Please help me in understanding the following code.
public static void main(String args[]){
int x=0,c=0;
for(int i=0;i<3;i++)
x = x + x++;
System.out.println(x);
why this program always prints zero(0) as output. I am not able to understand the execution sequence of it.
bkyadav wrote:
at certain point of time in porgram
(x++) should be treated as x = x+1; but that is not happening.Here's the rule : you have to proceed the expression from left to right.
For example :
int x = 8;
x = x + ++x; // x = 8 + 9 = 17
int x = 8;
x = x + x++; // x = 8 + 8 = 16
int x = 8;
x = x + --x; // x = 8 + 7 = 15Also, in the for statement of your example :
for(int i=0;i<3;i++)the value of i+ is first tested before being incremented for the next iteration otherwise the test on value of i+ = 0 would have been skipped.
Similar Messages
-
Please help me to modify the following code !
SELECT VTEXT FROM TVKGGT
INTO CORRESPONDING FIELDS OF TABLE t_tvkggt
WHERE KDKGR = itab-kdkg1.
read table t_tvkggt with key kdkgr = t_tvkggt-kdkgr binary search.
itab-vtext2 = t_tvkggt-vtext.
I am getting corresponding values of vtext where itab has
values of kdkgr and also doesnt have any values of kakgr.
how to remove those values of vtext which doesnt have any value for kdkgr.Hi,
select * from mara
into table i_tab
where matnr = 'ACC CABLE'.
loop at i_tab where bstme NE ' ' .
endloop.
Check out with this one and inside loop ,
you can transfer only those records which have bstme value.
Apply for you case.
Reward if helpful/.
Thanks,
Madhura
Edited by: Madhura Nadgauda on Jan 17, 2008 7:19 AM -
Please help me in understanding the EDIFACT D96A format for INVOICE
Hi,
Im doing an INVOICE02 IDOC to EDIFACT D96A INVOIC scenario. Im new to EDI.
Pls Pls Pls Pls kindly help me in understanding the following EDIFACT D96A file.
UNBUNOA:35410033000055:145400110000009:14070612:085511137INV96A+EANCOM1'
UNH1INVOIC:D:96A:UN:EAN008'
BGM3805010237529+9'
DTM+137:200706120000:203'
DTM+35:20070612:102'
DTM+454:20070612:102'
RFF+ON:32210'
DTM+171:20070612:102'
RFF+DQ:000030585715'
DTM+171:20070612:102'
NADSU5410148000001::9+BVBA Unilever Belgium SPRLBl.De L?'Humanité 292 292Bruxelles1190BE'
RFF+VA:BE438390312'
RFF+ARA:0438390312'
NADBY5400110000009::9+D.L.L.RUE OSSEGHEM 53-MOLENBEEKMOLENBEEK-SAINT-JEAN1080BE'
NADDP5400110000009::9+D.L.L.RUE OSSEGHEM 53-MOLENBEEKMOLENBEEK-SAINT-JEAN1080BE'
NADIV5400110000009::9+DELHAIZE FRS. CENTRALESRUE OSSEGHEM , 53BRUSSEL-MOLENBEEK1080BE'
RFF+VA:BE402206045'
RFF+ARA:0402206045'
CUX+2:EUR:4'
LIN10+8000920900987:EN'
PIA1000000000019009801:SA'
IMDF+IN:::IGLO POELEE LEGUMES CHAMPIGNONS 6X8'
QTY+47:81'
QTY+46:81'
MOA+203:1584.4'
PRI+AAA:19.56'
PRI+AAB:21.24'
TAX7VAT+++:::6.000'
MOA+125:1584.4'
ALCA++1'
PCD+1:0:1'
ALCA++1'
PCD+1:1.97:1'
ALCA++1'
PCD+1:1.96:1'
LIN20+5410148126459:EN'
PIA1000000000011264501:SA'
IMDF+IN:::Epinards hachis en portions '
QTY+47:112'
QTY+46:112'
MOA+203:1061.01'
PRI+AAA:9.47'
PRI+AAB:10.96'
TAX7VAT+++:::6.000'
MOA+125:1061.01'
ALCA++1'
PCD+1:0:1'
ALCA++1'
PCD+1:1.97:1'
ALCA++1'
PCD+1:1.96:1'
LIN40+5410148013452:EN'
PIA1000000000010134500:SA'
IMDF+IN:::15 Fish Sticks Colin d?'Alaska '
QTY+47:256'
QTY+46:256'
MOA+203:4937.63'
PRI+AAA:19.29'
PRI+AAB:20.16'
TAX7VAT+++:::6.000'
MOA+125:4937.63'
ALCA++1'
PCD+1:0:1'
ALCA++1'
PCD+1:1.97:1'
LIN50+5414807999958:EN'
PIA1000000000019999501:SA'
IMDF+IN:::Iglo Poisson Pané Epinards 7X400g'
QTY+47:180'
QTY+46:180'
MOA+203:4160.31'
PRI+AAA:23.11'
PRI+AAB:24.08'
TAX7VAT+++:::6.000'
MOA+125:4160.31'
ALCA++1'
PCD+1:0:1'
ALCA++1'
PCD+1:1.97:1'
LIN60+5410148120952:EN'
PIA1000000000011209501:SA'
IMDF+IN:::Epinards Crhme en Portions '
QTY+47:112'
QTY+46:112'
MOA+203:1594.69'
PRI+AAA:14.24'
PRI+AAB:15.92'
TAX7VAT+++:::6.000'
MOA+125:1594.69'
ALCA++1'
PCD+1:0:1'
ALCA++1'
PCD+1:1.97:1'
ALCA++1'
PCD+1:1.96:1'
LIN70+5410148124158:EN'
PIA1000000000011241503:SA'
IMDF+IN:::EPINARDS HACHES EN PORTIONS 450G'
QTY+47:144'
QTY+46:144'
MOA+203:938.01'
PRI+AAA:6.51'
PRI+AAB:7.44'
TAX7VAT+++:::6.000'
MOA+125:938.01'
ALCA++1'
PCD+1:0:1'
ALCA++1'
PCD+1:1.97:1'
ALCA++1'
PCD+1:1.96:1'
LIN120+5410148016729:EN'
PIA1000000000010167201:SA'
IMDF+IN:::Macaroni Fromage/Jambon '
QTY+47:260'
QTY+46:260'
MOA+203:4337.55'
PRI+AAA:16.68'
PRI+AAB:17.58'
TAX7VAT+++:::6.000'
MOA+125:4337.55'
ALCA++1'
PCD+1:0:1'
ALCA++1'
PCD+1:1.97:1'
LIN130+5410148441255:EN'
PIA1000000000014412503:SA'
IMDF+IN:::CHOUX ROUGES AUX POMMES 450G'
QTY+47:144'
QTY+46:144'
MOA+203:1756.99'
PRI+AAA:12.2'
PRI+AAB:13.36'
TAX7VAT+++:::6.000'
MOA+125:1756.99'
ALCA++1'
PCD+1:0:1'
ALCA++1'
PCD+1:1.97:1'
ALCA++1'
PCD+1:1.96:1'
LIN140+5410148017702:EN'
PIA1000000000010177001:SA'
IMDF+IN:::Frit?'Kot 1'
QTY+47:60'
QTY+46:60'
MOA+203:1102.6'
PRI+AAA:18.38'
PRI+AAB:22'
TAX7VAT+++:::6.000'
MOA+125:1102.6'
ALCA++1'
PCD+1:0:1'
ALCA++1'
PCD+1:1.97:1'
ALCA++1'
PCD+1:4.9:1'
LIN180+8000920801796:EN'
PIA1000000000018017901:SA'
IMDF+IN:::EPINARDS EN BRANCHES 10 X 450'
QTY+47:190'
QTY+46:190'
MOA+203:2204.2'
PRI+AAA:11.6'
PRI+AAB:12.9'
TAX7VAT+++:::6.000'
MOA+125:2204.2'
ALCA++1'
PCD+1:0:1'
ALCA++1'
PCD+1:1.97:1'
ALCA++1'
PCD+1:1.96:1'
LIN200+5410148014268:EN'
PIA1000000000010142602:SA'
IMDF+IN:::PETITS POIS EXTRA FINS 450G'
QTY+47:238'
QTY+46:238'
MOA+203:1999.6'
PRI+AAA:8.4'
PRI+AAB:9.24'
TAX7VAT+++:::6.000'
MOA+125:1999.6'
ALCA++1'
PCD+1:0:1'
ALCA++1'
PCD+1:1.97:1'
ALCA++1'
PCD+1:1.96:1'
LIN230+8000920807248:EN'
PIA1000000000018072403:SA'
IMDF+IN:::IGLO POUL ET PENNE AUX LEG.SOLEI. 6'
QTY+47:99'
QTY+46:99'
MOA+203:1727.54'
PRI+AAA:17.45'
PRI+AAB:18.3'
TAX7VAT+++:::6.000'
MOA+125:1727.54'
ALCA++1'
PCD+1:0:1'
ALCA++1'
PCD+1:1.97:1'
UNS+S'
CNT+2:12'
MOA+124:1644.27'
MOA+86:29048.8'
MOA+79:27404.53'
MOA+125:27404.53'
TAX7VAT++:::6.000S'
MOA+125:27404.50'
MOA+124:1644.27'
UNT2121'
UNZ111137'
Advance appreciations,
Ram.Its very simple:
UNB-segment : Interchange Header
S001 SYNTAX IDENTIFIER
0001 Syntax Identifier UNOA
0002 Syntax version number 2
S002 INTERCHANGE RECIPIENT
0004 Sender Identification 8711382000091 (= GLN Code Tilburg)
0007 Identification Code Qualifier 14
S003 INTERCHANGE SENDER
0004 Recipient Identification 8711700400008(= GLN Code Unilever)
0007 Identification Code Qualifier 14
S004 DATE/TIME OF PREPARATION
0017 Date YYMMDD
0019 Time HHMM
0020 INTERCHANGE CTRL REF. Unique message reference number
0026 APPLICATION REFERENCE WMS0330
UNH-segment: Message header
0062 MESSAGE REFERENCE NUMBER Unique sequence numbe within UNB
S009 MESSAGE IDENTIFIER
0065 Message type identifier INVRPT
0052 Message type version number D
0054 Message type release number 96A
0051 Controlling agency EN
0057 Association assigned code EAN004
BGM-segment: Beginning of message
C002 DOCUMENT/MESSAGE NAME
1001 Document/message name, coded 35 (= Inventory report)
3055 Code list responsible agency, coded 9 (= EAN)
1004 DOCUMENT/MESSAGE NUMBER Unique Number assigned by CS (= Date/Time CCYYMMDDHHMMSS)
1225 MESSAGE FUNCTION, CODED 9 (= Original)
DTM-segment: Date/time/period
C507 DATE/TIME/PERIOD
2005 Date/time/period qualifier 137 (=Document/message date/time)
2380 Date/time/period Document date
2379 Date/time/period format qualifier 102 (= CCYYMMDD)
RFF-segment: Reference
C506 REFERENCE
1153 Reference code qualifier ON (= Order number)
1154 Reference identifier Agreement number
NAD-segment: Name and address
3035 PARTY QUALIFIER GY (= Inventory reporting party = CS)
GM (= Inventory controller = XYZ)
C082 PARTY IDENTIFICATION DETAILS
3039 Party id. identification GLN code
3055 Code list responsible agency, coded 9 (= EAN)
LIN-segment: Line item
1082 LINE ITEM NUMBER Unique Line Number
C212 ITEM NUMBER IDENTIFICATION
7140 Item number EAN Material code
7143 Item number type, coded EN (= EAN)
PIA-segment: Additional Product Information
4347 PRODUCT ID FUNCTION IDENTIFIER "1"(= Additional Information)
C212 ITEM NUMBER IDENTIFICATION
7140 Item number Promotional Variant
7143 Item number type, coded "PV (= Promotional variant)
QTY-segment: Quantity
C186 QUANTITY DETAILS
6063 Quantity qualifier 12 (= Despatch quantity)
6060 Quantity Number of stock units
PRI: Represent price
TAX: represent tax.
Try to go to the below website where you will able to get the information regarding all the sgements and elements of Invocie.
http://www.edifactory.de/messages.php?s=D96A
Also refer the below link for EDI understanding:
http://www.gxs.com/pdfs/Tutorial/Tutor_EDIFACT_GXS.pdf
Thnx
Chirag Gohil -
I want to check the main diffrence in Pop up block enabled and disabled.But,i don't get any difference.Would u please help me to understand the difference using one practical example of website
Here's two popup test sites.
http://www.kephyr.com/popupkillertest/test/index.html
http://www.popuptest.com/ -
Please help me out with the function code of print option in module pool
please help me out with the function code of print option in module pool, along with CASE condition.
regards,
asifHi
you can use the Function module
CALL FUNCTION 'GET_PRINT_PARAMETERS'
EXPORTING
destination = 'LP01' "'Printer name
list_name = 'TEST'
list_text = 'SUBMIT ... TO SAP-SPOOL'
immediately = ' '
line_size = '2000'
no_dialog = 'X' "pass space to Pop screen for Print option
IMPORTING
out_parameters = wa_pri_params
valid = w_valid.
"next call below things
NEW-PAGE PRINT ON NO DIALOG PARAMETERS wa_pri_params.
"and try to Print the values inside the new-page
NEW-PAGE PRINT OFF.
Prabhudas -
Please help me to explain the following method
I saw the following code in a source file
//This method actually does the code generation
//Returns an instance of the generated class.
protected Class generateWrapperClass()
throws JasperGenerationError,ServletException
verify();
protected void verify()
I can't understand how does method generateWrapperClass() works.
verify() is of type void and the method generateWrapperClass() has no return value.
Can anyone help to explain it to me?
ThanksI can't understand how does method
generateWrapperClass() works.
verify() is of type void and the method
generateWrapperClass() has no return value.It does have a return type, it returns a Class. Your confusing the keyword "class" with the Object "Class". Java is case sensitive so class and Class are 2 different things. -
Please help me to find the sample code and schema for GetDBDateTime.zip fil
Please help me to find the GetDBDateTime.zip and Guest_Book.zip files.
Tks!Does this Help?
http://www.oracle.com/technology/sample_code/products/ias/files/psp/GetDBDateTime/Readme.html
Did you install Oracle9iAS ? -
Help needed in understanding the Java code.
Hi All,
I have recently started learning the Java language. I came across this example and had a problem in understanding the output of the program. I could follow that if the continue statement is present in the below program the output is "Found 9 p's in the string" . But if the continue statement is removed I could not understand why the output would be "Found 35 p's in the string" .Is it because of the spaces and characters other than p... (eter ier icked a eck of ickled eers)
Example-----------------------
The continue statement skips the current iteration of a for, while , or do-while loop. The unlabeled form skips to the end of the innermost loop's body and evaluates the boolean expression that controls the loop. The following program, ContinueDemo , steps through a String, counting the occurences of the letter "p". If the current character is not a p, the continue statement skips the rest of the loop and proceeds to the next character. If it is a "p", the program increments the letter count.
class ContinueDemo {
public static void main(String[] args) {
String searchMe
= "peter piper picked a " +
"peck of pickled peppers";
int max = searchMe.length();
int numPs = 0;
for (int i = 0; i < max; i++) {
// interested only in p's
if (searchMe.charAt(i) != 'p')
continue;
// process p's
numPs++;
System.out.println("Found " +
numPs + " p's in the string.");
Here is the output of this program:
Found 9 p's in the string.
To see this effect more clearly, try removing the continue statement and recompiling. When you run the program again, the count will be wrong, saying that it found 35 p's instead of 9.The answer is already in your example - "The unlabeled form skips to the end of the innermost loop's body and evaluates the boolean expression that controls the loop."
It unloads the current loop iteration when condition is matching. Loop is again starting from boolean expression inside loop declaration.
Java Programming - java forum -
HI,
I am using this for the first time. I have downloaded a Adobe E-book from my library. I installed Digital Edition 4 and i keep on getting this message when i try to get the book from my pc downloads. Please help me overcome this issue
regards,
kapil desaiPlease try de-authorizing and authorizing again.
Steps to De-authorize
1) Switch to Library Mode by clicking Library button
2) Select menu item Help--> Erase Authorization or Press Ctrl+Shift+D
3) Click Erase button to De-authorize
Steps to Authorize
1) Launch ADE
2) Switch to Library Mode by clicking Library button (if you are in Reading Mode)
3) Select menu item Help-->Authorize Computer or Press Ctrl+Shift+U
4) Enter the valid credential to Authorize
Hope this solves your problem. -
Yesterday the time capsule light went off. All efforts to put it on again failed. All electric connections are in good order and working perfectly. Please help me.
Hi again,
I called them this morning. Admits my allergies and sneezing I was able to talk to them.
They will replace it with basically no questions asked.
I guess also having a MBP under AppleCare also helped too as the case is registered under that.
They gave me a few options.
The could take my credit card number as insurance and send me a new one and them I send them my dead one back, or I could take it into an Apple Store for a replacement there. The problem is that I have data on there that I want to maintain, so they said take it to the Apple Store or an Apple Service provider and they would handle the transfer.
I don't have an Apple Store in my city, but have a Service Provider that I know that could do the transfer for me, but I kinda want to do it at the Apple Store because maybe then they would give me a new one instead of another w year tombstone.
So I need to weigh my options.
I'll let you know further what happens.
P.S. my serial number was not in the range listed, but that didn't seem to make a difference. I think the key is to be courteous, respectful and friendly. -
Please help me by solving the following query
hi download the image from the above link and here i want latest dosi line count.....
Please help meI think you don't need a plsql for this purpose ... you can find the sub total & final total in the query itself like
select
DOSI,
ELEMENT_TYPE,
SUM(USED) USED
from
DOEMS_LICENSE_SUMMARY
where
DOSI in (DOSILIST)
GROUP BY
rollup(ELEMENT_TYPE, DOSI) ** duplicate** -
In SE30 hit list, please help me to understand the GROSS and the NET column
Here a line from the Hit List :
Call = Perform TRANSFER_TO_UNIX
Number = 6
Gross = 5662 microsecond
Net = 810 microseconds
The whole program execution takes 1.705.253 microseconds.
Can somebody explain me the meaning of the GROSS and the NET time using this example ?
The routine TRANSFER_TO_UNIX has been executed 6 times. That is clear.
Is the gross time the total time required for a call or for 6 calls ?
=> following documentation , "the gross time is the total time required for A call. This includes the runtime of all modularization units and abap statement called by the subject."
=> but following a blog read on this forum, the gross time is the total times, not the times per execution.
That confused me very much .
Can somebody clarify that for me ?
Also, what I don't understand at all is the NET time
=> following documentation, the net time is the gross time less the time required for modularization units (MODULE, PERFORM, CALL FUNCTION, CALL SCREEN, CALL TRANSACTION, CALL METHOD, CALL DIALOG, SUBMIT), and for the ABAP statements listed separately. For statements such as APPEND, the gross time is the same as the net time.
If the gross and net runtimes of a call are different, the call must either contain further calls or modularization units
Here is the code of the routine :
add 1 to w_nb_ok.
clear l_record.
l_record-gpart = <f_vkont>-gpart.
l_record-vkont = <f_vkont>-vkont.
l_record-mahnv = <f_vkont>-mahnv.
l_record-zzfbdate = <f_vkont>-zzfbdate.
l_record-zzcastatus = <f_vkont>-zzcastatus.
l_record-ktokl = <f_vkont>-ktokl.
l_record-regiogr_ca_b = <f_vkont>-regiogr_ca_b.
l_record-mahnv_new = <f_vkont>-mahnv_new.
l_record-zzfbdate_new = <f_vkont>-zzfbdate_new.
l_record-zzfbdate_upd = <f_vkont>-zzfbdate_upd.
l_record-zzcastatus_new = <f_vkont>-zzcastatus_new.
l_record-zzcastatus_upd = <f_vkont>-zzcastatus_upd.
transfer l_record to w_output_file.
I
Thanks in advance
Marie> the call must either contain further calls or modularization units,
yes
Check in your measurment setting what is traced separately, for an exercise you can switch off everything besides the call function, methods and forms,
then you will see gross = net if there no other call inside.
But the recommended setting is described in the blog.
Note, the sum of all net times is the total runtime, and the maximum of the gross times should be the same. Unfortunately there are slight deviations in the gross
times and the displayed total time in the SE30 is taken from the gross times.
Siegfried -
Need explanation of the following code
HI All,
I need your help on explanation of the following code :
what I don't understand is how it route the request (all the benefit of the replace statement )
If the input is /scarr/LH/SPFLI/402
how he know to route it and
what is the benefit for using the wild card and the concatenate CONCATENATE '^' lv_verif_pattern '$'
Edited by: James Herb on Apr 13, 2010 9:53 AM
Edited by: James Herb on Apr 13, 2010 9:53 AMDATA: lt_routing_tab TYPE z_resource_routing_tab,
CONSTANTS: param_wildcard TYPE string VALUE '([^/])*'.
FIELD-SYMBOLS: <ls_routing> LIKE LINE OF lt_routing_tab.
CALL METHOD get_routing
RECEIVING
rt_routing_tab = lt_routing_tab.
LOOP AT lt_routing_tab ASSIGNING <ls_routing>.
* replace all parameters placeholders by regex
lv_verif_pattern = <ls_routing>-url_info.
lv_signature = <ls_routing>-url_info.
REPLACE ALL OCCURRENCES OF REGEX '\{([A-Z]*[_]*[a-z]*[0-9]*)*\}'
IN lv_verif_pattern WITH param_wildcard.
CONCATENATE '^' lv_verif_pattern '$' INTO lv_verif_pattern.
* check if pattern matches current entry
FIND ALL OCCURRENCES OF REGEX lv_verif_pattern
IN url_info MATCH COUNT lv_count.
* pattern matched
IF lv_count > 0.
* get controller class name
lv_controller_name = <ls_routing>-handler_class.
ls_class-clsname = lv_controller_name.
* check if class exists
* class found
IF sy-subrc = 0.
* create controller
CREATE OBJECT eo_controller TYPE (lv_controller_name).
* create parameter table
SHIFT lv_verif_pattern RIGHT DELETING TRAILING '$'.
SHIFT lv_verif_pattern LEFT DELETING LEADING ' ^'.
SPLIT lv_verif_pattern AT param_wildcard INTO TABLE lt_url_parts.
lv_url_info = url_info.
LOOP AT lt_url_parts INTO lv_url_part.
SHIFT lv_signature LEFT DELETING LEADING lv_url_part.
SHIFT lv_signature LEFT DELETING LEADING '{'.
SHIFT lv_url_info LEFT DELETING LEADING lv_url_part.
Edited by: James Herb on Apr 13, 2010 9:56 AM -
Please help me to build the logic
Hi All,
Please help me to implement the following logic.
The conditional statements should not only be executed in sequence, but also if any of them are true they should not be overridden by any subsequent conditional statements being true.
When actual effort Accepted or Rejected for AST proposals and calculate a flag for “enhance to AST guideline” = Y/N as follows for each employee and display at the employee level
1)If AST eligibility = N AND proposed AST % >0, then “N”
2)Else If AST eligibility = N AND proposed AST % = 0 then “n/a”
3)Else If AST eligibility = Y AND Act Rank = 3 AND proposed AST = 0 then “Y”
4)Else If AST eligibility = Y AND Act Rank = 3 AND proposed AST >0 then “N”
5)Else If AST eligibility = Y AND Act Rank = 2 AND proposed AST = 0 then “Y”
6)Else If AST eligibility = Y AND AST % is greater than or equal to the AST guideline minimum AND less than or equal to the AST guideline maximum, then “Y”
7)Else If AST eligibility = Y AND AST % is less than the minimum guideline OR greater than the maximum guideline, then “N”
I tried the following code but I am not getting the expected result .
Could you Please help me to build the logic.
Your earliest response is very helpful to me.
if (upper(P_stat)='ACCEPTED' or upper(P_stat) like 'REJECTED%') then
else if NVL(P_elgi,'N') <> 'Y' AND P_prop > '0' then
P_flag := 'N';
else if(NVL(P_elgi,'N') <> 'Y' AND P_prop = '0') then
P_flag := 'N/A';
else if ((NVL(P_elgi,'N')='Y') AND P_rank = '3' AND P_prop = '0') then
P_flag := 'Y';
else if((NVL(P_elgi,'N')='Y') AND P_rank = '3' AND P_prop > '0') then
P_flag := 'N';
else if((NVL(P_elgi,'N')='Y') AND P_rank = '2' AND P_prop = '0') then
P_flag := 'Y';
Else if (P_prop >=ast_min_guide AND P_prop <= ast_max_guide ) then
P_flag := 'Y';
else
((P_prop < ast_min_guide) OR (P_prop > ast_max_guide)) then
P_flag := 'N';
end if;
end if;Thanks for ur quick responce .
When actual effort Accepted or Rejected for AST proposals and calculate a flag for “enhance to AST guideline” = Y/N
Once the above condition is satisfied we have to check for remaing conditions
if (upper(P_stat)='ACCEPTED' or upper(P_stat) like 'REJECTED%') then
once it is satisfies then we have to go for remaing conditions.
how can we do it in CASE statement.
1)If AST eligibility = N AND proposed AST % >0, then “N”
2)Else If AST eligibility = N AND proposed AST % = 0 then “n/a”
3)Else If AST eligibility = Y AND Act Rank = 3 AND proposed AST = 0 then “Y”
4)Else If AST eligibility = Y AND Act Rank = 3 AND proposed AST >0 then “N”
5)Else If AST eligibility = Y AND Act Rank = 2 AND proposed AST = 0 then “Y”
6)Else If AST eligibility = Y AND AST % is greater than or equal to the AST guideline minimum AND less than or equal to the AST guideline maximum, then “Y”
7)Else If AST eligibility = Y AND AST % is less than the minimum guideline OR greater than the maximum guideline, then “N”
I tried the following code but I am not getting the expected result . -
Please help me to solve the issue in my query.
Hi All,
Please help me to understand the mistake what i did in below query and help to resolve that.
Actually i am trying to create a query to filter the records from db based on my input parameter.
If my input parameter is 1(@showallrecords) then i need to show all the records which has the IsLatest as 1
If my input parameter is 0(@showallrecords) then i need to show all the records which has the IsLatest as 0
select * from tabel1 INNER JOIN tabel2
ON tabel1.KeyId = tabel2.KeyId
and (@showallrecords = 1 and tabel1.IsLatest = 1 )
and (@showallrecords = 0 and tabel1.IsLatest = 0 )
when i am executing the above query with the parameter @showallrecords = 1 ,db is returning 0 rows.If i am executing the above query after removed the last line and (@showallrecords = 0 and tabel1.IsLatest = 0 ) then records are coming.
i understand that 1=0(last line) and the condition is not true.So its affecting the result.
Please help me to solve this.select * from tabel1 INNER JOIN tabel2
ON tabel1.KeyId = tabel2.KeyId
WHERE (tabel1.IsLatest = @showallrecords Or @showallrecords=0)
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