Remove some portion of the String

Hi,
My problem is String contains data is
artist1
title1
-1
artist2
title2
2
artist3
title3
-1
artist4
title4
2
i want to remove some portion of the string like artist2, title2, 2 so my updated string should be like
artist1
title1
-1
artist3
title3
-1
artist4
title4
2
Here i am using String.replaceAll("artist2","");
String.replaceAll("title3","");
String.replaceAll("2","")("[\code]
its deleting whole data in a string, can any one please help me how to delete particular part of the string. Here artist and title are unique and no are reapeated.

Hey I had the same problem like you yesterday.
I tried using regEx with positiv lookahead but noticed that there was a problem when the String went over multiple lines. There is probably some solution to it that i havent found yet.
So what I did was get the Index of the first text I wanted deleted(in your case I guess "artist2"). Then got the Index of the end of the deletion point(In your case the "2"?) and then formed a new String with the substring from the orginal one and the indexes of the two deletion points.
Sounds kinda dirty but it did work out. Anyway I'll dig myself into regular expressions more today because if you get them to work, they're a charm :)

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Need some help with the String method

Hello,
I have been running a program for months now that I wrote that splits strings and evaluates the resulting split. I have a field only object (OrderDetail) that the values in the resulting array of strings from the split holds.Today, I was getting an array out of bounds exception on a split. I have not changed the code and from I can tell the structure of the message has not changed. The string is comma delimited. When I count the commas there are 26, which is expected, however, the split is not coming up with the same number.
Here is the code I used and the counter I created to count the commas:
public OrderDetail stringParse(String ord)
OrderDetail returnOD = new OrderDetail();
int commas = 0;
for( int i=0; i < ord.length(); i++ )
if(ord.charAt(i) == ',')
commas++;
String[] ordSplit = ord.split(",");
System.out.println("delims: " + ordSplit.length + " commas: " + commas + " "+ ordSplit[0] + " " + ordSplit[1] + " " + ordSplit[2] + " " + ordSplit[5]);
The rest of the method just assigns values to fields OrderDetail returnOD.
Here is the offending string (XXX's replace characters to hide private info)
1096200000000242505,1079300000007578558,,,2013.10.01T23:58:49.515,,USD/JPY,Maker,XXX.XX,XXX.XXXXX,XXXXXXXXXXXXXXXX,USD,Sell,FillOrKill,400000.00,Request,,,97.7190000,,,,,1096200000000242505,,,
For this particular string, ordSplit.length = 24 and commas = 26.
Any help is appreciated. Thank you.

Today, I was getting an array out of bounds exception on a split
I don't see how that could happen with the 'split' method since it creates its own array.
For this particular string, ordSplit.length = 24 and commas = 26.
PERFECT! That is exactly what it should be!
Look closely at the end of the sample string you posted and you will see that it has trailing empty strings at the end: '1096200000000242505,,,'
Then if you read the Javadocs for the 'split' method you will find that those will NOT be included in the resulting array:
http://docs.oracle.com/javase/6/docs/api/java/lang/String.html#split(java.lang.String)
split
public String[] split(String regex)
Splits this string around matches of the given regular expression. This method works as if by invoking the two-argument split method with the given expression and a limit argument of zero. Trailing empty strings are therefore not included in the resulting array.
Just a hunch but your 'out of bounds exception' is likely due to your code assuming that there will be 26 entries in the array and there are really only 24.

Removing some songs at the same time

Hi, i've got a problem with my itunes, i've got my music all mixed up and moved atleast 8 times all around the computer, but now the itunes has got about 7-8 copies of every song, and to remove these you have to select one by one to get them removed. I need something just to remove the ones that don't have a location or not working. I also tryed removing them all but then i'll loose my top rated list and this is about 95 songs and to put these back, it will take hours. So please if there is an option which i don't now about or another program that could sort that out, that would be great, please tell me as soon as possible. Thanks, Besho2005
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Go here
http://ottodestruct.com/blog/category/geekery/programmery/
Otto42 is a regular poster on discussions. He wrote some java scripts.
Get the FindDeadTracks and RemoveDeadTracks scripts, read his directions on downloading and using them, and run them.

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How can I remove the brackets in the middle of the string.

Hi,
This is String str = Hello (buntty and dumbu) how are you?
When I used String token[]=s.split(" "); it splits the string
Hello
(buntty
and
dumbu)
how
are
you?
I want the string str= Hello buntty and dumbu how are you?
Please help to remove that (brackets from the string.
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Buntty

Use String.replaceAll()

Some portion of phone screen not working.

I bought my iphone 4 in december 2011 from UK.
Its incurring a problem from past 2 weeks. Some portion in the middle is not working which disables me from using key 7, 8, 9 in the phone keypad of making calls. I tried reseting my phone but the problem still exists. Since I reside in India, I cant get it corrected from Apple service centre in India and there is no scope of me going UK by December 2012.
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Remove regular expression from a string

Hello,
I have a string like this
@1test;'"{input+
Please help me to remove special characters from the string.

A: remove regular expression from a string

Hi Krishna,
DATA : str TYPE STRING VALUE '@1test;"{}]input+',
            char,
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WHILE length > index.
char = str+index(1).
WRITE char.
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    REPLACE ALL OCCURRENCES OF '"' in str WITH ''. " characters "{}[] are not comparable
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    REPLACE ALL OCCURRENCES OF '}' in str WITH ''.
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Add or remove special char from '+-*/!`@#$%^&()_=[]{};' in if part as per your requirement.
Hope it meets your requirement.
Do not forget to mark helpful/correct if ma answer is useful .
Thanks,
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Extend the String Class

Is there a way to extend the string class? I know it's final, if i make my class final too would that work? I want to add some functionality to the string class, but I wanna be able to do concatination with the + operator and stuff like that. That's special to the String class.
Any help would be great.
Thanks.
Joe

Well, put your mind at easy with the fact that being
able to use the '+' operator on Strings is a design
flaw in Java. At least from a purist point of view...And from a pragmatist's point of view, it's a reasonable compromise, the benefit of which outweighs the downside. This is consistent with Java's goal as a good general-purpose language. It's not intended to be pure OO or pure anything else.

Would removing some rows cause Row Currency issues?

Here is my story
Clicking a link goes to a table. The table looked fine, scrolling to next page as expected. For some strange reason, I started getting row currency errors. So I added "EnableTokenValisdation=false" on pagedef. Then I realized that I could not scroll to the next page. It has like 50 records. However, when I try to go to the next set (or if try to View All records), I get no row found. Why? Help!
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Frank, I agree. I removed the kludge.
Now, how can this happen. I have a application that worked.
I remove some rows from the database using sqldeveloper.
I retry the same app and I get row currency errors. Is this a possibility and if so, what can be done or how can I find the problem?
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Addressing of part of the string in the container

Hello,
in a mail task I would like to print only some characters from a string - e.g. from second to tenth - is it possible to address some part of the string in the container as is usual in abap?
thx,
JJ

Hi,
Yes , it is possible. If you want to show only some part of the string value in mail description you can use normal abap string operations. For example: In Mail description if you want to show only a part variable VALUE. you can just use &VALUE+a(b)&. It will work !!
You can try it out !!
Regards
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I want to do this for the an entire array of clusters. I'm trying to use a for loop. Can't figure out how to parse the string portion of the enum into the string portion of the cluster.
Alternatively, I'd be happy if I could figure out some way to tie the enum to the array of clusters, but I figure that gets problematic.
DH
Solved!
Go to Solution.

Dark Hollow wrote:
OK, let's say that the enumerated type has N elements. I want to initialize an N element array of strings. How do I reference each string in the enumerated type to get to each string?
Easy way to do this is to use GetNumericInfo.vi, part of the Variant library, found in vi.lib\utility\VariantDataType\GetNumericInfo.vi. Wire your enumeration to the Variant input; one of the outputs is an array of the strings in the enumerated type.
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Using ps trying to remove an object from a picture, following steps but when object is removed area is replaced by another portion of the photo like someones face as opposed to what should normally be in the background

using PS on a regular computer windows 7 tryng to remove an object from a picture, following steps in the tutorial however when the object is removed it is replaced by another (unwanted) portion of the photo i.e. someones face instead of what would have normally been in the background

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Removing number appended at the end from a string field

Hi,
I have a string field which has numbers appended to its end. I need to remove the numbers and display only the string values.
The string is not of fixed length, and the numeric values can be single digit or 2 digits and might be separate by a space but not always.
Here is some sample data:
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Just a quick option is to use the REPLACE function, i.e.
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You just have to build it up a little more so it caters for numbers 0 - 9. At the moment it only works for numbers 1 - 3. Another way you could do this is write some code to loop through the length of the string looking at each individual character to test for a number.
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Cheers,
Chris

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Remove some portion of the String

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