Send two signals at the same time to serial

Hi
I have a problem in that I want to control some relay boards by serial. The boards have an address byte (to determine which of the three relay boards) and a relay combination (four relays on each board). The .vi I will need to make will be sending data to the serial as a result of feedback from sensors (they are currently simply controlled by timers to simulate) so there is a good chance that there will be two relay addresses sent at the same time and consequently much confusion. The timed simulation demonstrates this possibility by switching all relays on at the start.
Is there a way of avoiding this? Any help would be much appreciated.
Many thanks
Alastair

Alastair,
When you say send to multiple boards "at the same time" exactly what to you mean? On a serial port only one byte at a time can be sent. You do not specify how many bytes are sent to each board to handle the addressing, the data, and any EOT (End of Transmission) characters.
I can think of two possibilities.
1. Relays are slow. If the transmission rate is fast enough, you could send messages to all relays sequentially over the serial port but still have the appearance of simultaneous activation of the relays. If the relays switch in 10 ms and each command contains 6 bytes, sending the data at 115 kilobaud would take about 1.5 ms for three boards. This would likely be close enough to simultaneous for relays.
2. Add a command similar to the GPIB GET (Group Execute Trigger). All devices on the bus respond to this command by executing a previously stored command. No addressing is used for this command. This does require that the relay boards be modified to respond to their address and to the common or group address and to store a command for later execution.
Lynn

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Generat two signals at the same time and reading voltage

Hii
i have try to generate two signals at the same time and read voltage from another port on the board(not have to be at the same time), i have not alot of expriens in labview
and i based my code of example(http://zone.ni.com/devzone/cda/epd/p/id/5197) from yours site and try to suit to my needs
now my problem is when i generat the 2 signals(that work perfect) i canot read voltage from another port on my CB-68LP
i can not find the problem and make it over i hope there is away to figer out and fix it.
i have two cards 6229, and two CB-68LP board.
labview 8.5.
my code is look like this - http://img142.imageshack.us/my.php?image=scrennshot2no2.png
(this works perfect).
and this is my code after suit to my need - http://img183.imageshack.us/my.php?image=scrennshotfl5.png,there is error exception at the right side.
the exception-
Possible reason(s):
Specified route cannot be satisfied, because it requires resources that are currently in use by another route.
Property: RefClk.Src
Source Device: Dev1
Source Terminal: 10MHzRefClock
Required Resources in Use by
Task Name: _unnamedTask<0>
Source Device: Dev1
Source Terminal: None
Destination Device: Dev1
Destination Terminal: RefClock
Task Name: _unnamedTask<1>
eyal

sorry...
The AO tasks is very important they will be synchronize ,it is very importent the two tasks will start at the same time
and after it run at synchronize mode i will need to make reading of voltage
i gust try to make simulation of machin (i give that machin AO and reading from it voltage that all)
first of all i make the two signals(synchronize signals).
and after it i will need to reading voltage.
i can make two signals synchronize together.
i can make reading voltage
but i can't make two signals synchronize together with reading voltage
it throw to me this error message.
i am looking for away to figer this out.
thank's for any help
eyal
Attachments:
test11.vi ‏130 KB

How to count frequency of two signal at the same time ?

Hello every one
please help me with this one i am really stuck.
The situation   : I have two square wave signal, and i want to measure the frequency of both of themat the same time.
the problem : Error -50103 occurred at DAQmx Read (Counter DBL 1Chan 1Samp).vi:3
Please see the attachement.
i also have 3 analog inputs to be measured.
but i dont have any problem with the analog inputs,,,multiple analog inputs can easily be measured,,,,,but the prob lem is in the digitl (square wave ) signals.
Attachments:
i want to use two counter input.GIF ‏54 KB
two counter tasks1.vi ‏250 KB

NI has an excellent overview of the accuracy and tradeoffs of the different freq measurement methods titled "Making Accurate Frequency Measurements." To boil down the essence of it, the (possibly) increased accuracy of the 2-counter method depends on a relatively long collection / accumulation time which would in turn typically limit the rate at which you could update your measured freq value.
Now let me offer some friendly but blunt advice. LabVIEW makes it easy to collect data. However, there are many other factors affecting the usefulness of that data. I support the dictum: "It is hard to measure *well*."  Choice of sensors, their sensitivity to environment, various sources of noise, an understanding of the decision to be made from the data, programming methods, etc. And even more etc.
What I mean is that just because a hardware freq measurement can be performed that is precise to 1 part per million, it would be very RARE in a test that ALL of those 6 significant digits prove useful. In your app, the measurements are presently only approximately correlated in time. And the gap of blind time between measurements will usually represent a much longer period of time than the measurement itself.
Analogy: suppose you had a 100 minute film at 25 frames/sec for a total of 150_000 frames. Now start selecting individual frames that are separated by some random # of frames between about 200 and 500. In the end, you may end up with a sequence of 400 frames in the correct order. Each individual frame is VERY accurate, but the collection of all of them can zip by in 16 seconds and not give you a much understanding about the movie.
What would usually work out much better is to sacrifice some accuracy in order to collect a greater quantity of frames. You trade off the instantaneous accuracy for the overall coherency.
Sorry, got on a roll...   Back to your question. My own preference is almost always to avoid consuming hardware resources when not truly necessary. I've been toying with counters for many years and have still never once deployed an app using a 2-counter frequency measurement. I do the 1-counter measurement and save the other counter(s) for other purposes.
If you've got an M-series board, the 80 MHz timebase allows you to measure a 500 kHz pulsetrain with a quantization error of only about 0.06% (1 part in 160). There's a pretty fair chance that whatever physical process emits that pulsetrain isn't appreciably more stable than that
-Kevin P.

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I purchased 2 airport expresses today and the answer to this is yes

Telnet two devices at the same time 1 C# program

Hi, currently I have one 100% working program used to telnet my Arduino circuit.
I use this C# class found somewhere around the web: Anyway, without this forum, I wouldn't be able to finish my program.
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using System.Net.Sockets;
namespace USSR
enum Verbs
WILL = 251,
WONT = 252,
DO = 253,
DONT = 254,
IAC = 255
enum Options
SGA = 3
class TelnetConnection
TcpClient tcpSocket;
int TimeOutMs = 100;
public TelnetConnection(string Hostname, int Port)
tcpSocket = new TcpClient(Hostname, Port);
public string Login(string Username, string Password, int LoginTimeOutMs)
int oldTimeOutMs = TimeOutMs;
TimeOutMs = LoginTimeOutMs;
string s = Read();
if (!s.TrimEnd().EndsWith(":"))
throw new Exception("Failed to connect : no login prompt");
WriteLine(Username);
s += Read();
if (!s.TrimEnd().EndsWith(":"))
throw new Exception("Failed to connect : no password prompt");
WriteLine(Password);
s += Read();
TimeOutMs = oldTimeOutMs;
return s;
public void WriteLine(string cmd)
Write(cmd + "\n");
public void Write(string cmd)
if (!tcpSocket.Connected) return;
byte[] buf = System.Text.ASCIIEncoding.ASCII.GetBytes(cmd.Replace("\0xFF", "\0xFF\0xFF"));
tcpSocket.GetStream().Write(buf, 0, buf.Length);
public string Read()
if (!tcpSocket.Connected) return null;
StringBuilder sb = new StringBuilder();
do
ParseTelnet(sb);
System.Threading.Thread.Sleep(TimeOutMs);
} while (tcpSocket.Available > 0);
return sb.ToString();
public bool IsConnected
get { return tcpSocket.Connected; }
void ParseTelnet(StringBuilder sb)
while (tcpSocket.Available > 0)
int input = tcpSocket.GetStream().ReadByte();
switch (input)
case -1:
break;
case (int)Verbs.IAC:
// interpret as command
int inputverb = tcpSocket.GetStream().ReadByte();
if (inputverb == -1) break;
switch (inputverb)
case (int)Verbs.IAC:
//literal IAC = 255 escaped, so append char 255 to string
sb.Append(inputverb);
break;
case (int)Verbs.DO:
case (int)Verbs.DONT:
case (int)Verbs.WILL:
case (int)Verbs.WONT:
// reply to all commands with "WONT", unless it is SGA (suppres go ahead)
int inputoption = tcpSocket.GetStream().ReadByte();
if (inputoption == -1) break;
tcpSocket.GetStream().WriteByte((byte)Verbs.IAC);
if (inputoption == (int)Options.SGA)
tcpSocket.GetStream().WriteByte(inputverb == (int)Verbs.DO ? (byte)Verbs.WILL : (byte)Verbs.DO);
else
tcpSocket.GetStream().WriteByte(inputverb == (int)Verbs.DO ? (byte)Verbs.WONT : (byte)Verbs.DONT);
tcpSocket.GetStream().WriteByte((byte)inputoption);
break;
default:
break;
break;
default:
sb.Append((char)input);
break;
My UI Code:
using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.IO;
using System.Linq;
using System.Net;
using System.Text;
using System.Threading.Tasks;
using System.Windows.Forms;
using System.Net.Sockets;
namespace USSR
public partial class mainForm : Form
TelnetConnection tc;
public bool keyPressChecker = false;
public bool connectedChecker = false;
public mainForm()
InitializeComponent();
// webBrowser1.Navigate("http://admin:[email protected]");
this.tc = null;
this.connectedChecker = false;
private void radioButton2_CheckedChanged(object sender, EventArgs e)
try
if (submarineRadioBtn.Checked)
System.Diagnostics.Process.Start("dummySub.exe");
catch (Exception ex)
MessageBox.Show(ex.ToString());
private void centerBtnCamera_Click(object sender, EventArgs e)
private void forwardBtn_Click(object sender, EventArgs e)
if (connectedChecker)
this.tc.WriteLine("W");
private void connectToolStripMenuItem1_Click(object sender, EventArgs e)
try
//create a new telnet connection
tc = new TelnetConnection("192.168.0.102", 23);
if (tc.IsConnected)
connectedChecker = true;
catch (Exception ex)
MessageBox.Show(ex.ToString());
private void controlKeyDownCheckBox_CheckedChanged(object sender, EventArgs e)
if (controlKeyDownCheckBox.Checked == true)
keyPressChecker = true;
else
keyPressChecker = false;
private void controlKeyDownCheckBox_KeyDown(object sender, KeyEventArgs e)
if (keyPressChecker == true)
if (e.KeyCode == Keys.W)
if (connectedChecker)
tc.WriteLine("W");
if (e.KeyCode == Keys.S)
if (connectedChecker)
tc.WriteLine("S");
private void reverseBtn_Click(object sender, EventArgs e)
if (connectedChecker)
tc.WriteLine("S");
private void disconnectToolStripMenuItem_Click(object sender, EventArgs e)
try
tc = null;
connectedChecker = false;
catch (Exception ex)
MessageBox.Show(ex.ToString());
private void controlKeyDownCheckBox_KeyUp(object sender, KeyEventArgs e)
if (keyPressChecker == true)
if (e.KeyCode == Keys.W)
if (connectedChecker)
tc.WriteLine("O"); //decrease to MID PT.
if (e.KeyCode == Keys.S)
if (connectedChecker)
tc.WriteLine("P"); //decrease speed to MID PT.
private void exitToolStripMenuItem_Click(object sender, EventArgs e)
Application.Exit();
Now, what I want to know is this: IS IT POSSIBLE FOR MY C# PROGRAM TO TELNET TWO DEVICES AT THE SAME TIME?
Thanks
Glenn

try this links :
http://www.codeproject.com/Articles/19071/Quick-tool-A-minimalistic-Telnet-library
http://stackoverflow.com/questions/25116077/send-and-receive-commands-via-telnet-in-c-sharp
http://stackoverflow.com/questions/12283241/ssh-to-server-then-telnet-to-device

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Explanation:
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www.ni.com/teststand
Ryan
Ryan
Applications Engineer
National Instruments

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Message Edited by Dennis Knutson on 03-20-200609:35 AM
Attachments:
Run Method.JPG ‏44 KB

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That's not true. WebLogic supports a non-secure and secure listener port at the
same time. That was one of the selling points for my organization.
Michael Girdley wrote:
If, you mean the same port on two different IP addresses, then the answer is
yes.
If, you mean two different ports on the same IP address, then the answer is
no.
Thanks,
Michael
Michael Girdley
Product Manager, WebLogic Server & Express
BEA Systems Inc
fxy <[email protected]> wrote in message
news:8fdk99$t9$[email protected]..
<URGENT QUESTION>
I'd like to know if weblogic can support two ports at the same time.
thank you in advance.
<URGENT QUESTION>

Well, the question was really meant to see if any change was made to WL to support
this, not because I didn't believe Michael Girdley.
P.S., this is something Websphere 4.0 let's you do...In case this encourages someone
to add this support.
"Mike Reiche" <[email protected]> wrote:
>
If you don't believe Michael Girdley, then I don't know why you would
believe anyone
else. I believe the answer is still 'no'.
Why do they 'have to be on different ports'? We block requests by URI
- so just
block all requests to /youradminapp/* at the firewall. Or you can block
them at
your Web Server. Or restrict them by user in WL.
Mike
you"Anil Arora" <[email protected]> wrote:
Is it still true that WL 6.0 cannot host multiple (non-secure) HTTPports
on one
server? We need this capability within one JVM to allow one web application
to
be accessed from one port while another through a second port. Forexample,
we
have a application to be exposed through the firewall at port 7001.
Then we have
another admin application to only be accessed within the firewall. But
they need
to be deployed within the same JVM since they may have shared statebetween
them.
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Anil
"Michael Girdley" <[email protected]> wrote:
I'm sorry, to clarify my statement: I was speaking about nonsecure
communications. Weblogic can only support one listener port at a time.
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Michael
Michael Girdley
Product Manager, WebLogic Server & Express
BEA Systems Inc
Allen Akers <[email protected]> wrote in message
news:[email protected]...
That's not true. WebLogic supports a non-secure and secure listenerport
at the
same time. That was one of the selling points for my organization.
Michael Girdley wrote:
If, you mean the same port on two different IP addresses, then
the
answer is
yes.
If, you mean two different ports on the same IP address, then theanswer
is
no.
Thanks,
Michael
Michael Girdley
Product Manager, WebLogic Server & Express
BEA Systems Inc
fxy <[email protected]> wrote in message
news:[email protected]...
<URGENT QUESTION>
I'd like to know if weblogic can support two ports at the same
time.
thank you in advance.
<URGENT QUESTION>

Send two signals at the same time to serial

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