Question about 'cin' & 'cout' (C++) (SOLVED)

Question

Probably a stupid question with a simple answer but here goes;
when i compile the following code
#include <iostream>
#include <string>
int main(int argc, char* argv[])
string buffer;
while (1 == 1)
cout<<" ## ";
cin>>buffer;
it compiles fine, when run it does the following
prints " ##  " minus quotes
then pauses for input
however the strange thing is that if i enter a string with a space in, quotes or no, it repeats the 'cout' statement, see below for output
##  this is a string
then pauses for input, as it should, i ask you why it does this as i don't call it "expected behaviour", not with that code anyway.
EDIT: fixed some typos
EDIT_2: boxed of output&code, thx ewaller
Last edited by Iknow (2011-06-25 23:39:13)

Answer 1

Nah, there is a loop, right?
You type "this is a string".
cin reads "this" and gets out.
while(1 == 1) is tested and gets in (of course).
cout prints " ## ". (*)
cin reads "is" and gets out.
etc.
(*) The thing why it gets "mixed" (I mean you type the whole string and then ## * 4 appears) is probably because terminal is flushing (and thus refreshing) stdout on Enter hit only.