Please check the Code snippet and detail the difference

Question

Please go through the two code snippets given below...
Can some one please let me know if using generics is a better way to denote the signature and if yes, why is it so?
Thank you
Two classes:
class SimpleStr {
     String name = "SimpleStr";
     public SimpleStr(String name) {
          this.name = name;
     public String getName() {
          return this.name;
     public String toString() {
          return getName();
class MySimpleStr extends SimpleStr {
     String name = "MySimpleStr";
     public MySimpleStr(String name) {
          super(name);
          this.name = name;
     public String getName() {
          return this.name;
     public String toString() {
          return getName();
Code Snippet 1:
class AnotherSimpleStr {
     public <S extends SimpleStr>S getInfo() {
          return (S)new MySimpleStr("val3");
Code Snippet 2:
class AnotherSimpleStr {
     public SimpleStr getInfo() {
          return new MySimpleStr("val3");
}

Answer 1

Also, please see the code below, the getInfo() method is not taking care of Type safety right??!!!!
class AnotherSimpleStr {
     public <S extends SimpleStr>S getInfo() {
          return (S)new Object();
     public <S extends SimpleStr>S getInfoAgain(Class<S> cls) {
          return (S)new MySimpleStr("Val");
}