Query regarding dummy column in OBIEE.

Hi Gurus,
I have a report where data is pulled at region level
regions are say :A,B,C,D,E,F,G,H
Now we have a reqmt from one of our client to group the regions and classify them as grades.But we don't have any grades in our database.This reqmt is for users of a specific country only so we don't want to add this new grade column to our database.We want to create a new dummy column for this specific report only and want to hard code the grades like this
Grade Top : Regions are A,B,D
Grade Bottom:Regions areC,F,G
Grade Middle:Regions areE,H
So the reqmt is i want to add a new dummy column (only for this particular report) called Grade with three values :Top,Bottom,Middle
How to do this , pls suggest.
Regards,
RC

Hi,
You could add a additional column to the request. In the Expression Builder you create a 'CASE-statement'
CASE when Regions in ( 'A','B','D' ) then 'Grade Top'
when Regions in ( 'C','F','G' ) then 'Grade Bottom'
when Regions in ( 'E','H' ) then 'Grade Middle'
END
Regions would be you logical column
Good Luck,
Daan Bakboord
http://obibb.wordpress.com

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1.I invoke a procedure in Oracle called submit thru
my Java application.
The submit procedure saves the XML data in the
database
and displays this data in a Front End GUI.
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I would like to display the new row with the new
elements in the GUI.
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1.Delete the row being shown,save the new row with
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Hi all,
I am new to obiee, so need some help from obiee experts. Can anyone tell me how to place one column data under another column in obiee report?
i need the report to be as below
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Two ideas I can think of:
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See example below. Hope this is what you want.
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Hi all.
I have this little query, regarding the functions that are synchronised, based on accessing the lock to the object, which is being used for synchronizing.
Ok, I will clear myself with the following example :
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int a;
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Kindly correct me I am wrong anywhere in the above.
c) In case 3, we have a static function , synchronized on a non-static object. However, Java does not allow functions of this type, so we may safely move forward.
d) In case 4, we have a static function, synchronized on a static object.
Here, again if obj1, and obj2 happen to call the function at the same time, obj1 will try to obtain lock for obj1.a; while obj2 will try to obtain lock for obj2.a. However, since obj1.a and obj2.a are the same, thus we will indeed obtain sychronisation. But we are only partly done for this case.
First, Kindly correct me I am wrong anywhere in the above.
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Ashutosh

a) In case 1, we have a non-static function, synchronized on a non-static object. Thus, effectively, there is no-synchronisationThere is no synchronization between distinct First objects, but that's what you specified. Apart from the coding bug noted below, there would be synchronization between different threads using the same instance of First.
b) In case 2, we have a non-static function, synchronized on a static object. Here, again if obj1, and obj2 happen to call the function at the same time, obj1 will try to obtain lock for obj1.a; while obj2 will try to obtain lock for obj2.a.obj1/2 don't call methods or try to obtain locks. The two different threads do that. And you mean First.b, not obj1.b and obj2.b, but see also below.
d) In case 4, we have a static function, synchronized on a static object. Here, again if obj1, and obj2 happen to call the function at the same time, obj1 will try to obtain lock for obj1.a; while obj2 will try to obtain lock for obj2.a.Again, obj1/2 don't call methods or try to obtain locks. The two different threads do that. And again, you mean First.b. obj1.b and obj2.b are the same as First.b. Does that make it clearer?
Now, I have a query : what happens if the call is made in a classically static manner, i.e. using the statement "First.func_four;".That's what happens in any case whether you write obj1.func_four(), obj2.func)four(), or First.func_four(). All these are identical when func_four(0 is static.
Now, consider this, suppose we have the same reference obj1, in two threads, and the call "obj1.func_four;" happens to occur at the same time from each of these threads. Thus, we have obj1 rying to obtain lock for obj1.aNo we don't, we have a thread trying to obtain the lock on First.b.
and again obj1 trying to obtain lock for obj1.aYou mean obj2 and First.b, but obj2 doesn't obtain the lock, the thread does.
which are the same locks. So, if obj1.a of the first thread obtains the lock, then it will enter the function no-doubt, but the call from the second thread will also succeed.Of course it won't. Your reasoning here makes zero sense..Once First.b is locked it is locked. End of story.
Thus, effectively, our synchronisation is broken.No it isn't. The second thread will wait on the same First.b object that the first thread has locked.
However in any case you have a much bigger problem here. You're autoboxing your local 'int' variable to a possibly brand-new Integer object every call, so there may be no synchronization at all.
You need:
Object a = new Object();
static Object b = new Object();

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Fightclub,
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