Problem with regular expression validation

hi,
   how can i validate folder structure
   conditions
     no two forward slashes(/) in a sequence no special characters
    " /w" and   " '/' "
   e:/tomcat/ss/ss.text
       if(valStr.matches("((['/'])[a-zA-Z0-9_]*)")){
                System.out.println("matches");
         else
                System.out.println("notmatches");
this is no correct .
please give me right solution
with regards
ss

hI,
/appmg/dd/
is the paths for solaris( starts with /)
i have to test if it is valid path name or not
with regards
ss

Similar Messages

Problem with Regular Expression

Hi There!!
I have a problem with regular expression. I want to validate that one word and second word are same. For that I have written a regex
Pattern p=Pattern.compile("([a-z][a-zA-Z]*)\\s\1");
Matcher m=p.matcher("nikhil nikhil");
boolean t=m.matches();
if (t)
          System.out.println("There is a match");
     else
          System.out.println("There is no match");
The result I am getting is always "There is no match
Your timely help will be much appreciated.
Regards

Ram wrote:
ErasP wrote:
You are missing a backward slash in the regex
Pattern p = Pattern.compile("([a-z][a-zA-Z]*)\\s\\1");
But this will fail in this case.
Matcher m = p.matcher("Nikhil Nikhil");It is the reason for that *[a-z]*.The OP had [a-z][a-zA-Z]* in his code, so presumably he know what that means and wants that String not to match.

Problems with regular expressions.

Hi all.
I want to substitute within an xml file a string with the following structure:
Referencer="//@Model/@OwnedElement.0/@OwnedElement.1/@OwnedElement.0/@OwnedElement.1/@OwnedElement.33 ..."
where the dots mean that the string within the quotes may be repeated (separated by spaces) many times.
I've tried to match such expression with java regex, with no luck. I thought running
line.contains("Referencer=\"[^\"\\r\\n]*\"");
would return true, but it didn't.
Could anybody point me the right way?.
Thank you all in advance.

Method String.contains() does not take a regular expression - you need to use method String.matches() or class Pattern.
This looks to be a good problem to solve using http://elliotth.blogspot.com/2004/07/java-implementation-of-rubys-gsub.html .

Problem with Regular Expressions

Hi Everyone:
I'm having a problem finding the easiest way to retrieve the replacement text that has been edited to insert back-references from previous matches. For instance,
Lets say I want to use the below regular expression
foo_bar([1-9])_fun
on the search text
foo_bar1_fun
foo_bar2_fun
foo_bar3_fun
and then the replacement text would be
foobar_fun$1
so in the end I would get
foobar_fun1
foobar_fun2
foobar_fun3
What I would like to do is be able to extract the replacement text that has been modified with the back reference matches after I use the Matcher.appendReplacement(stringbuffer, string) method.
So to clarify further, after I find the first match and use the appendReplacement Method, I would like to extract just the replacement that was made to the text, in this case foobar_fun1
Thanks for any help!

Alright, thanks for the reply. I'll try and make this a little more clear
import java.util.regex.Matcher;
import java.util.regex.Pattern;
public class LeClassName {
   public static void main(String[] args) {
      String input = "12341234foo_bar1_fun24342345foo_bar2_fun3522545foo_bar3_fun3423432";
      Pattern pattern = Pattern.compile("foo_bar([1-9])_fun");
      StringBuffer sb = new StringBuffer();
      Matcher matcher = pattern.matcher(input);
      while (matcher.find()) {
         matcher.appendReplacement(sb, "foobar_fun$1");
         //after the first pass through, I would like to extract, foobar_fun1
         // but what is in sb is 12341234foobar_fun1
      System.out.println(sb.toString());
}I did find a solution myself after a bit of thinking but if anyone can come up with a better solution do tell and I'll award that person the answer. Thanks again!
My Solution:
private String fixBackReplacements() throws IndexOutOfBoundsException {
            String currentMatch = this.findMatch.group();
            Pattern temporaryPattern = Pattern.compile(findText);
            Matcher temporaryMatcher = temporaryPattern.matcher(currentMatch);
            return temporaryMatcher.replaceFirst(replaceText);
}

Problem with Regular Expression: XML comment parsing

I have create pattern to parse xml comments:
It works fine but only problem that I have is that it parse only last occurrence :(

sabre150 wrote:
MrJbee wrote:
I have create pattern to parse xml comments:
It works fineI'm surprised it works fine since the ".*" is greedy and will gobble as much as it can and you will end up matching from the start of the first comment to the end of the last comment.
but only problem that I have is that it parse only last occurrence :(Make the ".*" reluctant using ".*?" or, best of all, use an XML parser.
Edited by: sabre150 on Jan 11, 2010 4:00 PMFirst at thanks for reply.
Second it is not so greedy like it look. Because of that:
(?!.*(<!--))I can`t use xml parser since It is only part of my JEditor with styles. I use reg exp to highlight comments, strings, chars and so on....
By the way I try to replace .* => .*? and it is still no results. I mean only last is selected. Maybe you have an example on how to match structure if the do not
have specified substrings.
Something like this:
hello[^(guten tag)]*bye // I know that this is wrongEdited by: MrJbee on Jan 11, 2010 1:22 PM

CFFORM (Flash) Validation with Regular Expressions Not Working

I am having troubles getting regular expression validation to
work in a CFFORM. The below code is an extract of a much larger
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I'd appreciate any comments/info for help on this, have
searched high and low on information to get this working...but no
joy.
The code is:
<cffunction name="checkFieldSet" output="false"
returnType="string">
<cfargument name="fields" type="string" required="true"
hint="Fields to search">
<cfargument name="form" type="string" required="true"
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<cfargument name="ascode" type="string" required="true"
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<cfset var f = "">
<cfsavecontent variable="vcode">
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<cfloop index="f" list="#arguments.fields#">
<cfoutput>
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mx.controls.Alert.show(msg,'Validation Error'); ">
<cfset vcode = vcode & "if(ok) #ascode#">
<cfset vcode =
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<cfreturn vcode>
</cffunction>
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height="600" skin="halosilver" action="new_data.cfc">
<cfformgroup type="panel" label="New Form"
style="background-color:##CCCCCC;">
<cfformgroup type="tabnavigator" id="tabs">
<cfformgroup type="page" label="Step 1">
<cfformgroup type="hbox">
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style="headerHeight: 13;">
<cfformgroup type="vbox">
<cfinput type="text" name="reqName" width="300"
label="First Name:" validate="regular_expression" pattern="[^0-9]"
validateat="onblur" required="yes" message="You must supply your
First Name.">
<cfinput type="text" name="reqLname" width="300"
label="Last Name:" validate="regular_expression" pattern="[^0-9]"
validateat="onblur" required="yes" message="You must supply your
Last Name.">
<cfinput type="text" name="reqEmail" width="300"
label="Email:" validate="email" required="yes" message="You must
supply your email or the address given is in the wrong format.">
<cfinput type="text" name="reqPhone" width="300"
label="Phone Extension:" validate="integer" required="yes"
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</cfformgroup>
</cfformgroup>
</cfformgroup>
<cfformgroup type="horizontal"
style="horizontalAlign:'right';">
<cfinput type="button" width="100" name="cnt_step2"
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quote:
Originally posted by:
Luckbox72
The problem is not the Regex. I have tested 3 or 4 different
versions that all work on the many different test sites. The
problem is it that the validation does not seem to work. I have
changed the patter to only allow NA and I can still type anything
into the text box. Is there some issue with useing Regex as your
validation?
Bear in mind that by default validation does not occur until
the user attempts to submit the form. If you are trying to control
the characters that the user can enter into the textbox, as opposed
to validating what they have entered, you will need to provide your
own javascript validation.

Regular Expression Validator Problem

Hi,
I have a text area that I want to use a regular expression
validator on to verify that one or more 9 char alphanumeric serial
numbers were entered.
<mx:RegExpValidator
source="{entryField}"
property="text"
flags="gi"
expression="{/[a-zA-Z0-9][a-zA-Z0-9][a-zA-Z0-9][a-zA-Z0-9][a-zA-Z0-9][a-zA-Z0-9][a-zA-Z0- 9][a-zA-Z0-9][a-zA-Z0-9](
|,|\\n|\\r|\\t)/}"
valid="handleResult(event)"
invalid="handleResult(event)"
trigger="{entryField}"
triggerEvent="textInput"
/>
//for testing
private function
handleResult(eventObj:ValidationResultEvent):void {
if (eventObj.type == ValidationResultEvent.VALID)
entryField.setStyle("borderColor", "green");
entryField.setStyle("borderThickness", "2");
else
entryField.setStyle("borderColor", "red");
entryField.setStyle("borderThickness", "2");
The problem is the handler function always comes back
invalid, even when it should be valid, such as: 123456789 a12345678
lk231jkop
Can anyone advise where I might be going wrong?
Thanks!

This is weird, i just tried your RegExp using the Adobe's
Live Docs example and it worked perfectly.
Try it at:
http://livedocs.adobe.com/flex/201/langref/mx/validators/RegExpValidator.html
Scroll down to the end of the page, then type your RegExp and
your TestValue and click the Validate button, it works. I am
guessing that maybe it is your
i
flag, try removing it from your validator.
Hope this helps

Urgent!!! Problem in regular expression for matching braces

Hi,
For the example below, can I write a regular expression to store getting key, value pairs.
example: ((abc def) (ghi jkl) (a ((b c) (d e))) (mno pqr) (a ((abc def))))
in the above example
abc is key & def is value
ghi is key & jkl is value
a is key & ((b c) (d e)) is value
and so on.
can anybody pls help me in resolving this problem using regular expressions...
Thanks in advance

"((key1 value1) (key2 value2) (key3 ((key4 value4)
(key5 value5))) (key6 value6) (key7 ((key8 value8)
(key9 value9))))"
I want to write a regular expression in java to parse
the above string and store the result in hash table
as below
key1 value1
key2 value2
key3 ((key4 value4) (key5 value5))
key4 value4
key5 value5
key6 value6
key7 ((key8 value8) (key9 value9))
key8 value8
key9 value9
please let me know, if it is not possible with
regular expressions the effective way of solving itYes, it is possible with a recursive regular expression.
Unfortunately Java does not provide a recursive regular expression construct.
$_ = "((key1 value1) (key2 value2) (key3 ((key4 value4) (key5 value5))) (key6 value6) (key7 ((key8 value8) (key9 value9))))";
my $paren;
   $paren = qr/
           [^()]+ # Not parens
         |
           (??{ $paren }) # Another balanced group (not interpolated yet)
    /x;
my $r = qr/^(.*?)$(\w+?) (\w+?|(??{$paren}))$\s*(.*?)$/;
while ($_) {
     match()
# operates on $_
sub match {
     my @v;
     @v = m/$r/;
     if (defined $v[3]) {
          $_ = $v[2];
          while (/\(/) {
               match();
          print "\"",$v[1],"\" \"",$v[2],"\"";
          $_ = $v[0].$v[3];
     else { $_ = ""; }
C:\usr\schodtt\src\java\forum\n00b\regex>perl recurse.pl
"key1" "value1"
"key2" "value2"
"key4" "value4"
"key5" "value5"
"key3" "((key4 value4) (key5 value5))"
"key6" "value6"
"key8" "value8"
"key9" "value9"
"key7" "((key8 value8) (key9 value9))"
C:\usr\schodtt\src\java\forum\n00b\regex>

Regular Expression Validator - want to edit an object acct field

The field is a character field. But the field must be editted as follows:
Field must either be 4 numeric numbers with the first position always an 8 so it could be a range from 8000 to 8999
But I must also allow them to enter "8%" or "8n%" or "8nn%" where n represents a number. They want me to allow wild cards.
How would I define this edit on the same field.
1) First Validation: If it has a "%" then the first digit must be an 8 then I can have any of the wild card combinations given above.
2) Second Validation: If no wild card then the field must be in the range from 8000-8999
Is this validation a candidate for Regular Expression Validator or for my own custom method.
If I can code this as a regular expression validator how would I code it. I spent the last day looking on the web for Regular Expression Validator examples.

I get the following errors that occur. I can key 8% or 8ddd but when I try these combinations 8d% or 8dd% then the following errors pop up. It gives multiple error but I am just keying on a single line. I can add multiple object lines but just one at a time.
java.lang.reflect.InvocationTargetException at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
java.lang.reflect.InvocationTargetException at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
- JBO-ObjectCode_Rule_1: Object must be in range 8000-8999 or object must be in form of 8%, 8n%, 8nn% where n represents a number.
- JBO-27008: Attribute set for ObjectCode in view object AccountsecuritygroupobjView2 failed
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- JBO-ObjectCode_Rule_1: Object must be in range 8000-8999 or object must be in form of 8%, 8n%, 8nn% where n represents a number.
- JBO-27008: Attribute set for ObjectCode in view object AccountsecuritygroupobjView2 failed
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Inline display of error message for a regular expression validation

Hi All,
I am using ApexLib in my application.
I am using regular expression validation for some of the items.
Those validation will happen when the button is pressed and the message will be displayed as per the error.
But, I want the errors to be displayed immediately when the focus is away from that item.
as we do for required items.
could anybody help me to achieve it?
Thanks in advance
bye
Srikavi

Hi Srikavi,
to achieve a Validation of an item when leaving the field you'll have to use some javascript code (as ApexLib does internally).
What do you need:
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- some Javascript code which is called in the onChange Event (you can put this code either in your page html header or, if it is used more often in your application, in a seperate js File)
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I actually never tried it myself, but i'm pretty sure that this will work (according to what i've seen in the ApexLib code).
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Edited by: peter_raganitsch on Sep 5, 2008 11:56 AM

Problems with regular Texting since iOS 7.0.3

Hello, I have an iPhone 5s recently upgraded to iOS 7.0.3 via OTA update. I never use iMessage, I have an unlimited text plan, so I always have used SMS with everyone. However, after this last update, I have problems with regular SMS. I can send SMS to everyone as usual, but can only get text messages from some-all of them using iPhone 5 with at least the lastest iOS6 version. I have noticed then only way to text them now is to turn on iMessage, otherwise I keep missing their replies. These are people, that until the last upgrade, I was texting with on a regular basis with no problems using plain SMS with iMessage option OFF. Contrary to most, I don't want to use iMessage but rather use regular carrier provided SMS.
For instance, both my son and daughter use an iPhone 5 with iOS 7 (but not the latest patch 7.0.3) installed, I can text with my son OK, but can't get any texts from my daughter, can only communicate with her using iMessage-BTW, we are all on the same network on a family plan. Can't understand this at all. Since I can SMS with some, but not others I don't think this is a problem with my carrier but rather a problem with my phone since the update to 7.0.3, and they say I am the only one they have problem with texting with and I am the only one on the new software version.
Anyone else has noticed this issue.

I wonder if this may have something to do with iMessage on my Macs. Recently updated to Maverirks and the iMessage app on my Macs was set up to my email and mobile phone (it wasn't before). I wonder if this is so, then whoever I send an SMS to that has iMessage on and replies back, will be picked up by iMessage since is turned on on my Mac, since replies go to the Mac but not my phone. If the sender has iMessage off, I get the SMS fine.

Grouping & Back-references with regular expressions on Replace Text window

I really appreciate the inclusion of the Regular Expressions in the search & replace feature. One thing I am missing is back-references in the replacement expression. For instance, in the unix tools vi or sed, I might do something like this:
s/$firstPart$ $secondPart$ $oldThirdPart$/\2 \1 newThirdPart/g
which would allow me to switch the places of firstPart and secondPart, and totally replace thirdPart. If grouping and back-references are already present in the Replace Text window, how does one correctly invoke them?

duplicate of Grouping & Back-references with regular expressions on Replace Text window

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Reset Item After Regular Expression Validation Fails

Apex 4.2
I have a page item (P1_MYITEM) that should only hold alpha charaters, so I have created an item regular expression validation
using
^[a-zA-Z]+$
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Assistance with Regular Expression and Tcl

Assistance with Regular Expression and Tcl
Hello Everyone,
I recently began learning Tcl to develop scripts for automating network switch deployments.
In my script, I want to name the device with a location and the last three octets of the base mac address.
I can get the Base MAC address by :
show version | include Base
Base ethernet MAC Address       : 00:00:00:DB:CE:00
And I can get the last three octets of the MAC address using the following regular expression.
([0-9a-f]{2}[:-]){2}([0-9a-f]{2}$)
But I have not been able to figure out how to call the regular expression in the tcl script.
I have checked several resources but have not been able to figure it out. Suggestions?
Ultimately, I want to set the last three octets to a variable (something like below) and then call the variable when I name the switch.
set mac [exec "sh version | i Base"] (include the regular expression)
ios_config "hostname location$mac"
Thanks for any assistance in advance.
Chris

This worked for me.
Switch_1(tcl)#set result [exec show ver | inc Base]
Base ethernet MAC Address       : 00:1B:D4:F8:B1:80
Switch_1(tcl)#regexp {([0-9A-F:]{8}\r)} $result -> mac
1
Switch_1(tcl)#puts $mac
F8:B1:80
Switch_1(tcl)#ios_config "hostname location$mac"
%Warning! Hostname should contain at least one alphabet or '-' or '_' character
locationF8:B1:80(tcl)#

Problem with regular expression validation

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