITH HEADER LINE,
 G_OBJPARB LIKE SOOP1 OCCURS 0 WITH HEADER LINE,
 G_RECIPIENTS LIKE SOOS1 OCCURS 0 WITH HEADER LINE,
 G_REFERENCES LIKE SOXRL OCCURS 0 WITH HEADER LINE,
 G_ATTACHMENTS LIKE SOOD5 OCCURS 0 WITH HEADER LINE.
DATA: BEGIN OF G_FILES OCCURS 10 ,
 TEXT(4096) TYPE C,
 END OF G_FILES.
DATA: BEGIN OF IT_WS_FILE OCCURS 0,
 WS_FILE LIKE RLGRAP-FILENAME,
 END OF IT_WS_FILE.
DATA: BEGIN OF IT_SAPID OCCURS 0,
 SAPID LIKE USR02-BNAME,
 END OF IT_SAPID.
DATA: BEGIN OF IT_EMAIL OCCURS 0,
 EMAILADD LIKE PA0105-USRID_LONG,
 END OF IT_EMAIL.
DATA: BEGIN OF IT_TSP01 OCCURS 0.
 INCLUDE STRUCTURE TSP01.
DATA: END OF IT_TSP01.
DATA: BEGIN OF TAB2 OCCURS 50,
 TEXT(200) TYPE C,
 END OF TAB2.
DATA: V_DOCDATA TYPE SODOCCHGI1,
 V_OBJPACK LIKE SOPCKLSTI1 OCCURS 0 WITH HEADER LINE,
 V_OBJHEAD LIKE SOLISTI1 OCCURS 0 WITH HEADER LINE,
 V_OBJTXT LIKE SOLISTI1 OCCURS 0 WITH HEADER LINE,
 V_OBJBIN LIKE SOLISTI1 OCCURS 0 WITH HEADER LINE,
 V_OBJHEX LIKE SOLIX OCCURS 0 WITH HEADER LINE,
 IT_RECVRS TYPE SOMLRECI1 OCCURS 0 WITH HEADER LINE,
 IT_CONTNT TYPE SOLISTI1 OCCURS 0 WITH HEADER LINE,
 IT_BODY LIKE SOLISTI1 OCCURS 10 WITH HEADER LINE,
 V_TLIN TYPE I,
 V_LINE TYPE I.
DATA: BEGIN OF IT_TEXTLINE OCCURS 500,
 TEXTLINE(5000),
 END OF IT_TEXTLINE.
DATA: FYL LIKE RLGRAP-FILENAME,
 GV_SUBNO LIKE SOSU-SUBNO,
 GV_EMAIL LIKE PA0105-USRID_LONG,
 GV_NEXTDAY LIKE SY-DATUM,
 YEAR(4) TYPE C,
 RECFLAG TYPE C.
SELECTION-SCREEN BEGIN OF BLOCK PARAM WITH FRAME TITLE TEXT-001.
PARAMETERS: SUBJ(254) TYPE C OBLIGATORY, "Subject
 DESC(254) TYPE C. "Message
SELECT-OPTIONS: SAPID FOR USR02-BNAME NO INTERVALS. "Recipient's SAP ID
SELECT-OPTIONS: EMAILADD FOR PA0105-USRID_LONG NO INTERVALS.
SELECTION-SCREEN END OF BLOCK PARAM.
SELECTION-SCREEN BEGIN OF BLOCK PARAM2 WITH FRAME TITLE TEXT-002.
SELECT-OPTIONS: WS_FILE FOR DYNPREAD-FIELDNAME NO INTERVALS.
SELECTION-SCREEN END OF BLOCK PARAM2.
SELECTION-SCREEN BEGIN OF BLOCK PARAM3 WITH FRAME TITLE TEXT-003.
SELECTION-SCREEN BEGIN OF LINE.
PARAMETERS: RBUT1 RADIOBUTTON GROUP A USER-COMMAND BUT. "Local PC
SELECTION-SCREEN COMMENT 5(20) FOR FIELD RBUT1.
SELECTION-SCREEN END OF LINE.
SELECTION-SCREEN BEGIN OF LINE.
PARAMETERS: RBUT2 RADIOBUTTON GROUP A. "Server
SELECTION-SCREEN COMMENT 5(20) FOR FIELD RBUT2.
SELECTION-SCREEN END OF LINE.
SELECTION-SCREEN BEGIN OF LINE.
PARAMETERS: RBUT3 RADIOBUTTON GROUP A. "Spool
SELECTION-SCREEN COMMENT 5(20) FOR FIELD RBUT3.
PARAMETERS: SPOOLNUM LIKE RSPOTYPE-RQNUMBER. "Spool Number
SELECTION-SCREEN END OF LINE.
SELECTION-SCREEN END OF BLOCK PARAM3.
SELECTION-SCREEN BEGIN OF BLOCK PROC WITH FRAME TITLE TEXT-004.
SELECTION-SCREEN BEGIN OF LINE.
PARAMETER: BPROC AS CHECKBOX USER-COMMAND BCK. "Background Processing
SELECTION-SCREEN COMMENT 5(50) FOR FIELD BPROC.
SELECTION-SCREEN END OF LINE.
SELECTION-SCREEN END OF BLOCK PROC.
AT SELECTION-SCREEN ON VALUE-REQUEST FOR WS_FILE-LOW.
DATA: WS_FILE_TEMP TYPE IBIPPARMS-PATH.
CLEAR: WS_FILE_TEMP.
CALL FUNCTION 'F4_FILENAME'
 EXPORTING
 PROGRAM_NAME = SY-REPID
 DYNPRO_NUMBER = SY-DYNNR
 FIELD_NAME = 'WS_FILE'
 IMPORTING
 FILE_NAME = WS_FILE_TEMP.
WS_FILE-LOW = WS_FILE_TEMP.
AT SELECTION-SCREEN.
SELECT SAPNAM FROM SOUC
 INTO TABLE IT_SAPID
 WHERE SAPNAM IN SAPID
 AND DELETED = ''.
GV_NEXTDAY = SY-DATUM + 1.
LOOP AT EMAILADD.
 IT_EMAIL-EMAILADD = EMAILADD-LOW.
 APPEND IT_EMAIL.
 CLEAR: IT_EMAIL.
ENDLOOP.
IF NOT BPROC IS INITIAL.
 CLEAR: RBUT1, RBUT3.
 RBUT2 = 'X'.
ELSE.
 CLEAR: RBUT2.
ENDIF.
IF NOT RBUT3 IS INITIAL.
 REFRESH: WS_FILE.
ENDIF.
IF SAPID IS INITIAL AND EMAILADD IS INITIAL.
 MESSAGE E000(ZZ) WITH TEXT-201.
ELSEIF NOT SAPID IS INITIAL AND EMAILADD IS INITIAL.
 CLEAR IT_SAPID.
 READ TABLE IT_SAPID.
 SELECT SINGLE SUBNO FROM SOSU
 INTO GV_SUBNO
 WHERE USRNO IN ( SELECT USRNO FROM SOUC
 WHERE SAPNAM = IT_SAPID-SAPID ).
 IF SY-SUBRC NE 0.
 MESSAGE E000(ZZ) WITH TEXT-202.
 ENDIF.
 CLEAR: IT_SAPID.
ELSEIF NOT SAPID IS INITIAL AND NOT EMAILADD IS INITIAL.
 CLEAR: IT_SAPID, IT_EMAIL.
 READ TABLE IT_SAPID.
 READ TABLE IT_EMAIL.
 SELECT SINGLE SUBNO FROM SOSU
 INTO GV_SUBNO
 WHERE USRNO IN ( SELECT USRNO FROM SOUC
 WHERE SAPNAM = IT_SAPID-SAPID ).
 IF SY-SUBRC NE 0.
 SUBMIT RSSOADM0 WITH USRNAM EQ IT_SAPID-SAPID
 WITH NEW_SUBS EQ IT_EMAIL-EMAILADD
 WITH SUB_ESC EQ 'U'
 WITH EDAT EQ SY-DATUM
 WITH BDAT EQ SY-DATUM
 WITH BDAT EQ GV_NEXTDAY
 WITH EDAT EQ '99991231'
 WITH BTIM EQ SY-UZEIT
 WITH ETIM EQ '240000'
 WITH FORW_ALL EQ 'X'
 WITH PSTHR2 EQ ''
 AND RETURN.
 ENDIF.
 CLEAR: IT_SAPID.
ELSEIF NOT EMAILADD IS INITIAL AND SAPID IS INITIAL.
 RECFLAG = 'X'.
ENDIF.
START-OF-SELECTION.
 PERFORM B_SENDMAIL.
FORM B_SENDMAIL.
YEAR = SY-DATUM+0(4).
LOOP AT WS_FILE.
 CLEAR: FYL.
 FYL = WS_FILE-LOW.
 REFRESH: TAB2.
 CALL FUNCTION 'WS_UPLOAD'
 EXPORTING
 FILENAME = FYL
 FILETYPE = 'BIN'
 TABLES
 DATA_TAB = TAB2.
 IT_TEXTLINE[] = TAB2[].
DOCUMENT_DATA (SUBJECT OF MAIL)
 V_DOCDATA-OBJ_NAME = DESC.
 V_DOCDATA-OBJ_DESCR = SUBJ.
 V_DOCDATA-OBJ_LANGU = SY-LANGU.
 V_DOCDATA-SENSITIVTY = 'C'.
 V_DOCDATA-OBJ_PRIO = '1'.
BODY OF MAIL
 IT_BODY-LINE = 'Collection Report'.
 APPEND IT_BODY.
CONTENTS_TXT (Attachments)
 IT_CONTNT[] = IT_TEXTLINE[].
 DESCRIBE TABLE IT_CONTNT LINES V_LINE.
 READ TABLE IT_CONTNT INDEX V_LINE.
PACKING_LIST
 V_OBJPACK-DOC_SIZE = ( V_LINE - 1 ) * 255 + STRLEN( IT_CONTNT ).
 V_OBJPACK-TRANSF_BIN = 'X'.
 V_OBJPACK-HEAD_START = 1.
 V_OBJPACK-HEAD_NUM = 0.
 V_OBJPACK-BODY_START = 1.
 V_OBJPACK-BODY_NUM = V_LINE.
 V_OBJPACK-DOC_TYPE = 'TXT'.
 V_OBJPACK-OBJ_NAME = 'ATTACHMENT'.
 V_OBJPACK-OBJ_DESCR = 'Attached Document'.
 APPEND V_OBJPACK.
 CLEAR V_OBJPACK.
RECEIVERS of mail
 IF RECFLAG IS INITIAL.
 LOOP AT IT_SAPID.
 IT_RECVRS-RECEIVER = IT_SAPID-SAPID.
 IT_RECVRS-REC_TYPE = 'B'.
 IT_RECVRS-COM_TYPE = ''.
 IT_RECVRS-EXPRESS = 'X'.
 IT_RECVRS-NO_FORWARD = ''.
 IT_RECVRS-NO_PRINT = ''.
 APPEND IT_RECVRS.
 CLEAR IT_RECVRS.
 ENDLOOP.
 ELSE.
 LOOP AT EMAILADD.
 IT_RECVRS-RECEIVER = EMAILADD-LOW.
 IT_RECVRS-REC_TYPE = 'U'.
 IT_RECVRS-COM_TYPE = 'INT'.
 IT_RECVRS-EXPRESS = 'X'.
 APPEND IT_RECVRS.
 CLEAR IT_RECVRS.
 ENDLOOP.
 ENDIF.
OBJECT_HEADER (Filename)
 CONCATENATE 'Collection Report' '_'
 SY-DATUM+4(4) YEAR '.TXT'
 INTO V_OBJHEAD-LINE.
 V_OBJHEAD-LINE = FYL+16(25).
 APPEND V_OBJHEAD.
 CLEAR V_OBJHEAD.
Function Module For Sending Mail with Attachment
 CALL FUNCTION 'SO_NEW_DOCUMENT_ATT_SEND_API1'
 EXPORTING
 DOCUMENT_DATA = V_DOCDATA
 TABLES
 PACKING_LIST = V_OBJPACK
 OBJECT_HEADER = V_OBJHEAD
 CONTENTS_HEX = IT_CONTNT
 CONTENTS_TXT = IT_BODY
 RECEIVERS = IT_RECVRS
 EXCEPTIONS
 TOO_MANY_RECEIVERS = 1
 DOCUMENT_NOT_SENT = 2
 DOCUMENT_TYPE_NOT_EXIST = 3
 OPERATION_NO_AUTHORIZATION = 4
 PARAMETER_ERROR = 5
 X_ERROR = 6
 ENQUEUE_ERROR = 7
 OTHERS = 8.
 IF SY-SUBRC = 0.
 MESSAGE S000(ZZ) WITH TEXT-005.
 ELSE.
 MESSAGE S000(ZZ) WITH TEXT-006.
 ENDIF.
ENDLOOP.
end of my code *
please help me guys... when i run this program, DOCUMENT_NOT_SENT is what i always get..
waiting for ur reply... thank you vey much and godbless.

Hi,
Try this sample code.
FORM SEND_TO_EMAIL USING zFName.
DATA: OBJPACK LIKE SOPCKLSTI1 OCCURS 2 WITH HEADER LINE.
DATA: OBJHEAD LIKE SOLISTI1 OCCURS 1 WITH HEADER LINE.
DATA: OBJBIN LIKE SOLISTI1 OCCURS 10 WITH HEADER LINE.
DATA: OBJTXT LIKE SOLISTI1 OCCURS 10 WITH HEADER LINE.
DATA: RECLIST LIKE SOMLRECI1 OCCURS 5 WITH HEADER LINE.
DATA: DOC_CHNG LIKE SODOCCHGI1.
DATA: TAB_LINES LIKE SY-TABIX.
DATA: ctmp(50) TYPE C.
Creation of the document to be sent
DOC_CHNG-OBJ_NAME = 'JOURNAL'.
CONCATENATE 'SAP Payroll Journal file Period' pybegda INTO ctmp
 SEPARATED BY SPACE.
DOC_CHNG-OBJ_DESCR = cTmp.
OBJTXT = 'SAP Payroll Journal'.
APPEND OBJTXT.
CONCATENATE 'For Period' pybegda INTO ctmp
 SEPARATED BY SPACE.
OBJTXT = ctmp.
APPEND OBJTXT.
CONCATENATE 'Attached File :' zFname INTO ctmp
 SEPARATED BY SPACE.
OBJTXT = ctmp.
APPEND OBJTXT.
OBJTXT = 'Please find the attachment.'.
APPEND OBJTXT.
DESCRIBE TABLE OBJTXT LINES TAB_LINES.
READ TABLE OBJTXT INDEX TAB_LINES.
DOC_CHNG-DOC_SIZE = ( TAB_LINES - 1 ) * 255 + STRLEN( OBJTXT ).
Creation of the entry for the compressed document
CLEAR OBJPACK-TRANSF_BIN.
OBJPACK-HEAD_START = 1.
OBJPACK-HEAD_NUM = 0.
OBJPACK-BODY_START = 1.
OBJPACK-BODY_NUM = TAB_LINES.
OBJPACK-DOC_TYPE = 'RAW'.
APPEND OBJPACK.
Creation of the document attachment
LOOP AT xMail.
 CONDENSE xMail-aline.
 OBJBIN = xMail-aline.
 APPEND OBJBIN.
 CLEAR OBJBIN.
ENDLOOP.
DESCRIBE TABLE OBJBIN LINES TAB_LINES.
OBJHEAD = zFname. APPEND OBJHEAD.
Creation of the entry for the compressed attachment
OBJPACK-TRANSF_BIN = 'X'.
OBJPACK-HEAD_START = 1.
OBJPACK-HEAD_NUM = 1.
OBJPACK-BODY_START = 1.
OBJPACK-BODY_NUM = TAB_LINES.
OBJPACK-DOC_TYPE = 'RAW'.
OBJPACK-OBJ_NAME = 'DATA'.
OBJPACK-OBJ_DESCR = 'SAP Payroll File'.
OBJPACK-DOC_SIZE = TAB_LINES * 255.
APPEND OBJPACK.
Completing the recipient list
LOOP AT PENERIMA.
 CONDENSE PENERIMA-PNRM.
 RECLIST-RECEIVER = PENERIMA-PNRM.
 RECLIST-REC_TYPE = 'U'.
 APPEND RECLIST.
ENDLOOP.
Sending the document
CALL FUNCTION 'SO_NEW_DOCUMENT_ATT_SEND_API1'
 EXPORTING
 DOCUMENT_DATA = DOC_CHNG
 PUT_IN_OUTBOX = ' '
 TABLES
 PACKING_LIST = OBJPACK
 OBJECT_HEADER = OBJHEAD
 CONTENTS_BIN = OBJBIN
 CONTENTS_TXT = OBJTXT
 RECEIVERS = RECLIST
 EXCEPTIONS
 TOO_MANY_RECEIVERS = 1
 DOCUMENT_NOT_SENT = 2
 OPERATION_NO_AUTHORIZATION = 4
 OTHERS = 99.
CASE SY-SUBRC.
 WHEN 0.
 WRITE: / 'Result of the send process:'.
 LOOP AT RECLIST.
 WRITE: / RECLIST-RECEIVER(48), ':'.
 IF RECLIST-RETRN_CODE = 0.
 WRITE / 'The document was sent'.
 ELSE.
 WRITE / 'The document could not be sent'.
 ENDIF.
 ENDLOOP.
 WHEN 1.
 WRITE: / 'Too many receiver'.
 WHEN 2.
 WRITE: / 'Document could not be sent to any recipient'.
 WHEN 4.
 WRITE: / 'No send authorization'.
 WHEN OTHERS.
 WRITE: / 'Error occurred while sending'.
ENDCASE.
ENDFORM.

Using regular expressions in java

Does anyone of you know a good source or a tutorial for using regular expressions in java.
I just want to look at some examples....
Thanks

thanks a lot... i have one more query
Boundary matchers
^      The beginning of a line
$      The end of a line
\b      A word boundary
\B      A non-word boundary
\A      The beginning of the input
\G      The end of the previous match
\Z      The end of the input but for the final terminator, if any
\z      The end of the input
if i want to use the $ for comparing with string(text) then how can i use it.
Eg if it is $120 i got a hit
but if its other than that if should not hit.

Changeparticular characters in a string by using regular expressions ...

Hello Everyone,
I am trying to write a function by using oracles regular expression function REGEXP_REPLACE but I could not succed till now.
My problem as follows, I have a text in a column for example let say 'sdfsdf Sdfdfs Sdfd' I want replace all s and S characters with X and make the text look like 'XdfXdf XdfdfX Xdfd'.
Is it possible by using regular expressions in oracle ?
Can you give me some clues ?
Thank you

SSU wrote:
Hello Everyone,
I am trying to write a function by using oracles regular expression function REGEXP_REPLACE but I could not succed till now.
My problem as follows, I have a text in a column for example let say 'sdfsdf Sdfdfs Sdfd' I want replace all s and S characters with X and make the text look like 'XdfXdf XdfdfX Xdfd'.
Is it possible by using regular expressions in oracle ?
Can you give me some clues ?
Thank you
SQL> SELECT
2 regexp_replace('sdfsdf Sdfdfs Sdfd','s|S','X') from dual;
REGEXP_REPLACE('SD
XdfXdf XdfdfX XdfdRegards,
Achyut

Using regular expressions for validating time fields

Similar to my problem with converting a big chunk of validation into smaller chunks of functions I am trying to use Regular Expressions to handle the validation of many, many time fields in a flexible working time sheet.
I have a set of FormCalc scripts to calculate the various values for days, hours and the gain/loss of hours over a four week period. For these scripts to work the time format must be in HH:MM.
Accessibility guidelines nix any use of message box pop ups so I wanted to get around this by having a hidden/visible field with warning text but can't get it to work.
So far I have:
var r = new RegExp(); // Create a new Regular Expression Object
r.compile ("^[00-99]:\\] + [00-59]");
var result = r.test(this.rawValue);
if (result == true){
true;
form1.flow.page.parent.part2.part2body.errorMessage.presence = "visible";
else (result == false){
false;
form1.flow.page.parent.part2.part2body.errorMessage.presence = "hidden";
Any help would be appreciated!

Date and time fields are tricky because you have to consider the formattedValue versus the rawValue. If I am going to use regular expressions to do validation I find it easier to make them text fields and ignore the time patterns (formattedValue). Something like this works (as far as my very brief testing goes) for 24 hour time where time format is HH:MM.
// form1.page1.subform1.time_::exit - (JavaScript, client)
var error = false;
form1.page1.subform1.errorMsg.rawValue = "";
if (!(this.isNull)) {
var time_ = this.rawValue;
if (time_.length != 5) {
    error = true;
else {
    var regExp = /^([01]?[0-9]|2[0-3]):[0-5][0-9]$/;
    if (!(regExp.test(time_))) {
      error = true;
if (error == true) {
form1.page1.subform1.errorMsg.rawValue = "The time must be in the format HH:MM where HH is 00-23 and MM is 00-59.";
form1.page1.subform1.errorMsg.presence = "visible";
Steve

Using Regular Expressions To Remove Characters JDK 1.4

I want to write a regular expression to remove all commas in a string of text.
string is:
1,000
or 1,000,000
I want it to return 1000 and 1000000.
I have tried some but I am just starting with Regular Expressions.
Please Help!

Try this tutorial: Linux : Education : Tutorials
Using regular expressions
David Mertz
President, Gnosis Software, Inc.
September 2000
http://www-105.ibm.com/developerworks/education.nsf/linux-onlinecourse-bytitle/6C2B4863702F592B8625696200589C5B?OpenDocument

Using Regular Expressions to replace Quotes in Strings

I am writing a program that generates Java files and there are Strings that are used that contain Quotes. I want to use regular expressions to replace " with \" when it is written to the file. The code I was trying to use was:
String temp = "\"Hello\" i am a \"variable\"";
temp = temp.replaceAll("\"","\\\\\"");
however, this does not work and when i print out the code to the file the resulting code appears as:
String someVar = ""Hello" i am a "variable"";
and not as:
String someVar = "\"Hello\" i am a \"variable\"";
I am assumming my regular expression is wrong. If it is, could someone explain to me how to fix it so that it will work?
Thanks in advance.

Thanks, appearently I'm just doing something weird that I just need to look at a little bit harder.

How to fetch substring using regular expression

Hi,
I am new to using regular expression and would like to know some basic details of how to use them in Java.
I have a String example= "http://www.google.com/foobar.html#*q*=database&aq=f&aqi=g10&fp=c9fe100d9e542c1e" and would like to get the value of "q" parameter (in bold) using regular expression in java.
For the same example, when we tried using javascript:
match = example.match("/^http:\/\/(?:(?!mail\.)[^\.]+?\.)?google\.[^\?#]+(?:.*[\?#&](?:as_q|q)=([^&]+))?/i}");
document.write('
' + match);
We are getting the output as: http://www.google.com/foobar.html#q=database,*database* where the bold text is the value of "q" parameter.
In Java we are trying to get the value of the q parameter separately or atleast resembles the output given by JavaScript. Please help me resolving this issue.
Regards
Praveen

BalusC wrote:
Regex is a cumbersome solution for fixed patterns like URL's. String#substring() in combination with String#indexOf would most likely already suffice.I usually agree, although, in this case, finding the exact parameter might be difficult without a small regex, perhaps:
"\\wq=\\s*"in conjunction with Pattern/Matcher, used similarly to an indexOf() to find the start of the parameter value.
Winston

How to create and read text file using LabVIEW 7.1 PDA module?

How to create and read text file using LabVIEW 7.1 PDA module? I can not create a text file and read it.
I attach my code here.
Attachments:
File_IO.vi ‏82 KB

Well my acquisition code runs perfect. The problem is reading it. I can't seem to read my data no matter what I do. My data gets saved as a string using the array to string vi but I've read that the string to array vi (which I need to convert back to array to read my data) does not work on the pda. I'm using version 8.0. So I was trying to modify the program posted in this discussion so that it would save data from my DAQ. I did that but I still can't read the data after its saved. I really don't know what else to do. All I need to do is read the data on the pda itself. I can't understand why I'm having such a hard time doing that. I found a possible solution on another discussion that talks about parsing the strings because of the bug in the "string to array" vi. However, that lead me to another problem because for some reason, the array indicators or graphs don't function on the pda. When i build the program to the pda or emulator, the array indicators are faded out on the front panel as if the function is not valid. Does this kind of help give a better picture of what I'm trying to do. Simply read data back. Thanks.

A question about using regular expression

Hi,
This is a part of HTML file.
how
are
you
I want to search string between each pair of , tags by using Regular Expression.
For example:
how
are
you
If I use following method
String regx="(.+)";
Matcher m=Pattern.compile(regx).matcher(str);
int currentLoc=0;
while(currentLoc<str.length()){
 if(m.find(currentLoc))
 System.out.println(m.group(1));
 currentLoc=m.end();
}The content between first and last will be searched.
How to solve this problem?

Use a non-greedy match:
(?s)(.+?)(?s) makes the dot match the line terminator (same as setting the dot all option)

Finding URLs using regular expression.

I have an requirement where user will type some text containing URLs like "Please visit this site http://www.google.com/e/qHvQcWco`~!@#$%^&*()-7747. Thank you". This text has to be modified as below before saving it to the database.
"Please visit this site <a href='http://www.google.com/e/qHvQcWco`~!@#$%^&*()-7747'>http://www.google.com/e/qHvQcWco`~!@#$%^&*()-7747</a>. Thank you"
I am using regular expression (http|https)://.+?\\s which marks the end of the url with a white space character.This pattern doesn't work if the URL is located at the end of the string since there will be no space at the end.
For example if the string is "Please visit this site http://www.google.com/e/qHvQcWco`~!@#$%^&*()-7747" the regex will fail.
My acutal problem is to find the URL irrespective its position within the string.
Pattern urlPattern = Pattern.compile("(http|https)://.+?\\s", Pattern.CASE_INSENSITIVE);
Matcher matcher = urlPattern.matcher(plainText);
Map stringIndexMap = new HashMap();
//Searching the input string for urlPattern...
while(matcher.find()) {
String urlString = matcher.group();
//Storing the urls in a hashmap with their indices as keys....
stringIndexMap.put(new Integer(matcher.start()), urlString.trim());
Set keySet = stringIndexMap.keySet();
Iterator it = keySet.iterator();
//Iterating over the hashmap containing urls...
while(it.hasNext()) {
String urlString = (String) stringIndexMap.get(it.next());
* Replacing the url string in the input text with <a href="#" onclick="window.open('<urlString>')"
* using String index
clickableURLString.replace(clickableURLString.indexOf(urlString),
clickableURLString.indexOf(urlString) + urlString.length(),
"<a href=\"#\" onclick=\"window.open('" + urlString
+ "')\">" + urlString + "</a>");
return clickableURLString.toString();

The end of the input is '$' as a regex.
import java.util.regex.*;
public class Prasanna{
public static void main(String[] args){
 String text
= "Please visit this site http://www.google.com/e/qHvQcWco`~!@#$%^&*()-7747";
// String regex = "(http|https)://.+?(?:\\s|$)"; // this works
 String regex = "(http|https)://[^ ]+"; // this also works
 Pattern pat = Pattern.compile(regex, Pattern.CASE_INSENSITIVE);
 Matcher mat = pat.matcher(text);
 while (mat.find()){
 System.out.println(mat.group());
}

Searching for a substring using Regular Expression

I have a lengthy String similar to repetetion of the one below
String str="<option value='116813070'>Something1</option><option value='ABCDEF' selected>Something 2</option>"I need to search for the Sub string "<option value='ABCDEF' selected>" (need to get the starting index of sub string) and but the value ABCDEF can be anything numberic with varying length.
Is there any way i can do it using regular expressions(I have no other options than regular expression)?
thanks in advance.

If you go through the tutorial then you will find this on the second page:
import java.io.Console;
import java.util.regex.Pattern;
import java.util.regex.Matcher;
public class RegexTestHarness {
 public static void main(String[] args){
 Console console = System.console();
 if (console == null) {
 System.err.println("No console.");
 System.exit(1);
 while (true) {
 Pattern pattern =
 Pattern.compile(console.readLine("%nEnter your regex: "));
 Matcher matcher =
 pattern.matcher(console.readLine("Enter input string to search: "));
 boolean found = false;
 while (matcher.find()) {
 console.format("I found the text \"%s\" starting at " +
 "index %d and ending at index %d.%n",
 matcher.group(), matcher.start(), matcher.end());
 found = true;
 if(!found){
 console.format("No match found.%n");
}It's does everything you need and a bit more. Adapt it to your needs then write a regular expression. Then if you have problems by all means come back and post them up here, but first at least attempt to solve it yourself.

Parsing a text file using regular expression

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