Simple (probably) sqlldr question

I’m new to sqlldr, am having a problem, and would appreciate some help.
This is probably a easy problem for someone who is experienced.
The input data file looks has year and month of birth in the second position. For instance,
15|198101|4|20040204|20040204
means the person was born in 1981, in January.
The table I want to load wants person’s age in years, which goes into field 7.
A crude way of calculating the person’s age would be 2011 – 1981,
So I tried
     col7      POSITION(4:7)     EXPRESSION ”2011 – TO_NUMBER( SUBSTR(:col7,1,4),9 )“
For instance,
INTO TABLE TABLE1
     col1     POSITION(1:2)      CHAR,
     col2               CONSTANT 0,
     col3               CONSTANT "30-SEP-11",
     col4     POSITION(11:11) INTEGER EXTERNAL,
     col5     POSITION(13:20) "TO_DATE(:col5,'yyyymmdd')",
     col6     POSITION(22:29) "TO_DATE(:col6,'yyyymmdd')",
     col7      POSITION(4:7)     EXPRESSION ”2011 – TO_NUMBER( SUBSTR(:col7,1,4),9 )“
But that didn’t work. I tried various variations but they didn't work either.
Can anyone suggest the proper code?
Also, a more refined way would take the month into consideration, so that a person born
in Sept 1991 would today be 20 but one born in Dec 1991 would still be 19.
Can anyone suggest the proper code for that?
Thanks.

Hello user6071447.
I'm not sure what error you are getting, but here is an example of calculating age while loading using sqlldr with the sample data that you provided:LOAD DATA
APPEND
INTO TABLE test_table
age_in_years POSITION(4:9) "FLOOR(MONTHS_BETWEEN(SYSDATE, TO_DATE(:age_in_years, 'YYYYMM')) / 12)"
)If your looking for a little less accuracy, you can remove the month from the equation.
Hope this helps,
Luke
Please mark the answer as helpful or answered if it is so. If not, provide additional details.
Always try to provide actual or sample statements and the full text of errors along with error code to help the forum members help you better.

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