Qualified name of a port

i want to get the qualified name of the port in this WSDL in
QName object , what can i write
<wsdl:definitions targetNamespace="urn:CCCC" xmlns:SOAP-ENC="http://schemas.xmlsoap.org/soap/encoding/" xmlns:sc1="http://novell/extendComposer/SystemFault" xmlns:soap="http://schemas.xmlsoap.org/wsdl/soap/" xmlns:tns="urn:CCCC" xmlns:wsdl="http://schemas.xmlsoap.org/wsdl/" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<wsdl:types>
<schema attributeFormDefault="qualified" elementFormDefault="qualified" targetNamespace="http://novell/extendComposer/SystemFault" xmlns="http://www.w3.org/2001/XMLSchema">
<element name="FaultInfo">
<complexType>
<sequence>
<element maxOccurs="1" minOccurs="1" name="ComponentName" type="string"/>
<element maxOccurs="1" minOccurs="1" name="DateTime" type="string"/>
<element maxOccurs="1" minOccurs="1" name="MainCode" type="string"/>
<element maxOccurs="1" minOccurs="1" name="SubCode" type="string"/>
<element maxOccurs="1" minOccurs="1" name="Message" type="string"/>
</sequence>
</complexType>
</element>
</schema>
</wsdl:types>
<wsdl:message name="defaultinputRequest">
<wsdl:part name="cicsusername" type="xsd:string"/>
<wsdl:part name="cicspassword" type="xsd:string"/>
<wsdl:part name="dqryusername" type="xsd:string"/>
</wsdl:message>
<wsdl:message name="ccccoutputResponse">
<wsdl:part name="empno" type="xsd:string"/>
<wsdl:part name="empname" type="xsd:string"/>
<wsdl:part name="nationality" type="xsd:string"/>
<wsdl:part name="dateofbirth" type="xsd:string"/>
</wsdl:message>
<wsdl:message name="_SystemFault">
<wsdl:part element="sc1:FaultInfo" name="FaultInfo"/>
</wsdl:message>
<wsdl:portType name="CCCCPortType">
<wsdl:operation name="defaultinput" parameterOrder="cicsusername cicspassword dqryusername">
<wsdl:input message="tns:defaultinputRequest"/>
<wsdl:output message="tns:ccccoutputResponse"/>
<wsdl:fault message="tns:_SystemFault" name="_SystemFault"/>
</wsdl:operation>
</wsdl:portType>
<wsdl:binding name="CCCCSoapBinding" type="tns:CCCCPortType">
<soap:binding style="rpc" transport="http://schemas.xmlsoap.org/soap/http"/>
<wsdl:operation name="defaultinput">
<soap:operation/>
<wsdl:input>
<soap:body encodingStyle="http://schemas.xmlsoap.org/soap/encoding/" namespace="urn:CCCC" use="encoded"/>
</wsdl:input>
<wsdl:output>
<soap:body encodingStyle="http://schemas.xmlsoap.org/soap/encoding/" namespace="urn:CCCC" use="encoded"/>
</wsdl:output>
<wsdl:fault name="_SystemFault">
<soap:fault encodingStyle="http://schemas.xmlsoap.org/soap/encoding/" name="_SystemFault" namespace="http://novell/extendComposer/SystemFault" use="encoded"/>
</wsdl:fault>
</wsdl:operation>
</wsdl:binding>
<wsdl:service name="CCCCService">
<wsdl:port binding="tns:CCCCSoapBinding" name="CCCCPort">
<soap:address location="http://10.30.31.9/aaaWS/CCCC"/>
</wsdl:port>
</wsdl:service>
</wsdl:definitions>

Since 1.4 a change in the import structure actually
makes it impossible for a class in a package to
reference a class in the default package.Yep.
The choices are
1. Put it in a package.
2. Create a wrapper that does have a package. Use a compiler before 1.4 to compile it. Use the compiled version only in the new code.
3. Don't use it.

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Server fully qualified Name

Hi Experts,
How to findout the EP server fully qualified name?
I have following URL only
for eg: http://<servername>:<port>/irj/portal
i need fully qualified name?
Regards,
Manivannan P

Hi sap_prof, hi colleagues,
as I had also problems when starting with WDA on my SAP NetWeaver 7.0 SR 3, Development Subscription,
I like to add some comments how I have solved this situation.
My SAP AS-ABAP-Java runs in a Microsoft workgroup landscape (without an explicit DNS-Server) together
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Looking here (as usual) in the forum, I found yesterday following threads:
[FQDN for workgroup]
[Re: Server fully qualified Name]
So, having found the solution for my issue, I decided to come back to the community to give my implemented solution.
But knowing now the correct term FQDN, I found instead following additionally thread which give us the hint in the right
direction: [Re: CX_FQDN runtime error]
Reading in the book "Windows Server 2003, R2 and SP1 Edition, Wiley, given by Jeffrey R. Shapiro and Jim Boyce,
I get conscious about that with Windows hosts file you are able to resolve FQDN names without needing to query
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So, I build up my hosts files on all machines in the following manner:
127.0.0.1    localhost
192.168.MMM.NNN    <hostname>    <hostname>.dr-rauch.eu
192.168.MMM.NNN    <HOSTNAME>    <HOSTNAME>.dr-rauch.eu
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alternative DNS-Server    IP-address of my gateway/router, to be able furtheron to access the www.
Last but not least, I extended my SAP AS-ABAP-Java instance profile as proposed in the online help with the
following item:
icm/host_name_full = $(SAPLOCALHOST).dr-rauch.eu, and
via SU01 I managed a new user - especially for web access - to prevent some upcomming access and
other issues, and did what is said in the SAP note 1088717 - Active Services for WDA in the SICF.
Now I am able and ready to work in my "DNS-less" Microsoft workgroup landscape with my SAP system.
Thank you for this forum.
Regards, Christian

What are the names of the ports I have in my Macbook Pro to plug an external monitor into?

What are the names of the ports in my MacBook Pro that I can plug an external monitor into?

You have Thunderbolt or Mini DisplayPort. If you know which external display you want or you already have it, look at the ports it has got and get a Mini DisplayPort adapter for it. There are Mini DisplayPort adapters for DVI, VGA and HDMI.
Most external displays have DVI, VGA or HDMI. If you can use HDMI, use it, because it will provide much better quality. See > http://support.apple.com/kb/HT4241?viewlocale=en_US&locale=en_US
Mini DisplayPort adapters can be used with Thunderbolt

How Oracle Installation cannot get fully qualified name of the server?

Hi,
I'm installing Oracle Internet Application Server (10.1.2) on Windows. The Win machine has fully qualified name as myserver.mydomain.com
However, after the installation, Oracle shows that the URL to Internet Application Server is only
http://myserver:7777
I have changed the hosts file of the Win machine and add the line, e.g.,
10.1.10.10 myserver.mydomain.com myserver
where 10.1.10.10 is the IP of the Win machine.
I re-install Oracle Internet Application Server again, but it still cannot picks up the fully qualified name as myserver.mydomain.com for the URL of Internet Application Server page.
Any ideal?

I'm installing Oracle Internet Application Server (10.1.2) on Windows. The Win machine has fully qualified name as myserver.mydomain.com
I have changed the hosts file of the Win machine and add the line, e.g.,
10.1.10.10 myserver.mydomain.com myserverInstead, use the following in your hosts file, and then try again.
10.1.10.10 myserver.mydomain.com # myserver

SQL Server 2012 Management Studio: Import XML File to SQL Table - XML parsing: illegal qualified name character

Hi all,
In my SQL Server 2012 Management Studio, I executed the following code:
CREATE TABLE Products(
sku INT Primary KEY,
product_desc VARCHAR(30));
INSERT INTO Products (sku, product_desc)
SELECT X.product.query('SKU').value('.', 'INT'),
X.product.query('Desc').value('.', 'VARCHAR(30)')
FROM (
SELECT CAST(x AS XML)
FROM OPENROWSET(
BULK 'H:\ZenProducts.xml',
SINGLE_BLOB) AS T(x)
) AS T(x)
CROSS APPLY x.nodes('Products/Product') AS X(product);
SELECT sku, product_desc
FROM Products;
I got the following message:
Msg 9455, Level 16, State 1, Line 5
XML parsing: line 3, character 12, illegal qualified name character
I have no ideas why the "product" in the statement "SELECT X.product.query('SKU').value('.','INT')" is not legal qualified name charcter!!!??? Please kindly help, advise and respond.
Thanks in advance,
Scott Chang

Hi Manish, Thanks for your response.
Here is a copy of my ZenProducts.xml:
<Products>
<Product>
<SKU>1<</SKU>
<Desc>Book</Desc>
</Product>
<Product>
<SKU>2<</SKU>
<Desc>DVD</Desc>
</Product>
<Product>
<SKU>3<</SKU>
<Desc>Video</Desc>
</Product>
I found the wrong "<<" in my xml file and changed it to the right "<" for the statement<SKU>1</sku>. I executed the corrected code and I got the following new message:
Msg 2714, Level 16, State 6, Line 1
There is already an object named 'Products' in the database.
I don't know how to remove the old, existing the 'Products' object in the database and execute the corrected code again. Please kindly help, advise and tell me how to resolve this new problem.
Many Thanks,
Scott Chang
P. S. I played with another project to get the 'Products' object in my database before. Frankly, I don't know where the old 'Products' object and the database are. Please enlighten me in resolving this matter more clearly.
You welcome Scott, As Olaf mentioned in this post, there was already a table exists , so need to drop your Products table.
Apart from this, I guess either you did not pasted the full XML file or what, I needed to have the ( </Products>)closing tag in your XML file as follows.
<Products>
<Product>
<SKU>1</SKU>
<Desc>Book</Desc>
</Product>
<Product>
<SKU>2</SKU>
<Desc>DVD</Desc>
</Product>
<Product>
<SKU>3</SKU>
<Desc>Video</Desc>
</Product>
</Products>
You can use following script to drop if your
Products table is already existing.
if exists(select 1 from sys.tables where name ='Products')
drop table Products
CREATE TABLE Products(
sku INT Primary KEY,
product_desc VARCHAR(30));
INSERT INTO Products (sku, product_desc)
SELECT X.product.query('SKU').value('.', 'INT'),
X.product.query('Desc').value('.', 'VARCHAR(30)')
FROM (
SELECT CAST(x AS XML)
FROM OPENROWSET(
BULK 'H:\ZenProducts.xml',
SINGLE_BLOB) AS T(x)
) AS T(x)
CROSS APPLY x.nodes('Products/Product') AS X(product);
SELECT sku, product_desc
FROM Products;
Let us know if you face any other problem.
Thanks
Manish
Please click Mark as Answer if my post solved your problem and click
Vote as Helpful if this post was useful.

How to get fully qualified name for a class with just the class name

I want to get the fully qualified name of the class at runtime. The only piece of information which I have is the class name.
I want to create a runtime instance of a class with the class name [Just the class name].
Is there is any way to achieve this using ClassLoader?
Could anyone suggest me an idea?
Cheers,
Vinn.

Nope. If you are given "List", will you decide that means "java.util.List" or "java.awt.List"? Of course you could prompt the user to make the decision for you, I suppose. But using a class loader isn't going to make the task any easier.

Agentry Client 6.1.3 installation with preconfigure SMP server name et TCP Port

Hi,
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Hi Bill,
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Sorry for the confusion. I think I may have mis-worded my own question. It was a Friday!
Want I meant to say was, our developers' local JCo connections fail when they try to make a connection to an SAP system listed in the SLD. This is because the two machines (pc and SAP server) reside in different domains.
SAP Servers are in abc.domain.com
Desktop computers are in def.domain.com
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Hello,
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Since I have these import statement in my java class:
import javax.swing.*;
import javax.swing.border.*;
//I was wondering what the reason is that "javax.swing.border." is required in the following:
jsectionPanel.setBorder(new javax.swing.border.TitledBorder(
                                  new javax.swing.border.BevelBorder(javax.swing.border.BevelBorder.RAISED, Color.black, Color.black,
                                                  Color.lightGray,
                                                  Color.lightGray),
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                      javax.swing.border.TitledBorder.CENTER,         //int titleJustification,
                      javax.swing.border.TitledBorder.TOP,           //int titlePosition,
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-- HSC --

I guess there must have been something else conflicting at the time I tried because it would not compile, however, it works fine now.
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Fully-qualified name of a class not in a package

I have a class PackageNodeCreator and a class that's in a package called com.alex.PackageNodeCreator. I'm want to callthe first one (that's not in a package) like this...
PackageNodeCreator pnc=new PackageNodeCreator();
but I get this error:
symbol 'PackageNodeCreator' is ambiguous, found matching classes com.alex.PackageNodeCreator and PackageNodeCreator. Use fully-qualified name to disambiguate.
What is the fully qualified name of the PackageNodeCreator that's not in a package??
Message was edited by:
eggie5

Since 1.4 a change in the import structure actually
makes it impossible for a class in a package to
reference a class in the default package.Yep.
The choices are
1. Put it in a package.
2. Create a wrapper that does have a package. Use a compiler before 1.4 to compile it. Use the compiled version only in the new code.
3. Don't use it.

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Hi
How can i find out what does BlazeDs use for server.name and server.port in
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Mete
Thank you for your reply
So context.root is resolved at compile time and server & port at runtime
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Hi... Is it an AS3 "feature" or a FB compiler bug that I cannot use a class without importing it?
I have a statement such as
if (de.codebank.util.StringUtilities.startsWith(status.name, phase.name+"_"))
which does not compile until I import the StringUtilities class, which is pointless, of course.
The compile error mentions an unknown property "util"

I believe this is how AS3 works. Fully qualified class types require import statement.
You use fully qualified name whenever you want to avoid ambiguity.
However, when the code is like,
import mx.collections.XMLListCollection;
var arr:mx.collections.ArrayCollection;
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M2B-04-D-099.domain.com
but when i clikced next it gives me error as
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M i missing any steps?
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Deepali

Hi,
I am not able to install LDAP on my PC. My PC does not belong to any domain. What should I enter fully qualified name of my computer. When I enter only ldap (which is my computer name) it says "Value must be of the form hostname.domainname".
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I need to install LDAP as soon as possible.
Thanks in advance.
Kirti

Difference between fully qualified name and Canonical name

CAn annyone xplain Difference between fully qualified name and Canonical name

If you dont know then don't replyYou were given a link directly to the answer. The state of my knowledge is therefore (a) irrelevant and (b) not proven by anything in this thread.
Who asked [you] to reply
You* did, when you posted here.
I know how to get from java language specificationClearly not, or you wouldn't still be posting here.
I need clarification for what is in java lang specification..It seems clear enough to me. What part of "A member class or member interface M declared in another class C has a canonical name if and only if C has a canonical name. In that case, the canonical name of M consists of the canonical name of C, followed by ".", followed by the simple name of M." didn't you understand?

Identifying computer name on switch port

Hey Everyone,
I wish to build an CMDB for all our computers across the network. We have about 30x C2950 switches and few C3550. I wish to identify the computer name to switch port based on IP / Mac Address.
can this be done?
Let forward to anyone response.
Cheers,
Mark

Hi Mark,
Ping your desktops from each switch and then use the sh ip arp command to the Mac-address of the corresponding machine.
Use the command sh mac-address-table add xxxx.xxxx.xxxx to get the port details for the machine
ms_mla_mgmt_14dc#sh ip arp
Protocol Address Age (min) Hardware Addr Type Interface
Internet 172.16.102.249 3 0008.7434.e4d7 ARPA VLAN1
Internet 172.16.103.243 0 0013.c461.56bb ARPA VLAN1
ms_mla_mgmt_14dc#sh mac-address-table address 0050.5a10.6607
Non-static Address Table:
Destination Address Address Type VLAN Destination Port
0050.5a10.6607 Dynamic 1 GigabitEthernet0/2
ms_mla_mgmt_14dc#
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HTH
Narayan

Qualified name of a port

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