Query to exclude first record of the day

Question

Hi Everyone
I have a table report_data in this I wanted to retrieve the count of transactions performed each day which are
unique ones
e.g. count of transaction each day for that card is 1 if transaction is performed with that card on that day
which I did with
(Here card stands for the card number which I can consider with as a transaction)
select count(distinct(card)) from report_data where business_name='prime, inc.';
Now the problem is I want to find the count of the rest of the transaction excluding the first one of that day
I have used the following query but unable to retrieve the answer
select business_name, count(card) from report_data where card not in (select distinct(card) from report_data) group by card;
Please provide the answer
Thanks

Answer 1

Hi,
The syntax with distinct is without the brackets as shown below:
And if you want to list business_name you should include it in the group by list.
SELECT
  business_name
, COUNT(card)
FROM
  report_data
WHERE
  card NOT IN
    SELECT DISTINCT
      card            -- no brackets
    FROM
      report_data
GROUP BY
  card
  ,business_name
;This will not return any rows.
Since there will be no card in report_data that is not in report_data.
Now the problem is I want to find the count of the rest of the transaction excluding the first one of that dayIf you want a count of the number of cards without the first one on a day, just subtract 1.
If you want to list the cards without the first one per day do:
with report_data as
  select date '2012-04-20' as list_date, 1 as card, 'home' as business_name from dual union all
  select date '2012-04-20' as list_date, 2 as card, 'home' as business_name  from dual union all
  select date '2012-04-20' as list_date, 3 as card, 'home' as business_name  from dual union all
  select date '2012-04-21' as list_date, 1 as card, 'home' as business_name  from dual union all
  select date '2012-04-21' as list_date, 2 as card, 'home' as business_name  from dual
select
  business_name
  ,list_date
  ,card
from
  SELECT
    business_name
    ,list_date
    ,card
    ,row_number() over (partition by list_date order by card) rn
  FROM
    report_data
where
  rn > 1
BUSINESS_NAME LIST_DATE CARD
home          20-APR-12    2
home          20-APR-12    3
home          21-APR-12    2
;Regards,
Peter
Edited by: Peter vd Zwan on Apr 20, 2012 5:30 AM