Select the max record on date, but not today

Question

Hi all,
I have this table
Access
codi_uten number(9)
data_acce DATE
and for
select data_acce from Access
the codi_uten=3041
order by data_acce;
this is the result
DATA_ACCE
29-OTT-07
05-NOV-07
09-NOV-07
09-NOV-07
09-NOV-07
16-NOV-07
23-NOV-07
23-NOV-07
20-DIC-07
20-DIC-07
Where 20-Dic-07 is today ;)
I need a statment that can give me only the last data value (in this format dd/mm/yyyy) but it cannot consider today.
It's possible without use the RowId?
Thank's
Paolo from Madrid

Answer 1

No, you don't need rowids.
Creating an example table:
create table t
( id number primary key,
  day  date);
insert into t values(1, sysdate);
insert into t values(2, sysdate-1);
insert into t values(3, sysdate-2);
insert into t values(4, sysdate-3);Looking all rows:
select * from t
ID                                       DAY                 
1                                        12/20/2007 10:24:28 A
2                                        12/19/2007 10:24:28 A
3                                        12/18/2007 10:24:28 A
4                                        12/17/2007 10:24:28 A
4 rows selectedFind the last row, except rows with day = today
select *
from t
where day = (select max(day)
           from t
             where day < trunc(sysdate))
ID                                       DAY                 
2                                        12/19/2007 10:24:28 AAnd, finally, formating the data
select id, to_char(day, 'dd/mm/yyyy')
from t
where day = (select max(day)
           from t
             where day < trunc(sysdate))
ID                                       TO_CHAR(DAY,'DD/MM/YYYY')
2                                        19/12/2007      Merry Xmas,
Miguel