Select / how to select row that meet only one of select-options

Hello ,
I am developing rapport in release 6.0.
On the screen I have three select -options s1 , s2 , s3
I db table I have several entries with values in f1 f2 and f3
f1 f2 f3
1 | 2 |
3 | 4 |
5 | 6 |
a | b | c
When I enter , on screen 1 in S1 , and c in f3 i do not get any data in internal table . Obviously program is looking
for the row that satisfies   both criteria .
My question is what would be the way to get for same screen entry all row satisfying firs criteria and all lines satisfying
second criteria independently . SO i would like to have row 1|2 and row a|b|c if user enters , value "1" in s1 and value "c" in s3.
Thanks
source code .
select * from db_tab
into corresponding fields of table Itab
where f1 in s1 and
            f2 in s2 and
            f3 in s3.

Hello ,
I was thinkinf of OR , but i doesnt work .
When use enter only S3 and leave empty S1 the resul will be ALL entries from db table .
S1 = initial
S = c
result is
1|2
3|4
5|6
a|b|c
Thank you

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