Query on connecting two diff user interface systems?
Hi Friends
Is it possible to connect MM system ECC 6.0 EPh4 and SuS system SRM 7.0 to a portal and both buyers from MM side and Suppliers from (SRM component)SuS side logs into portal and buyer should have a buyer role+display role of supplier so that buyer can monitor supplier,If its possible through std/what kind of development needs to be done.
Regards
Micheal
see: /thread/1549422 [original link is broken] for the answer
Similar Messages
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Payload from Two diff Outbound interfaces and Business Service
Hi All:
I created a scenario....where messge is coming from two diff outbound message interface..and have only one inbound inteface...
Message_One is coming from one OA interface.
Message_Two is coming from other OA interface.
I am using only one Inbound interface...
Message Mapping
Source Message:
MessageOne
MessageTwo
Target Message:
Message.
Now for this I cretaed one IP
<b>Fork</b> (two receive steps..for message one and mesage two)
<b>Transformation</b> (Interface Mapping between (Message one, Message Two) and Message
<b>Send.</b>
Here is the source from the Test Tab of the IR tool.
<?xml version="1.0" encoding="UTF-8"?>
<ns0:Messages xmlns:ns0="http://sap.com/xi/XI/SplitAndMerge">
<ns0:Message1>
<ns1:MT_Message_One xmlns:ns1="http://t-systems.com/XI/Demo/BPM">
<CutomerName>Gillette</CutomerName>
<CutomerID>AA123</CutomerID>
<ProductName>PN</ProductName>
<ProductID>1234</ProductID>
</ns1:MT_Message_One>
</ns0:Message1>
<ns0:Message2>
<ns1:MT_Message_Two xmlns:ns1="http://t-systems.com/XI/Demo/BPM">
<ProductCost/>
<ProductManufaturingDate/>
<ProductExpDate/>
<ProductID/>
</ns1:MT_Message_Two>
</ns0:Message2>
</ns0:Messages>
Now below information is coming from first File
<CutomerName>Gillette</CutomerName>
<CutomerID>AA123</CutomerID>
<ProductName>PN</ProductName>
<ProductID>1234</ProductID>
This infromation is coming from second file
<ProductCost/>
<ProductManufaturingDate/>
<ProductExpDate/>
<ProductID/>
Question how my input message looks for both??
I am using HTTP client to send the two diff message from two diff Business Service to same BPM.
Is it like
<b> <ns1:MT_Message_One xmlns:ns1="http://t-systems.com/XI/Demo/BPM">
<CutomerName>Gillette</CutomerName>
<CutomerID>AA123</CutomerID>
<ProductName>PN</ProductName>
<ProductID>1234</ProductID>
</ns1:MT_Message_One></b>
<b> <ns1:MT_Message_Two xmlns:ns1="http://t-systems.com/XI/Demo/BPM">
<ProductCost/>
<ProductManufaturingDate/>
<ProductExpDate/>
<ProductID/>
</ns1:MT_Message_Two>
</ns0:Message2></b>
Thanks & Regards,
Farooq FarooquiYes now I achived it...
It like the same as I mentioned
<ns1:MT_Message_One xmlns:ns1="http://t-systems.com/XI/Demo/BPM">
<CutomerName>Gillette</CutomerName>
<CutomerID>AA123</CutomerID>
<ProductName>PN</ProductName>
<ProductID>1234</ProductID>
</ns1:MT_Message_One>
<ns1:MT_Message_Two xmlns:ns1="http://t-systems.com/XI/Demo/BPM">
<ProductCost/>
<ProductManufaturingDate/>
<ProductExpDate/>
<ProductID/>
</ns1:MT_Message_Two>
</ns0:Message2> -
How do you connect two OSPF autonomous systems?
New member. Pls advise if this post does not belong here. Cheers.
You have two entirely separate OSPF systems. You wish to share routing
information between the two systems, but you don't want to join the
systems into one big OSPF system (you still want two area 0's).
Since OSPF does not use an AS number, as does EIGRP, how do you
redistribute routes between the two systems? Is it as simple as using
an ASBR and redistribute routes as you would any other non-OSPF routing
protocol? In that case, wouldn't configuring two interfaces of an ASBR
to join two different areas, of two different OSPF systems just screw
up the protocol and confuse it?
Thanx
JimThis is simple, but not so simple. :-) On one of the two routers, run two OSPF processes. Then set the processes up so one runs on all the interfaces except the connecting the two routers, and set the other one up so it runs on the interface connecting the two routers. Redistribute between the two processes.
So, if you have this:
10.2.0.0/16--A--10.1.1.0/24--B--10.3.0.0/16
On A:
router ospf 1
network 10.2.0.0 0.0.255.255 area 0
redistribute ospf 1 (insert metric, type, etc)
router ospf 2
network 10.1.1.0 0.0.0.255 area 0
redistribute ospf 1 (insert metric, type, etc)
On B:
router ospf 1
network 0.0.0.0 0.0.0.0 area 0
I would strongly suggest you use route tags or filters (tags are preferrable) to prevent routing loops between the two ospf processes/domains.
Russ -
Connect two ECC systems with one SAP CRM 7.0
Hi Gurus!
I have to do a customizing for connect two ECC 6.0 and one SAP CRM 7.0, only I need the organizational structure from both systems and they need update when the structure from CRM has changes. The business partner goes to ECCs system by PI interfaces.
Both organization models are different, so I have to maintain and update depending the changes in the business.
But I don't know if this is possible, I don't know if we can do this by Middleware, ALE or PI.
Can you please, give your oppinion about this topic?
Best regards,
Eugenia.-Hi Eugenia,
Please see note 1084315 which descriibes the the multiple backend scenario.
This should be relevant here.
Best regards
Christophe -
When we connect two bw systems to one R/3 system?
Hi ,
When we connect two bw systems to one R/3 system,
could you please exlain what is the imact to SAP and BW in terms of query performance, batch performance,Develoment ,Quality system,security,BW Support.
Thanks in advance.
Regards,
kranthiyou can connect multiple BW to single R3 source system.
In the delta queue (RSA7 in source system), you have a field with the target system, so you don´t have problem if you have many target bw system, because the data selection is done by system field.
Challenge arises when you have multiple R3 feeding to single BW system and then you have to consolidate the master data say 0material fed from different source system R3 then you can consolidate data using consolidated infoobject.
The following components concatenate to the key of a consolidated InfoObject:
1)source system ID (two-character source system ID; permitted values are stored NW BI table RSSOURSYSTEM)
2)one blank character
3)backend object type (four-character backend object type; permitted values are stored BI table RSBWBEOTYP)
4)master data key value as stored in the source system
Note that the key of a consolidated InfoObject solely consists of non-integrated informations from the different source systems. Integration across source systems results from a (maybee repeatedly applied) data consolidation and cleasing process which unveils duplicate master data keys.
Hope it Helps
Chetan
@CP.. -
Connecting two BW systems to 4.6 C OLTP SYSTEM
hello experts,
i got issue while creating source system in BW SYSTEM.
My is i trying to conect single oltp source system(4.6C) to TWO BW clients
one system is having connection already... now i am trying to connect other system.
all the RFC Conections looks fine from the both the systems..
here the problem is i am getting error saying source system cannot to created.
as error occured in the oltp system... when i cheked in R3. THERE IS SHORT DUMP.
.....can pls help on ythis process... what steps do i need to follow
other issue.
same rfc connection between CRM AND BI client.
when i try to create crm source in bi...all rfc connetions are fine
i am getting error is source does not exist.
this is minor issue
i want help on the FIRST ONE.. THAT IS REALLY IMPORTANT
THANKS
NAGHi Roberto,
Thaks for your quick answer! that is usefull for configuring the system after the connection! but, I need that the connection work properly first. itsn't the case. We connect the both systems to R3 and defined the background user's for connection, but at moment to transfer data the process is not initiated in R3 (back job) for the BW2-R3 link. But for BW1-R3 does. then, we had changed the BW1-R3 link by changed the logical system name in R3, for connect BW2-R3 and this is working correctly. It is the problem: parallel simultaneous load is not working... do you any idea about this? which task we need perform... or some suggestions? thanks! -
Can a R3 system connect two XI system?
Hi,gurus:
Can a R3 system connect two XI system?In SM59 we have to point the rfc to a single xi.Is it right?If my scenario is about idoc,we can define two RFC in SM59,
and two partners in WE21 and two ports in WE20,right?
Correct..
If my scenario is about abap proxy,then we can define two RFC in SM59,
and two parameters in sxmb_adm in the R3 side,right?Then in the tcode:SPROXY,
we can see both interfaces in two XI systems,right?
this is not posssible... -
Hibernate query...how to connect two databases...
hi i m new to hibernate..
i created two tables..
1st table is catalog:
2nd table is acctinfo
//HBM file is :
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE hibernate-mapping PUBLIC "-//Hibernate/Hibernate Mapping DTD 3.0//EN" "http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd">
<hibernate-mapping>
<class name="hibernate.example.Catalog" table="catalog">
<id name="id" type="integer" column="ID">
<generator class="increment"/>
</id>
<property name="journal" type="string" column="JOURNAL"/>
<property name="publisher" type="string" column="PUBLISHER"/>
<property name="edition" type="string" column="EDITION"/>
<property name="title" type="string" column="TITLE"/>
<property name="author" type="string" column="AUTHOR"/>
<bag name="accinfo" cascade="all" >
<key column="ID"/>
<one-to-many class="hibernate.example.Acctinfo"/>
</bag>
</class>
<class name="hibernate.example.Acctinfo" table="acctinfo">
<id name="id" type="integer" column="ID">
<generator class="increment"/>
</id>
<property name="account" type="string" column="ACCOUNT"/>
<property name="password" type="string" column="PASSWORD"/>
<property name="balance" type="string" column="BALANCE"/>
</class>
</hibernate-mapping>
///******************getter setter file is::****************
package hibernate.example;
public class Acctinfo
int id;
String account;
String password;
String balance;
public Acctinfo()
public void setId(int id)
this.id = id;
public int getId()
return id;
public void setAccount(String account)
this.account = account;
public void setPassword(String password)
this.password = password;
public void setBalance(String balance)
this.balance = balance;
public String getAccount()
return account;
public String getBalance()
return balance;
public String getPassword()
return password;
//********************2nd getter setter file is:***********************
package hibernate.example;
import java.util.List;
public class Catalog
int id;
String journal;
String publisher;
String edition;
String title;
String author;
private List accinfo;
public Catalog()
public void setId(int id)
this.id = id;
public int getId()
return id;
public void setJournal(String journal)
this.journal = journal;
public String getJournal()
return journal;
public void setPublisher(String publisher)
this.publisher = publisher;
public String getPublisher()
return publisher;
public void setEdition(String edition)
this.edition = edition;
public String getEdition()
return edition;
public void setTitle(String title)
this.title = title;
public String getTitle()
return title;
public void setAuthor(String author)
this.author = author;
public String getAuthor()
return author;
public void setAccinfo(List accinfo)
this.accinfo = accinfo;
public List getAccinfo()
return accinfo;
* To change this template, choose Tools | Templates
* and open the template in the editor.
package hibernate.example;
import hibernate.example.Acctinfo;
import hibernate.example.Catalog;
import java.util.ArrayList;
import java.util.Iterator;
import java.util.List;
import java.util.ListIterator;
import org.hibernate.Query;
import org.hibernate.SQLQuery;
import org.hibernate.Session;
import org.hibernate.SessionFactory;
import org.hibernate.Transaction;
import org.hibernate.cfg.Configuration;
public class CatalogClient
Session session = null;
SessionFactory sessionFactory = new Configuration().configure().buildSessionFactory();
public static void main(String str[])
CatalogClient clc = new CatalogClient();
//clc.saveData();
//clc.deleteData();
//clc.showData();
clc.updateData();
public void showData()
try
session =sessionFactory.openSession();
String SQL_QUERY ="select id, journal, publisher, edition, title, author from catalog";
// String SQL_QUERY ="select c.ID, c.JOURNAL, c.PUBLISHER, c.EDITION, c.TITLE, c.AUTHOR, a.ACCOUNT, a.PASSWORD,a.BALANCE from catalog c, ACCTINFO a where c.ID = a.ID";
SQLQuery query = session.createSQLQuery(SQL_QUERY);
System.out.println("*** query : *** "+ query);
//for(ListIterator it=query.list().listIterator();it.hasNext();)
for (ListIterator lit = query.list().listIterator(); lit.hasNext();)
Object[] row = (Object[]) lit.next();
/*System.out.println("ID: " + row[0]);
System.out.println("Title: " + row[1]);
System.out.println("Author: " + row[2]);
System.out.println("Isbn: " + row[3]);
System.out.println("Pages: " + row[4]);
System.out.println("Copyright: " + row[5]);
System.out.println("Cost: " + row[6]);
System.out.println("******NEXT****************");
Object[] row = (Object[]) it.next();*/
System.out.println("ID: " + row[0]);
System.out.println("JOURNAL: " + row[1]);
System.out.println("PUBLISHER: " + row[2]);
System.out.println("EDITION: " + row[3]);
System.out.println("TITLE: " + row[4]);
System.out.println("AUTHOR: " + row[5]);
System.out.println("acc: " + row[6]);
System.out.println("pass: " + row[7]);
System.out.println("bal: " + row[8]);
System.out.println("***************************");
session.close();
catch(Exception e)
System.out.println(e.getMessage());
public void saveData()
session =sessionFactory.openSession();
Transaction transaction = null;
transaction = session.beginTransaction();
Catalog catalog = setBean();
//System.out.println("before save");
session.save(catalog);
//System.out.println("after save");
transaction.commit();
session.flush();
session.close();
public void updateData()
session =sessionFactory.openSession();
Catalog catalog = new Catalog();
catalog.setId(2);
catalog.setAuthor("manoj");
catalog.setJournal("java");
catalog.setEdition("1st");
catalog.setPublisher("indiabulls");
catalog.setTitle("java Servlet");
session.update(catalog);
session.flush();
session.close();
public void deleteData()
session =sessionFactory.openSession();
Catalog catalog = new Catalog();
catalog.setId(3);
session.delete(catalog);
session.flush();
session.close();
public static Catalog setBean()
Acctinfo accinfo = new Acctinfo();
accinfo.setAccount("MANOJ1");
accinfo.setPassword("orbis");
accinfo.setBalance("1000");
List list = new ArrayList();
list.add(accinfo);
Catalog catalog = new Catalog();
catalog.setJournal("india");
catalog.setPublisher("indiabulls");
catalog.setEdition("ist");
catalog.setTitle("orbis");
catalog.setAuthor("manoj");
catalog.setAccinfo(list);
return catalog;
//********************CFG FILE IS ******************
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE hibernate-configuration PUBLIC "-//Hibernate/Hibernate Configuration DTD 3.0//EN" "http://hibernate.sourceforge.net/hibernate-configuration-3.0.dtd">
<hibernate-configuration>
<session-factory name="session">
<property name="hibernate.dialect">org.hibernate.dialect.Oracle9Dialect</property>
<property name="hibernate.connection.driver_class">oracle.jdbc.driver.OracleDriver</property>
<property name="hibernate.connection.url">jdbc:oracle:thin:@172.16.31.25:1521:BOMBAY</property>
<property name="hibernate.connection.username">mumbai</property>
<property name="hibernate.connection.password">mumbai123</property>
<!-- Set AutoCommit to true -->
<property name="connection.autocommit">true</property>
<property name="dialect">org.hibernate.dialect.OracleDialect</property>
<!-- Mapping files -->
<mapping resource="Catalog.hbm.xml"/>
</session-factory>
</hibernate-configuration>
**********************error i m facing is :************************
0 [main] WARN net.sf.ehcache.config.Configurator - No configuration found. Configuring ehcache from ehcache-failsafe.xml found in the classpath: jar:file:/C:/Documents%20and%20Settings/d.poonam/Desktop/hibernate/lib/ehcache-1.1.jar!/ehcache-failsafe.xml
1188 [main] WARN org.hibernate.impl.SessionFactoryObjectFactory - Could not bind factory to JNDI
javax.naming.NoInitialContextException: Need to specify class name in environment or system property, or as an applet parameter, or in an application resource file: java.naming.factory.initial
at javax.naming.spi.NamingManager.getInitialContext(Unknown Source)
at javax.naming.InitialContext.getDefaultInitCtx(Unknown Source)
at javax.naming.InitialContext.getURLOrDefaultInitCtx(Unknown Source)
at javax.naming.InitialContext.getNameParser(Unknown Source)
at org.hibernate.util.NamingHelper.bind(NamingHelper.java:52)
at org.hibernate.impl.SessionFactoryObjectFactory.addInstance(SessionFactoryObjectFactory.java:90)
at org.hibernate.impl.SessionFactoryImpl.<init>(SessionFactoryImpl.java:247)
at org.hibernate.cfg.Configuration.buildSessionFactory(Configuration.java:1043)
at hibernate.example.CatalogClient.<init>(CatalogClient.java:24)
at hibernate.example.CatalogClient.main(CatalogClient.java:27)
please help me out....
thanks in advance..
if u know how to connect two tables plz let me know..
its urgent....I made this work with MySQL. Adapt to your situation as needed. - %
package hibernate.model;
import hibernate.util.HibernateUtils;
import hibernate.model.Catalog;
import hibernate.model.Account;
import org.apache.commons.logging.Log;
import org.apache.commons.logging.LogFactory;
import org.hibernate.Session;
import hibernate.util.HibernateUtils;
import static junit.framework.Assert.assertEquals;
import static junit.framework.Assert.assertNotNull;
public class CatalogTest
private static final Log LOGGER = LogFactory.getLog(CatalogTest.class);
public static void main(String[] args)
Session session = null;
try
session = HibernateUtils.getSessionFactory().getCurrentSession();
session.beginTransaction();
int rowsBefore = HibernateUtils.getRowCount(session, Catalog.class);
assertEquals("should not have any Catalogs", rowsBefore, 0);
Catalog catalog = new Catalog("test title");
catalog.addAccount(new Account(100));
catalog.addAccount(new Account(200));
Long id = (Long) session.save(catalog);
assertNotNull("generated id should not be null", id);
LOGGER.info("returned id: " + id);
session.getTransaction().commit();
LOGGER.debug("transaction committed");
catch (Exception e)
LOGGER.error(e);
session.getTransaction().rollback();
package hibernate.model;
import java.io.Serializable;
import java.text.NumberFormat;
public class Account implements Serializable
private Long id;
private int balance;
public Account()
this(null, 0);
public Account(int balance)
this(null, balance);
public Account(Long id, int balance)
this.id = id;
this.balance = balance;
public Long getId()
return id;
private void setId(Long id)
this.id = id;
public int getBalance()
return balance;
private void setBalance(int balance)
this.balance = balance;
public boolean equals(Object o)
if (this == o)
return true;
if (!(o instanceof Account))
return false;
Account account = (Account) o;
return !(id != null ? !id.equals(account.id) : account.id != null);
public int hashCode()
int result;
result = (id != null ? id.hashCode() : 0);
result = 31 * result + balance;
return result;
public String toString()
return new StringBuilder().append("Account{").append("id=").append(id).append(", balance=").append(NumberFormat.getCurrencyInstance().format(balance)).append('}').toString();
<?xml version="1.0"?>
<!DOCTYPE hibernate-mapping PUBLIC
"-//Hibernate/Hibernate Mapping DTD 3.0//EN"
"http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd">
<hibernate-mapping package="hibernate.model" default-access="field" default-lazy="true">
<class name="Account" table="accounts">
<id name="id" column="account_id">
<generator class="native"/>
</id>
<property name="balance" column="balance"/>
</class>
</hibernate-mapping>
package hibernate.model;
import java.io.Serializable;
import java.util.Set;
import java.util.HashSet;
import java.util.Collections;
public class Catalog implements Serializable
private Long id;
private String title;
private Set<Account> accounts;
public Catalog()
this(null, "", Collections.EMPTY_SET);
public Catalog(String title)
this(null, title, Collections.EMPTY_SET);
public Catalog(Long id, String title, Set<Account> accounts)
this.id = id;
this.title = title;
this.accounts = new HashSet<Account>(accounts);
public Long getId()
return id;
private void setId(Long id)
this.id = id;
public String getTitle()
return title;
private void setTitle(String title)
this.title = title;
public Set<Account> getAccounts()
return accounts;
private void setAccounts(Set<Account> accounts)
this.accounts = accounts;
public void addAccount(Account account)
this.getAccounts().add(account);
public void removeAccount(Account account)
this.getAccounts().remove(account);
public boolean equals(Object o)
if (this == o)
return true;
if (!(o instanceof Catalog))
return false;
Catalog catalog = (Catalog) o;
return !(id != null ? !id.equals(catalog.id) : catalog.id != null);
public int hashCode()
return (id != null ? id.hashCode() : 0);
public String toString()
return new StringBuilder().append("Catalog{").append("id=").append(id).append(", title='").append(title).append('\'').append(", accounts=").append(accounts).append('}').toString();
<?xml version="1.0"?>
<!DOCTYPE hibernate-mapping PUBLIC
"-//Hibernate/Hibernate Mapping DTD 3.0//EN"
"http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd">
<hibernate-mapping package="hibernate.model" default-access="field" default-lazy="true">
<class name="Catalog" table="catalogs">
<id name="id" column="catalog_id">
<generator class="native"/>
</id>
<property name="title" column="title"/>
<set name="accounts" cascade="all">
<key column="catalog_id"/>
<one-to-many class="hibernate.model.Account"/>
</set>
</class>
</hibernate-mapping>
<!DOCTYPE hibernate-configuration PUBLIC
"-//Hibernate/Hibernate Configuration DTD 3.0//EN"
"http://hibernate.sourceforge.net/hibernate-configuration-3.0.dtd">
<hibernate-configuration>
<session-factory>
<property name="connection.driver_class">com.mysql.jdbc.Driver</property>
<property name="connection.url">jdbc:mysql://localhost:3306/hibernate?autoReconnect=true</property>
<property name="connection.username">hibernate</property>
<property name="connection.password">hibernate</property>
<property name="connection.pool_size">1</property>
<property name="dialect">org.hibernate.dialect.MySQL5InnoDBDialect</property>
<property name="show_sql">true</property>
<property name="generate_statistics">true</property>
<property name="query.factory_class">org.hibernate.hql.classic.ClassicQueryTranslatorFactory</property>
<property name="cache.provider_class">org.hibernate.cache.NoCacheProvider</property>
<property name="cache.use_minimal_puts">false</property>
<property name="cache.use_query_cache">false</property>
<property name="order_updates">false</property>
<property name="hbm2ddl.auto">create-drop</property>
<property name="current_session_context_class">thread</property>
<mapping resource="hibernate/persistence/hibernate/Account.hbm.xml"/>
<mapping resource="hibernate/persistence/hibernate/Catalog.hbm.xml"/>
</session-factory>
</hibernate-configuration> -
Connecting Two ASAs together via local interface
Hi
I have two cisco ASA routers & wish to connect them together so that traffic between is permitted with out going outside interface.
Two asa are located at in ONE office and two have separate internet connection (ISP) configured.
So here is what I did so far.
configure one of the interface on each ASA with some IP adddress.
ASA 1 ------- interface 0/6 10.1.1.1 (ASA X 1512)
ASA 2 --------- interface 0/5 10.2.2.2 (ASA 5055)
now connected a Ethernet cable to these inferface.
I was able to addd a route on asa 2.
route add interface0/5 10.1.1.0/24 10.2.2.2
but when I add route on ASA 1 I get the following error.
route add interface0/6 10.2.2.2/24 10.1.1.1
%invalid next hop address it belongs to one of our interface.Sorry if I was not clear
I have two separate ISPs connecting two two separate ASAs.. Two asa are now connecting separate LANs.
Now I want to communicate between LANs.
So I connected an ethernet cable bw ASAs and trying to configure the route.
But not able to establish
Here is the configuration of ASA where I am faceing problem, while trying to add route
route add voice-interface 10.1.1.1/24 255.255.255.0 10.2.2.2 1
I get error says
route already exsists
interface GigabitEthernet0/0
nameif outside0
security-level 0
ip address 0.2.5.2 255.255.255.252
interface GigabitEthernet0/1
shutdown
no nameif
no security-level
no ip address
interface GigabitEthernet0/2
nameif inside2
security-level 100
ip address 192.168.1.1 255.255.255.0
interface GigabitEthernet0/5
nameif voice-interface
security-level 100
ip address 10.1.1.1 255.255.255.0
object network NETWORK_OBJ_12.1.3.0_2
subnet 12.1.3.0 255.255.255.0
object network NETWORK_OBJ_192.168.1.0_24
subnet 192.168.1.0 255.255.255.0
object network OBJ_ALL_NETWORK
subnet 0.0.0.0 0.0.0.0
description Any Network
object network voice-asa-network
subnet 10.2.2.0 255.255.255.0
object network 10.1.1.1
host 10.1.1.1
access-list outside0_cryptomap extended permit ip 192.168.1.0 255.255.255.0 12.1.3.0 255.255.255.0
access-list inside2_access_in extended permit ip 192.168.1.0 255.255.255.0 any
nat (inside2,outside0) source static NETWORK_OBJ_192.168.1.0_24 NETWORK_OBJ_192.168.1.0_24 destination static NETWORK_OBJ_12.1.3.0_24 NETWORK_OBJ_12.1.3.0_24 no-proxy-arp route-lookup
object network OBJ_ALL_NETWORK
nat (any,outside0) dynamic interface
route outside0 0.0.0.0 0.0.0.0 0.2.5.2 1
dynamic-access-policy-record DfltAccessPolicy
user-identity default-domain LOCAL
snmp-server enable traps snmp authentication linkup linkdown coldstart warmstart
crypto ipsec ikev1 transform-set ESP-DES-MD5-TRANS mode transport
crypto ipsec security-association pmtu-aging infinite
crypto map outside0_map 1 match address outside0_cryptomap
crypto map outside0_map 1 set pfs
crypto map outside0_map 1 set peer 9.2.5.1
crypto map outside0_map 1 set ikev1 transform-set ESP-AES-128-SHA ESP-AES-128-MD5 ESP-AES-192-SHA ESP-AES-192-MD5 ESP-AES-256-SHA ESP-AES-256-MD5 ESP-3DES-SHA ESP-3DES-MD5 ESP-DES-SHA ESP-DES-MD5
crypto map outside0_map 1 set ikev2 ipsec-proposal AES256 AES192 AES 3DES DES
crypto map outside0_map interface outside0
crypto ca trustpool policy
crypto ikev2 policy 1
encryption aes-256
integrity sha
group 5 2
prf sha
lifetime seconds 86400
crypto ikev2 policy 10
encryption aes-192
integrity sha
group 5 2
prf sha
lifetime seconds 86400
crypto ikev2 policy 20
encryption aes
integrity sha
group 5 2
prf sha
lifetime seconds 86400
crypto ikev2 policy 30
encryption 3des
integrity sha
group 5 2
prf sha
lifetime seconds 86400
threat-detection basic-threat
threat-detection scanning-threat
threat-detection statistics access-list
no threat-detection statistics tcp-intercept
ssl encryption aes128-sha1 3des-sha1
group-policy GroupPolicy_6.2.5.1 internal
group-policy GroupPolicy_6.2.5.1 attributes
vpn-tunnel-protocol ikev1 ikev2
class-map inspection_default
match default-inspection-traffic -
RV042 VPN Client Access not able to connect two users at same time
I have a RV042 and have set it up for VPN Client access using the QuickVPN client to connect my remote users. I discovered today that I cannot have two users connect in at the same time. Both users are in the same remote office. They can connect individually with no problem but if one is connected and the other tries connect also the second user gets a message the gateway is not responding. They are both running WinXPPRo SP3. Any help is greatly appreciated.
Were your QuickVPN clients behind a firewall router of some sort? For multiple QuickVPN clients to be able to connect to the remote RV042 at the same time, the local firewall router must have VPN Passthrough correctly implemented. You could try using a RV042 as the firewall router for your QuickVPN clients and you should be able to maintain 2 tunnels at the same time to the remote RV042.
-
Can two different SRM clients systems connect to one R/3 Back-end system?
Hello,
Trying to developing SRM Co-Exist/Global strategy, based on the following scenario:
1. Two different SRM client systems, each at DIFFERENT SRM Version/Release Level. SRM system "A" runs in Stand-Alone and Extend Classic Scenario mode. SRM system "B" runs in Classic Scenario mode
2. Two different R/3 back-end systems, each with SAME R/3 4.7 Version/Release Level.
Question 1: Can the two (2) different SRM client systems be connected to one (1) of the R/3 back-end systems?
Question 2: Are there any Basis Plug-In (PI_BASIS) issues/difficulties to consider from either the SRM client or R/3 back-end side?
Question 3: Does each SRM client need it own unique transaction document type(s) and number range(s) definitions?
Question 4: Are there any other difficulties, for example, with RFC and Partner Profile related definitions and what are the steps to address/resolve difficulties?
Please advise and thanks in advance for your feedback!
Regards,
Ed
Edited by: Ed Shigo on Mar 16, 2009 6:40 AMQuestion 1: Can the two (2) different SRM client systems be connected to one (1) of the R/3 back-end systems?
They can be connected
Question 2: Are there any Basis Plug-In (PI_BASIS) issues/difficulties to consider from either the SRM client or R/3 back-end side?
Make sure that you have unique consumer entries for Middleware for Material replication, RFCs etc
Question 3: Does each SRM client need it own unique transaction document type(s) and number range(s) definitions?
Yes you need to have them.
Question 4: Are there any other difficulties, for example, with RFC and Partner Profile related definitions and what are the steps to address/resolve difficulties?
Don't see any difficulties as long as the a structured approach is followed. -
How to inner join attribuet from user with system resource on sccm 2012 query
Hi , I am using SCCM 2012. Trying to create a WQL query to get list of computers with department name and netbios names,etc. these are in USER and SYSTEM RESOURCE object type seperately. The query wizard doesn't allow me to choose sytem
resource and USER attribute at same time. In JOIN, the inner join also doesn't have SYSTEM RESOURCE attribute class for me to join it with USER attribute class. Any way to resolve this issue so that I can get a query as mentioned?
I tried the wql below and pasted to my test query, it gave an error. I guess it's because that wql is on sccm2007.
Please advise,thanks!
http://social.technet.microsoft.com/Forums/en-US/8c47f069-5390-45bd-a619-5f5498947baa/sccm-query-which-joins-system-resource-and-user-resource?forum=configmgrgeneral
http://social.technet.microsoft.com/Forums/en-US/8c47f069-5390-45bd-a619-5f5498947baa/sccm-query-which-joins-system-resource-and-user-resource?forum=configmgrgeneral
Thanks and best regards, -- KFHi,
Try the suggestion by Garth Jones or post a new thread at
http://social.technet.microsoft.com/Forums/en-US/home?forum=ITCG
I am not familiar with WQL, maybe you could get better help at the forum above.
Juke Chou
TechNet Community Support -
Same query takes different time for two different users with same privileges
Hi,
Just wanted to know if it is possible for an INSERT query to take different amount of time for two different users for the same volume of data. If so, what could be the reason? I would like to add that we are not executing the query simultaneously. But it is always faster for user1(within 10-20 seconds) and slower for user2(takes around 8-10 minutes).Show execution plan for each user. I think there is other reasons which you didn't not tell
-
How to connect one ECC 6.0 system to two BW ssytems.
Hello all,
I am trying to connect one ECC 6.0 systems to two different BW systems. The BW systems have two different logic names.
I tried to find an answer in the threads , but could not able to find the steps. they were talking about the notes which fixes for the deltas. but I am not even able to connect the systems at all to implement that notes.
Please give me the steps how to connect to an another BW2 system. The connection between ECC and BW1 ia working fine.
Thanks,The error message is .
Source system cannot use any of the proposed connection names
Message no. RSAR362
Diagnosis
Every connection to a source system is named using a unique two-digit identifier. Source system LOGTST100 does not accept any of the proposed values.
The last proposed value was BB.
System Response
Source system has not been connected.
Procedure
If you want to recreate the source system from BI information, then you can only use a single value, namely BB, because the connection already has this name in BI.
Delete the existing connections in the source system or contact a BI consultant. -
Generate query at a time & connect two database ?
Hi
Could u help me? it is necessary that
I have two database ( RSHPL,RSPL) and both data base have same table name and same fieldname (Table Name :-OITM, Fieldname :ONHAND ,pk- ITEMcode,)
At first I tell u what I want?
I want to generate query at a time & connect two database and same table name(OITM) to select the TOTAL VALUE of this field(ONHAND) and pk-key is Itemcode.
Is it Possible? If Possible plz write this query and send me.Hi,
I don't think its possible to write a query from within SAP that allows you to get data from another SAP database.
I have used SQL Reporting Services to report on data from multiple databases, and this works very well for many of my clients. It depends on what you want to do with the data, do you need to display it on the screen in SAP and it to a field or will a report suffice?
Regards,
Adrian
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