Need to select the max record in a report

Dear All,
I have a certain report which displays the employee records along with their 'empids' and their 'beginning date'. For each 'empid', there are more than one records and hence more than one 'beginning date'. I need to select that record which contains the maximum 'beginning date'. How can this be possible in the reporting level without doing any coding in update rules or writing any exit ?
Regards,
Srinivas

Hi,
I think it is not possible because i am having doubt how the for each employ id how it will be different joining dates,i think for each employ having differeent joining dates ,if u want to see maximum number of employs in which in company then we can go for the only option non cumulative kf with maximum value with ur joining date as the reference.but it report level if it is keyfigure we can have options of maximum and minimum and like that we can do but in case of characterstic like employnumber and joiningdate both are characterstics.
Thanks
sathsih

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Select the max record on date, but not today

Hi all,
I have this table
Access
codi_uten number(9)
data_acce DATE
and for
select data_acce from Access
the codi_uten=3041
order by data_acce;
this is the result
DATA_ACCE
29-OTT-07
05-NOV-07
09-NOV-07
09-NOV-07
09-NOV-07
16-NOV-07
23-NOV-07
23-NOV-07
20-DIC-07
20-DIC-07
Where 20-Dic-07 is today ;)
I need a statment that can give me only the last data value (in this format dd/mm/yyyy) but it cannot consider today.
It's possible without use the RowId?
Thank's
Paolo from Madrid

No, you don't need rowids.
Creating an example table:
create table t
( id number primary key,
day date);
insert into t values(1, sysdate);
insert into t values(2, sysdate-1);
insert into t values(3, sysdate-2);
insert into t values(4, sysdate-3);Looking all rows:
select * from t
ID                                       DAY
1                                        12/20/2007 10:24:28 A
2                                        12/19/2007 10:24:28 A
3                                        12/18/2007 10:24:28 A
4                                        12/17/2007 10:24:28 A
4 rows selectedFind the last row, except rows with day = today
select *
from t
where day = (select max(day)
           from t
             where day < trunc(sysdate))
ID                                       DAY
2                                        12/19/2007 10:24:28 AAnd, finally, formating the data
select id, to_char(day, 'dd/mm/yyyy')
from t
where day = (select max(day)
           from t
             where day < trunc(sysdate))
ID                                       TO_CHAR(DAY,'DD/MM/YYYY')
2                                        19/12/2007      Merry Xmas,
Miguel

Select the one record with the latest record

I have the following table called tblSales:
SKU   TransDate   Color
===   ====== ====
123   1/1/2015    Red
123   1/2/2015    Red
123   1/5/2015    Red
123   1/1/2015    White
123   1/2/2015    White
123   1/3/2015    White
123   1/1/2015    Blue
123   1/2/2015    Blue
123   1/5/2015    Blue
I need to create a query along the lines "SELECT the latest record FROM tblSales WHERE Color = 'White''
In this example, the record dated 1/3/2015 would be the result. I know that MAX(TransDate) is used here, but not sure how.
Thanks.
Ken

Karl,
I had already tried that. It returns all 3 records having SKU = 123 and Color = White.
Worst case scenario is I can always search for White 123s using a query with TransDate DESC and then get the first record. I was just hoping for something a bit more elegant.
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How to select the max rowid from a subquery with group by

Hi Gurus,
Kindly help how to fix the following query because I'm getting Oracle error:ORA-01446.
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Why do you need to compare with rowid?
Wouldn't this suffice?
select * from edy_raw_data a
where (email,date_updated) = (select email, max(date_updated) from edy_raw_data b
where b.email=a.email
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Regexp substr to select the max number out an string

Hi all,
I need a solution for a query.
I,ve a query to select the lowest number in a string.
select regexp_substr('9 - 10','\d+')
from dual;
9
So this is the query I need to select the min number in he string.
but now I need it to give me the highest nr in the string .
the output that I need =10
Can someone help me pleasse?
My regards

Caroline wrote:
select regexp_substr('9 - 10','\d+')
from dual;
9
So this is the query I need to select the min number in he string.Actually it only gives you the first number in the string, not the minimum number.
SQL> select regexp_substr('9 - 10','\d+')
2 from dual;
R
9If your string is the other way around it will give you 10 instead of 9.
SQL> ed
Wrote file afiedt.buf
1 select regexp_substr('10 - 9','\d+')
2* from dual
SQL> /
RE
10You probably want something like...
SQL> ed
Wrote file afiedt.buf
1 with t as (select '9 - 10' as txt from dual)
2 -- end of sample data
3 select min(num) as min_num, max(num) as max_num
4 from (
5        select to_number(trim(REGEXP_SUBSTR (txt, '[^-]+', 1, level))) as num
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8*      )
SQL> /
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         9         10
SQL> ed
Wrote file afiedt.buf
1 with t as (select '10 - 9' as txt from dual)
2 -- end of sample data
3 select min(num) as min_num, max(num) as max_num
4 from (
5        select to_number(trim(REGEXP_SUBSTR (txt, '[^-]+', 1, level))) as num
6        from t
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How to select the first record?

Hi,
Could anyone tell me how to select the first record of every
group?
ex, I want to find out every customer their first purcaseDate.
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A00000001 2001/01/01 AA
A00000001 2001/02/02 AA
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A00000003 2001/03/05 DD
result:
A00000001 2001/01/01 AA
A00000002 2001/03/01 AC
A00000003 2001/03/05 DD
Thanks

Vincent,
You could do it as Carl suggested, with a couple of
corrections. You would need to include the CustomNo column in
the order by clause of your cursor. You would also need to add
a where clause to your update statement, otherwise everywhere
Region in the table would be updated with the same value of the
last CustomNo in the cursor, regardless of the CustomNo in the
table. See corrected code below:
DECLARE
CURSOR     cust
IS
SELECT     DISTINCT CustomNo, Region, Purchase_Date
FROM       my_table
ORDER BY   CustomNo, Purchase_Date, Region;
c_customer VARCHAR2 (9) := '...';
c_region   VARCHAR2 (2) := '..';
cntr       NUMBER := 0;
BEGIN
FOR x IN cust
LOOP
    IF x.CustomNo != c_customer
    THEN
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      c_region := x.Region;
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      cntr := cntr + 1;
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      THEN
        COMMIT;
        cntr := 0;
      END IF;
    END IF;
END LOOP;
COMMIT;
EXCEPTION
WHEN OTHERS THEN
    NULL;
END;
Another option is that you could just use one update statement,
like this:
UPDATE my_table a
SET    Region =
       (SELECT DISTINCT Region
        FROM   my_table b
        WHERE (CustomNo, Purchase_Date) IN
               (SELECT   CustomNo, MIN (Purchase_Date)
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Please click the Mark as Answer button if a post solves your problem!

1,May I know do we need to create the mx records if we send/receive the mail in the same organization?
2,If we send /receive the mail between two different organization/forest, we need to create the mx records ,is it right?
Please click the Mark as Answer button if a post solves your problem!
for 1. If you mean the same Exchange org, no.
For 2, it depends. You need a MX record for your receiving SMTP server ( At least, You *should* have one), but if sending to another org, not necessarily, as you could smarthost messages to it and a MX would not be required.
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The problem with Etisalat is that they outsourced that service to another company called Technocare.
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I need to Delete the empty space page of report

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http://imageshack.com/a/img540/191/nrOwz6.jpg
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Hi yha10,
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Right click the row group to select the "Group Properties" and add page break by check the "Between each instance of a group":
Right click the first column which the Group located and select the Insert Row-Inside Group-Below:
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How to get the max record

how to get the record with the max sequence no
table as
seq student mark
1 A 10
2 A 15
1 B 20
2 B 10
1 C 30
here is what i need
seq student mark
2 A 15
2 B 10
1 C 30

i have used your query + some decode
With t As
Select 'A' st, 'X' Type,    1 seq,   001 marker_no, 10 mark From dual Union All
Select 'A', 'X',    2,   001,       12 From dual Union All
Select 'B', 'X',    1,   002,       10 From dual Union All
Select 'B', 'X',    2,   003,       12 From dual Union All
Select 'B', 'X',    3,   003,       15 From dual Union All
Select 'C', 'X',    1,   001,       10 From dual Union All
Select 'C', 'X',    2,   002,       15 From dual Union All
Select 'C', 'Y',    3,   001,       20 From dual Union All
Select 'C', 'Y',    4,   001,       10 From dual
Select st,
       Sum (x_cnt) x_cnt,
       Max (x_seq) Keep (dense_rank Last Order By x_seq) x_seq,
       max(x_marker_no) keep(dense_rank last order by x_seq) x_marker_no,
       max(x_mark) keep(dense_rank last order by x_seq) x_mark,
       sum(y_cnt) y_cnt,
       max(y_seq) keep(dense_rank last order by y_seq) y_seq,
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st X_cnt X_seq X_marker_no X_mark Y_cnt Y_seq Y_marker_no Y_mark
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Need to fetch the last record/row from a table

Hi,
I have a requirement like fetching the closing balance of the last record of the table and inserting the same into the opening balance of the immediatetly created next record.
In simple words, I need to fetch a value from the last row of the record.
For example, I use the below query,
select rownum, empno, ename from emp
where rownum = (select count(rownum) from emp);
But, the above query does not return any of the record.
Hence, need help on this.
Regards,
Shivakumar A
Edited by: shiva on Mar 27, 2011 10:14 PM

Rows in a table are inherently unordered. In order to introduce the concept of "first" and "last", you would need to specify how to order the rows which would require that there was one or more columns in the table that you could order by in order to determine the "last" record.
In your closing balance example, if we assume that there is something like a BALANCE_DATE column,
SELECT account_number, balance_amount, balance_date
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           balance_date,
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      FROM table_of_balances )
WHERE rnk = 1Justin

Compare Dates and select the max date ?

Hello,
I am trying to write a script and will compare the dates in " eff_startdt" and give me the lastest date at the outcome.
I have data that some service locations have more than one contract date and I need to get the latest dated conract dates to work on the data but I tried many things I am always getting errors. When I run the script below I get " missing expression" error. I dont' see anything missing.
also somehow Max() is keep giving me errors when I do something like [ ON service_locs = vmeterid WHERE SERVICE_LOCS = SERVICE_LOCS AND EFF_STARTDT = MAX(EFF_STARTDT) ]
Can someone pls give me advice on this. Thanks
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FROM VMETER
INNER JOIN BROKER_DATA
ON service_locs = vmeterid WHERE SERVICE_LOCS = SERVICE_LOCS AND (SELECT MAX(EFF_STARTDT) FROM VMETER)
-----------------------------------------------------------

Hi,
I will try to explain on my example. I have got a table:
DESC SOLD_ITEMS;
Name                                    Value NULL? Type
COMPONENT                                          VARCHAR2(255)
SUBCOMPONENT                                       VARCHAR2(255)
YEAR                                               NUMBER(4)
MONTH                                              NUMBER(2)
DAY                                                NUMBER(2)
DEFECTS                                            NUMBER(10)
DESCRIPTION                                        VARCHAR2(200)
SALE_DATE                                          DATE
COMP_ID                                            NUMBERI have insert example data into my table:
select component, subcomponent, sale_date,comp_id
2 from sold_items;
COMPONENT       SUBCOMPONENT    SALE_DAT    COMP_ID
graph           bar             06/04/03          1
graph           bar             06/04/01          2
search          user search     06/04/02          3
search          user search     06/04/01          4
search          product search 06/03/20          5
search          product search 06/03/16          6
graph           bar             06/05/01          7
graph           bar             06/05/02          8
graph           bar             06/05/02          9
As you can see there are a few components and subcomponents duplicated with different date and comp_id value.
I want to get component and subcomponent combination with latest date.
SELECT COMPONENT, SUBCOMPONENT, MAX(SALE_DATE)
2 FROM SOLD_ITEMS
3* GROUP BY COMPONENT, SUBCOMPONENT;
Efect:
COMPONENT       SUBCOMPONENT    MAX(SALE
graph           bar             06/05/02
search          user search     06/04/02
search          product search 06/03/20
For your purpose I will do it using join and subquery. Maybe it will help you resolve your problem:
SELECT COMPONENT, SUBCOMPONENT, SALE_DATE, RANK
2 FROM (SELECT T1.COMPONENT, T1.SUBCOMPONENT, T2.SALE_DATE,
3          ROW_NUMBER() OVER (PARTITION BY T1.COMPONENT, T2.SUBCOMPONENT ORDER BY T2.SALE_DATE DESC) AS ROW
4          FROM SOLD_ITEMS T1, SOLD_ITEMS T2
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Results:
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graph           bar             06/05/02          1
search          product search 06/03/20          1
search          user search     06/04/02          1Hope this help you
Peter D.

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Need to select the max record in a report

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