Simple tic tac toe

Question

heres my code: my question is at the bottom
import apcslib.*;
import chn.util.*;
public class TicTacToe
public static void main(String[] args)
//variables and objects
TicTac one = new TicTac();
SketchPad paper = new SketchPad(500,500);
DrawingTool pen = new DrawingTool(paper);
ConsoleIO console = new ConsoleIO();
System.out.print("Choose who's turn it is:");
String choose = console.readToken();
char variable = choose.charAt(0);
if(variable == 'O' || variable == 'o')
System.out.println("1: Top Left Corner");
System.out.println("2: Top Middle");
System.out.println("3: Top Right Corner");
System.out.println("4: Middle Left");
System.out.println("5: Middle");
System.out.println("6: Middle Right");
System.out.println("7: Bottem Left Corner");
System.out.println("8: Bottom Middle");
System.out.println("9: Bottom Right Corner");
System.out.print("Choose where you want to put your mark by picking its number:");
int choice = console.readInt();
if(choice == 1)
one.board(); //draws a tic tac toe board
one.circle(-120, 65); //draws a circle at that location
else if(choice == 2);
one.board();
one.circle(-50, 65);
now my question, if i input 1 it draws the circle but it then continues on and draws the second circle to without me telling it to. but if i skip right to drawing the second circle it does and ignores the first one. thanks in advance for any input

Answer 1

   if(choice == 1)
      one.board();   //draws a tic tac
      one.circle(-120, 65);  //draws a
   else if(choice == 2);
       one.board();
       one.circle(-50, 65);
   }   Take the semicolen off of the second condition. It should be " if ( choice == 2 ) { ". Otherwise, the compiler thinks there is nothing to be executed as the result of choice == 2, and the instructions to draw the second circle are a seperate block of code that gets executed regardless of whether the choice is one, two, or fifteen billion.