Rounding of attendance hours

Hi experts,
In the system, rounding of the attendance hours is done. If a person works for two shifts in a day, the rounding is done individually. But the requirement is the rounding is to be done after taking the total of these attendance hours.
For example    attendance hr in first shift is 8.20 (rounded to 8)
          Attendace hr in second shift is 6.15 (rounded to 6)
                        Total is 14 hours
But the requirement is                8.20 + 6.16 = 14.36 (rounded to 15)
             Because the range 0.25 to 1 will be rounded to 1.
How can I achieve this in table TIP in Time eval? Please advise.
Thanks

Hello Mohammed,
Straight answer is no, reason is there is no such concept of rounding in time type. As we are aware TIP table is used for pair formations based on the working times which is further processed for determing the processing type / time types for the time pair. Once we do this determination Balances are formed in Time TypesThis all depends how are you treating the work hours, to be more clear what are the total planned hours / overtime hours for the employee. Whther the employee is working 1 shift or 2shifts for one single day.
Hope this clarifies your doubt.
Regards,
Tara

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Newcomer to numbers.. I can't seem to get my roundup logic working.
To break this into steps, it's a time analysis, but I seem to be missing something
c2=10:00
c3=10:20
goal is to have the equation return .5 here
I'd like to break down the logic I'm trying to use if you will all humour me.
Display a time difference as a decimal
=DUR2HOURS(c3-c2)
The output is as expected, .333333333333
Round that time difference up and limit to 2 places
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Sorry for such a basic question, I, in pursuit of learning numbers, want to understand why I'm doing this, not just stumble upon it.
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What are you thinking to be wrong in your result.
You are calculating :
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I really don't understand what you are wanting to achieve.
My first thought was that you wished to convert .3333333 in minutes but it's so trivial that I assume that I thought wrongly.
Just for info to convert a decimal hour in minutes, you just need to muliply the decimal value by 60.
h00ligan76 wrote:
To break this into steps, it's a time analysis, but I seem to be missing something
c2=10:00
c3=10:20
goal is to have the equation return .5 here
I really don't understand which kind of equation may return .5 starting from the two given values except maybe :
=ROUNDUP(DUR2HOURS(C3-C2)*4,0)/4
which return
.25 if the difference is in the range 0 minute < C3-C2 ≤ 15 minutes
.50 if the difference is in the range 15 minutes < C3-C2 ≤ 30 minutes
.75 if the difference is in the range 30 minutes < C3-C2 ≤ 45 minutes
1.0 if the difference is in the range 45 minutes < C3-C2 ≤ 60 minutes
Yvan KOENIG (VALLAURIS, France) mercredi 25 janvier 2012
iMac 21”5, i7, 2.8 GHz, 12 Gbytes, 1 Tbytes, mac OS X 10.6.8 and 10.7.2
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Edited by: gka2707 on Jun 10, 2010 2:28 PM
Edited by: gka2707 on Jun 10, 2010 2:29 PM
Edited by: gka2707 on Jun 10, 2010 2:31 PM

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I want to enter 6.51 attendance hours in infotype 2002. But when i do that it changes it to 6.52. Please help me . I havent specified any rounding rules in my configuration. I have tried changing work schedules, checking attendance counting rules and changing it...Nothing helped....Please help me...How can i solve my problem.
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Hi Sagarika
This is calculated as follows
Entered time:                     0.01 hours   = 60/100 minutes
Rounded duration in minutes:      1    minute =   1/60 hours
Rounded result:                   0.02 hours
As I understand it this is standard behviour in HR Time Management (and any CA-TS profile that transfers data to HR)
Best regards
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