Please explain the code below

Question

What will be the output of the following code? Can I get some detail explanation?
class A{
    void show(){
        System.out.println("A");
interface my{
    public void show();
class B extends A{
   B(my m){
       m.show();
    public void show(){
        System.out.println("B");
public class test implements my{
    public void show(){
        System.out.println("test");
    public static void main(String args[]){
      test t=new test();
      B b=new B(t);
      b.show();
}Thanks

Answer 1

What will be the output of the following code? Can I
get some detail explanation?Well, I guess you were not able to figure out HOW you got that output. Should have been a li'l more clear in your question. Never mind now... here is my understanding of the code.
1) The program starts at main()
2) creates an object for test called t (does nothing more than this since it does not have a constructor defined by you!!)
3)creates an object for B whose constructor takes an object argument of type my. you send t becuase test implements my.
4)calls the show method of m in the constructor.
5)now, where is the definition of show() for m? Its in test. So now, that show() is executed and hence "test" is printed first.
6)all done, it comes back to the main() to go to the next statement.
7)calls the show() of b.
8)this version of show asks to print "B" and hence the output.
Was this detailed explanation enough? I hope so... ;-)