SCCM Query for any PC with 2 partitions?

I'm trying to find a query that will allow me to tell any computer in our network that has 2 partitions.  When we deploy our Win7 through SCCM it has only the 1 partition and doesn't have the 100MB partition that is created if you install via a CD. 
Problem is we have some old 7 computers that we need to find to change the way we deploy bitlocker and MBAM through SCCM and if i can find the ones with 2 partitions then I'll have a much easier job.  Does anyone know how to do that via SCCM?

Hi, This query will list all computers with a disk 0 parition 1, that should mean they have two partitions. I got some strange result on one of my HP Laptops though which had 4, But you could give it a try.
select SMS_R_System.Name, SMS_G_System_PARTITION.DeviceID from SMS_R_System inner join SMS_G_System_PARTITION on SMS_G_System_PARTITION.ResourceId = SMS_R_System.ResourceId where SMS_G_System_PARTITION.DeviceID = "Disk #0, Partition #1"
Regards,
jörgen
-- My System Center blog ccmexec.com -- Twitter @ccmexec

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    where so.type in (''FN'', ''FS'', ''FT'', ''TF'', ''IF'')
    and d.class in (0,1)
    and d.referenced_major_id <> object_id(@base_table, ''U'')
    and d.object_id = object_id(@constraint, ''D'')',N'@base_table nvarchar(517),@constraint nvarchar(517)',@base_table=N'[dbo].[repTable]',@constraint=N'[dbo].[DF__repTable__id__117F9D94]'
    exec sp_executesql N'
    select so.name, schema_name(so.schema_id)
    from sys.sql_dependencies d
    inner join sys.objects so
    on d.referenced_major_id = so.object_id
    where so.type in (''FN'', ''FS'', ''FT'', ''TF'', ''IF'')
    and d.class in (0,1)
    and d.referenced_major_id <> object_id(@base_table, ''U'')
    and d.object_id = object_id(@constraint, ''D'')',N'@base_table nvarchar(517),@constraint nvarchar(517)',@base_table=N'[dbo].[repTable]',@constraint=N'[dbo].[DF__repTable__somein__1367E606]'
    Pauly C

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