Parsing hexadecimal long very huge numbers

Hi all:
How i can parse a hexadecimal long number like this:
String variable="E898374636475837";
long v=Long.parseLong(variable, 16);
This code throw:
Exception in thread "main" java.lang.NumberFormatException: E898374636475837
at java.lang.Long.parseLong(Long.java:322)
at q.main(q.java:6)
The problem is with numbers greater than
1FFFFFFFFFFFFFFF
Please help me, I nedd parse many DES keys entered by the user keyboard.
Thanks.

Try this out,
System.out.println(new java.math.BigInteger("E898374636475837", 16));
Hope this works out for you.
Regards
Omer

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Parsing long numbers very huge

Hi all:
How i can parse a long number like this:
String variable="E898374636475837";
long v=Long.parseLong(variable);
This code throw:
Exception in thread "main" java.lang.NumberFormatException: E898374636475837
at java.lang.Long.parseLong(Long.java:310)
at java.lang.Long.parseLong(Long.java:363)
at q.main(q.java:6)
Please help me, I nedd parse many DES keys entered by the user keyboard.
Thanks.

The long number is very huge.
Long number can store only 2 to the power 64 's
value.But not that huge.... The range of long is from -2^63 to 2^63-1. The value here is not in that range.
You'll need the class java.math.BigInteger to represent that value and it also has parsing methods of it's own; check the docs.

Adding, subtracting, multiplying, and dividing huge numbers.

Hi all,
I was wondering how huge numbers that can�ft be satisfied with type long can be added together. And also subtracted, multiplied, and divided. Numbers with 100 digits or so. I am playing with an idea of passing them in as strings. Then string��array or linked list (probably not the smoothest one). But I'm not sure whether this is the way to go.
Any suggestions?
Thanks a lot.

Jos... shouldn't you be out drinking Grolsch this
time on a Sat night? (early still where I am,
though).Nope, we just got back from a visit to some friends of ours and I just
checked in a couple of minutes ago. I'll have one last jenever and I'll
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kind regards,
Jos
ps. I never drink Grolsch after dinner; it's jenever time then ... ;-)

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First of all, there is no need to put the entire text of your post into the title of your thread.
Next, does your daughter have an iPhone? Do her friends have iPhones? If the answer to both questions is "yes", then it is possible she is not texting them, but using iMessage to communicate with them. iMessages will not show up in the texting traffic on a line as they are not texts, but messages sent thru Apple's servers.
For all "texts" to show up in the texting activity of an iPhone, you must disable iMessage on the device. Any messages sent as iMessages(blue bubbles around the text) on an iPhone will not show up in any texting activity.

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Rodeo,
I received the file you emailed. Without opening the file:
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James Ward4posted this yesterday.
http://www.tuaw.com/2014/09/16/be-aware-be-careful-be-prepared-for-icloud-drive/
quinn

I am using Numbers on my iPhone5 and cannot get the app to do a simple (SUM) calculation. It shows the formula correctly in the cell, but all I get for my long list of numbers to add is 0. How can I get this to work?

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Oaky, at least we got that far. Next step is to determine if all those "numbers" are really numbers. Changing the format to "number" doesn't necessarily change the string to a number. The string has to be in the form of a number. Some may appear to you and me as numbers but will not turn into "numbers" when you change the formatting from Text to Number. Unless you've manually formatted the cells to be right justified, one way to tell if it is text or a number is the justification. Text will be justified to the left, numbers will be justified to the right.
Here are some that will remain as strings:
+123
123 with a space after it.
.123

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:)

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I am a student with a question about how Java handles very large numbers. Regarding this from our teacher: "...the program produces values that
are larger than Java can represent and the obvious way to test their size does not
work. That means that a test that uses >= rather than < won?t work properly, and you
will have to devise something else..." I am wondering about the semantics of that statement.
Does Java "know" the number in order to use it in other types of mathematical expressions, or does Java "see" the value only as gibberish?
I am waiting on a response from the teacher on whether we are allowed to use BigInteger and the like, BTW. As the given program stands, double is used. Thanks for any help understanding this issue!

You're gonna love this one...
package forums;
class IntegerOverflowTesterator
public static void main(String[] args) {
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This is decent summary of the underlying problem http://mindprod.com/jgloss/gotchas.html#OVERFLOW.
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Parsing hexadecimal strings

im an fresher currently in a project on secure hash algorithm
my project is stopped due to certain reasons , further which i cannot proceed.
i woud be grateful to u if some one provides solution to my problem.
int a = (word[i] << 1) or (word[i] >> 32-n)
word is an array that consist of hexadecimal string .
the thing here is for instance , 0x2g46778, 2g46778
when u print(both, individually) using System.out.println yields different results.
the scenario is i have derived word array that consist only number without 0x extension ,
but result yielded is wrong as for the reason mentioned above.
but when i take an array that consist of 0x as string and concat it with every element of word array i get the full number (i.e 0x 2hg4kr7)
again the problem is parsing the hexadecimal string(with ox as extension)
Query:
please tell me whether their is any way for parsing hexadecimal string as ox is not recognized.
or
how to proceed with it such that my string get parsed.
thank u
sincerly
hari hara ganesh dharmarajan
india`

Could you post some sample input and desired output for your project?
What is an array of hex string?
Is it String[] with the contents of each string consisting of the char a-f and 0-9? Eg String[] xx = new String[] {"1234", abcd"};
What does "parsing a hex string" mean? Give an example please.

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Hello,
I have to parse a long file....the concept of that file it is that there are several billings included, and for each billing it is separated for an special escape character ( FF character , i tihnk it tells the printer to skip page )
Well, I have some java experience , but I dont know regular expressions in java...I need the following for instance:
COORSERPARK LTDA                                        NIT :      800,215,065-4
                                                            FACTURA DE VENTA No.   : F-003-00000060466
                       SANTAFE DE BOGOTA, FEBRERO    01 DE 2008
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Also for instance a line like this
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It may seem trivial, but if strings are fixed (FACTURA DE VENTA No. will always be the same and the same for PLAN), I would search for those strings (first by reading all document into a string variable) inside the document, and having the position of the end of that string, go on parsing ignoring white spaces and storing all "non-space" data found (if you are looking for a price, you know it won't have spaces, or if you're looking for a code you also know it would have no spaces or maybe it would have fixed length)...I know it's dirty but it would surely work.
I repeat, it's not smart but it will work with few code (I suppose :) ).
P.S. I hate regular expressions :)
Edited by: scuffia on Jan 31, 2008 9:27 PM

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Yolanda,
Yolanda Arroyo wrote:
Hi folks,
I have problems with my Tuxedo cofiguration using domains.
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I think that you are confusing the purpose of the 2 config files, ubbconfig and
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You should configure you application servers in the ubbconfig file. They
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One you have done this, you have a single domain.
To extend this to talk to external domains, now you need to configure the gateways.
Add a new server group to your ubbconfig and configure the domain gateway
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Need help parsing a long and passing the value.

I'm doing Cattle Drve 4b on javaranch.com (http://www.javaranch.com/say.jsp) and I need a bit of help.
I want to pass the reference of my num value to several small methods to work out the value printed. Here's the original code I did from 4a:
public class Say{
public static void main(String[]args){
int num = Integer.parseInt(args[0]); // parse argument from command line
String array[] ={"Zero", "One", "Two", "Three", "four", "five", "six","seven","eight",
           "nine","ten","eleven","twelve","thirteen","fourteen","fifteen","sixteen",
           "seventeen","eighteen","nineteen","twenty","thirty","fourty","fifty",
           "sixty","seventy","eighty","ninety"};     //initialize the array
//start check for value
if(num<21)
System.out.println("\n" + array[num]);
                                        // \n is added before
else if(num<30)                                   // each result for a
System.out.println("\n" + array[20]+ "-" + array[(num-20)]);     // cleaner output
else if(num<40)
System.out.println("\n" + array[21]+ "-" + array[(num-30)]);
else if(num<50)
System.out.println("\n" + array[22]+ "-" + array[(num-40)]);
else if(num<60)
System.out.println("\n" + array[23]+ "-" + array[(num-50)]);
else if(num<70)
System.out.println("\n" + array[24]+ "-" + array[(num-60)]);
else if(num<80)
System.out.println("\n" + array[25]+ "-" + array[(num-70)]);
else if(num<90)
System.out.println("\n" + array[26]+ "-" + array[(num-80)]);
else if(num<100)
System.out.println("\n" + array[27]+ "-" + array[(num-90)]);
//endFor 4b I need to be able to print out values in the billions, so I was going to create a few methods to keep it clean like so:
public class billion (long (int num)
{ if( num<9 billion)
     num-= 8 billion
System.out.print("eight billion ");
else if(num<8 billion){
num-= 7 billion
System.out.print("seven billion ");
....etc
return num;
public class million...
public class thousand...
etc.And the current main section will be moved into a new "tens" class.
I'm running into two problems though.
1. How do you parse a long? I know integers are like so:
int num = Integer.parseInt(args[0]); are longs the same?
like:
long num = Long.parseLong(args[0L])if not, how can I do it?
2. how do I properly pass num to all the methods? I'm going to make num a public int and make the methods public because that seems simplest, but can I pass num to the method and then return the new value of num back to main?
BTW, I'll be removing the carriage return from the beginning of the "tens" class when all is said and done so the results don't end up printing on multiple lines.
Thanks in advance everyone.

The L suffix is used to identify a Long literal.
The index of the args[] array does not need to be specified as a Long.
Solong num = Long.parseLong(args[0]);will suffice. You might want to put that in a try/catch block to catch the NumberFormatException that will be thrown if args[0] cannot be parsed to a long value.
Various ways to update the value of num in the methods of the same class:
Simplest of all: declare num as an instance variable. The methods simply access and assign its value.
Other ways:
-- pass num as a parameter to the method.
-- return the value of num from the method (provided the method doesn't have to return any other value)
-- Have a getNum() method return the value of num
-- Have setNum() method to update the value of num
db
What's that line? public class billion (long (int num)edit Typos, typos...
Also, the set/get approach with public access is the preferred method when used in the methods of another class.
Don't forget that the other class has to know whose set/get methods to call.
Message was edited by:
Darryl.Burke

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Parsing hexadecimal long very huge numbers

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