Retrieve file name from full file path

I am trying to retrieve a file name from a path (ex. c:\temp\tes.txt) using the following code, but it is given me an error of "The method split(String) in the type String is not applicable for the arguments (char).
{code}
String filepath = item.getName();
String[] buf = filepath.split('/');
String filename = buf[buf.length-1];
{code}
I tried to use double quote instead of single quote, but it is not returning anything.
{code}
String[] buf = filepath.split("/");
{code}
Anyone knows why? Thanks.

How is this related to JDBC?
Anyway, is the path separator actually a forward slash? Isn't it a backward slash?
If you're using Apache Commons FileUpload (which I guess, the 'item.getName()' is recognizeable), then just read their FAQ: [http://commons.apache.org/fileupload/faq.html#whole-path-from-IE].

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Obtaining file name from the file path given

hi,
how to obtain file name from the file path given

Hi bharath,
1. PC_SPLIT_COMPLETE_FILENAME
2.
DATA : path LIKE pcfile-path.
DATA : extension(5) TYPE c.
path = filename.
CALL FUNCTION 'PC_SPLIT_COMPLETE_FILENAME'
EXPORTING
complete_filename = path
* CHECK_DOS_FORMAT =
IMPORTING
* DRIVE =
extension = extension
name = name
* NAME_WITH_EXT =
* PATH =
EXCEPTIONS
invalid_drive = 1
invalid_extension = 2
invalid_name = 3
invalid_path = 4
OTHERS = 5
regards,
amit m.

Get Logical file name from Physical file name

Hi everybody,
Please how can i get Logical file name from Physical file name ?
Thanks & Regards
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Hi,
What i want is to get Logical file name from Physical file name, and not the opposite (get Physical file name from Logical file name).
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How to fetch the Date column(or Month column) from the file name from the specified path in ODI 11g

Hi ALL,
Can any one help us regarding How to fecth the Date column(or month column) from the file name specified in the path in a generalized way .
For example :
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I would suggest using a piece of Jython code for this. Something like this...
import os
import os.path
filelist = os.listdir(E:\Accounting\documents\)
for file in filelist:
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You'd need to work out what to do with datestr next... perhaps write it to a table or update an ODI variable with it.
Hope this is of some help.

Getting file name from a file path

Hello
I have got a String called filePath and it holds: "C:\Documents and Settings\paul\MyDocuments\nihtd.txt".
What I want do is to have another String variable called fileName that will use the 'filePath' variable to return the name on the file (that been "nihtd.txt" for the example given) but it must work with any file path for any file type.
Can anyone help? I have tried various ways but with no success.
Many thanks
Paul

Hmm, I just ran across another distinction between doing this by creating a File object as opposed to doing this by analysing the String: performance.
I always thought that creation of file objects is relatively cheap, since the Filesystem is not actually accessed when you create a new File instance. Apparently that is not true, at least not if you are on Windows and the file is on another server. Something like new File(\\server\share\file.txt) will create network traffic on Windows. So if you only meant to use the File class for parsing text, you might want to think again.
I would be interested to know how the FileSystem class is implemented on different platforms. Do you know where I can read up on that?
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Read file name from Payload (File Adapter)

Hello experts,
with Receiver-File Adapter I want to save a specific file. Name is given in the xml payload. I use Variable Substitution.
My structure is like this:
<root>
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Hi,
Like pointed by you , your source strucutre,
<root>
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    </elements>
    <elements>
        <name>name2></name>
    </elements>
</root>
The target strucuture after mutlimapping will be like,
My structure is like this:
<root>
    <elements>
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   </root>
Now, using Variable Name substitution, you will have the "name " element at a fixed level always , <b> payload:root,1,elements,1,name,1</b> and so you Variable Name subsitution will also work fine.
Hope it clears,
Regards
Bhavesh

File name from a path

hi ,
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Smoke me a kipper, I'll be back before breakfast.
SQL> var extended_filepath varchar2(128)
SQL> exec :extended_filepath := '/this/is/a/path/to/a/file.txt'
PL/SQL procedure successfully completed.
SQL> select instr(:extended_filepath, '/', -1)
2 from dual
3 /
INSTR(:EXTENDED_FILEPATH,'/',-1)
21
SQL> select substr(:extended_filepath, instr(:extended_filepath, '/', -1) +1)
2 from dual
3 /
SUBSTR(:EXTENDED_FILEPATH,INSTR(:EXTENDED_FILEPATH,'/',-1)+1)
file.txt
SQL> Cheers, APC

Flat file name from Sender Side Dynamically into subject of Receiver Mail

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Leela

[svn] 4267: Change path to Assets.swf in eclipse . project file from full hardcoded path to use the FLEX_SDK variable as the base path .

Revision: 4267
Author: [email protected]
Date: 2008-12-09 10:32:36 -0800 (Tue, 09 Dec 2008)
Log Message:
Change path to Assets.swf in eclipse .project file from full hardcoded path to use the FLEX_SDK variable as the base path. There is still an issue with Assets.swf not getting referenced correctly. If you import the framework project from Blazeds/trunk into Eclipse and get an error related to Assets.swf or that says "Unable to export SWC oem" for the time being try right clicking on the framwork project in Eclipse and selecting properties. Then in the properties panel, select Flex Library Build Path and then the Assets tab. On the Assets tab, check the check box next to Assets.swf and click Ok. This usually fixes the reference for me.
Modified Paths:
blazeds/trunk/development/eclipse/projects/flex/3.0/framework/.project

Revision: 4267
Author: [email protected]
Date: 2008-12-09 10:32:36 -0800 (Tue, 09 Dec 2008)
Log Message:
Change path to Assets.swf in eclipse .project file from full hardcoded path to use the FLEX_SDK variable as the base path. There is still an issue with Assets.swf not getting referenced correctly. If you import the framework project from Blazeds/trunk into Eclipse and get an error related to Assets.swf or that says "Unable to export SWC oem" for the time being try right clicking on the framwork project in Eclipse and selecting properties. Then in the properties panel, select Flex Library Build Path and then the Assets tab. On the Assets tab, check the check box next to Assets.swf and click Ok. This usually fixes the reference for me.
Modified Paths:
blazeds/trunk/development/eclipse/projects/flex/3.0/framework/.project

Seperating file name from the path

Hi,
im trying to validate the file path and trying to seperate file name from the path.
for eg.
if the path is f:\sapfilepath\doc\ext.txt
need to get f:\sapfilepath\doc im looking for a dynamic way of doing this.
your help will be appreciated.
Regards,
ravi.

Hi,
Use the function module
SO_SPLIT_FILE_AND_PATH
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Naren

Need to extract only file name from path.........

Hi All,
I have a parameter.This calls the function
"CALL FUNCTION 'F4_FILENAME' to get the file from C drive.
After selecting the file the path is displayed in the Parameter field.
My problem is I need to extract only file name from the path.Please advice.
Example : Prameter id    C:\folder\file.xls
I shd extract only file.xls from the path.Please advice.

Hi,
Use the below logic:
data: begin of itab,
           val    type char20,
        end of itab.
SPLIT l_f_path AT '\' INTO TABLE itab.
The last record of the internal table holds the file name.
describe table itab lines l_f_lines.
read itab index l_f_lines.
l_f_filaname = itab-val.
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How to get the target file name from an URL?

Hi there,
I am trying to download data from an URL and save the content in a file that have the same name as the file on the server. In some way, what I want to do is pretty similar to what you can do when you do a right click on a link in Internet Explorer (or any other web browser) and choose "save target as".
If the URL is a direct link to the file (for example: http://java.sun.com/images/e8_java_logo_red.jpg ), I do not have any problem:
URL url = new URL("http://java.sun.com/images/e8_java_logo_red.jpg");
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// Copy resource to local file
InputStream is = url.openStream();
FileOutputStream fos=null;
String fileName = null;
StringTokenizer st=new StringTokenizer(url.getFile(), "/");
while (st.hasMoreTokens())
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File localFile= new File(System.getProperty("user.dir"), fileName);
fos = new FileOutputStream(localFile);
try {
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        fos.write(buf, 0, i);
} catch (Throwable e) {
    e.printStackTrace();
} finally {
    if (is != null)
        is.close();
    if (fos != null)
        fos.close();
}Everything is fine, the file name I get is "e8_java_logo_red.jpg", which is what I expect to get.
However, if the URL is an indirect link to the file (for example: http://javadl.sun.com/webapps/download/AutoDL?BundleId=37719 , which link to a file named JavaSetup6u18-rv.exe ), the similar code return AutoDL?BundleId=37719 as file name, when I would like to have JavaSetup6u18-rv.exe .
URL url = new URL("http://javadl.sun.com/webapps/download/AutoDL?BundleId=37719");
System.out.println("Opening connection to " + url + "...");
// Copy resource to local file
InputStream is = url.openStream();
FileOutputStream fos=null;
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StringTokenizer st=new StringTokenizer(url.getFile(), "/");
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System.out.println("The file name will be: " + fileName);
File localFile= new File(System.getProperty("user.dir"), fileName);
fos = new FileOutputStream(localFile);
try {
    byte[] buf = new byte[1024];
    int i = 0;
    while ((i = is.read(buf)) != -1) {
        fos.write(buf, 0, i);
} catch (Throwable e) {
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} finally {
    if (is != null)
        is.close();
    if (fos != null)
        fos.close();
}Do you know how I can do that.
Thanks for your help
// JB
Edited by: jb-from-sydney on Feb 9, 2010 10:37 PM

Thanks for your answer.
By following your idea, I found out that one of the header ( content-disposition ) can contain the name to be used if the file is downloaded. Here is the full code that allow you to download locally a file on the Internet:
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      * @param url - the url.
      * @param destinationFolder - The destination folder.
      * @return the file
      * @throws IOException Signals that an I/O exception has occurred.
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          FileOutputStream fos = null;
          String fileName = getFileName(urlC);
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          fos = new FileOutputStream(localFile);
          try {
               byte[] buf = new byte[1024];
               int i = 0;
               while ((i = is.read(buf)) != -1) {
                    fos.write(buf, 0, i);
          } finally {
               if (is != null)
                    is.close();
               if (fos != null)
                    fos.close();
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      * Returns the file name associated to an url connection.<br />
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      * <p>
      * See <a
      * href="http://www.w3.org/Protocols/rfc2616/rfc2616-sec19.html">http:
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Hi,
I have built a ODI package with the following steps:
1. ODI is polling for a flat file in a Unix directory. I have used OdiFileWait tool for this purpose. Here the file name is not fixed, so I am using wild character (*) to poll for file. Example: DF*ABC1*.DAT where the first wild character denotes 1 letter and the second wild character denotes 2 digits.
2. In the second step, if the file is found, I am moving the file to ODI file server path (../oracledi/demo/file). Here I have used ODIFileMove tool.
3. Then I am using an ODI Interface to Load the file data into a Oracle database table.
4. I am using a Process log table to keep the log for each step I am executing in ODI that is ODIFileWait, ODIFileMove, Interface etc. for each file. In this table a row needs to be inserted after ODIFileWait tool gets the file, with the File Name and File Date. Later on this row will be updated as the consequent steps are executed.
Here is my concern, I need to get the exact File Name of the file after ODIFileWait gets the file and I need to insert that in the Process Log table after the ODIFileWait step gets a file. So if I can store the File Name in a ODI Variable, I can insert it into the Process log table at this point. This I am not able to do.
The files are coming in a different directory (not in ODI file server path), So after getting the file it is moved to ODI file server path (../oracledi/demo/file)
The Files which I am processing are fixed length format. Also, the File name and File Date is stored in the 1st Record(Header record) of the files.
Kindly provide me suggestions to implement this in my code.
Thanks and Regards,
Anik
Edited by: 809820 on Nov 10, 2010 11:36 PM

Look at this link -http://odiexperts.com/getting-one-or-several-unknown-files-from-a-directory
change the command to fetch the ls command and write into File and then using either java or jython break the data and fetch the file name and date and insert into log table.
(or)
you can use the os.system command and get the complete ls command into string and then process and insert it.
Let us know if you need any other help.

How to delete file names from Adobe Reader list

How can I delete file names from the Adobe Reader list? I have deleted the file & it's empty, but deleted file names remain in my list & it's very annoying. I can't seem to find an option anywhere to delete the file names.

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How can I assign image file name from Main() class

I am trying to create library class which will be accessed and used by different applications (with different image files to be assigned). So, what image file to call should be determined by and in the Main class.
Here is the Main class
import org.me.lib.MyJNIWindowClass;
public class Main {
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Your problem is one of timing. Consider this simple example.
public class Example {
    public String s;
    private String message = "Hello, " + s;
    public String toString() {
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    public static void main(String[] args) {
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        ex.s = "world";
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}When this code is executed, the following happens in order:
1. new Example() is executed, causing an object to constructed. In particular:
2. field s is given value null (since no value is explicitly assigned.
3. field message is given value "Hello, null"
4. Back in method main, field s is now given value "world", but that
doesn't change message.
5. Finally, "Hello, null" is output.
The following fixes the above example:
public class Example {
    private String message;
    public Example(String name) {
        message = "Hello, " + name;
    public String toString() {
        return message;
    public static void main(String[] args) {
        Example ex = new Example("world");
        System.out.println(ex.toString());
}

Retrieve file name from full file path

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