[Solve] Bash: Rename file in folder to sequential numbers saving path

Question

I have a folder with many subfolders with many files. I want to rename all files to sequential numbers (0001.jpg, 0002.jpg, .0003,jpg ...) but i want to save the path. I mean that the files should not be saved in the root directory (where i launched the script), but I want them to remain in original subdirectorys. How can i do this?
Last edited by cypherinside (2011-11-14 18:37:16)

Answer 1

cypherinside wrote:
for src in "$1"/*; do ## "$1"/*
are all the subdirectory. Can i use "$(pwd)/*" instead of "$1/*"? In this way i don't write the parent directory
If you want to specify $PWD, just call the script with an argument of '.' to point it at PWD.
cypherinside wrote:
if [[ -d $src ]];
walk "$src"
continue
fi
I dont' understand
It's simple recursion. You don't want to rename directories, you want to process the contents of the directory in the same way you're processing the current directory.
cypherinside wrote:
printf -v dest '%s/%04d.jpg' "$1" "$(( ++i ))"
Stores in dest... what? I assume that %s is a string as in C language, infact you give "$1" as argument (but why?). And I assume that  "$((++i))" is like i=$((i+1)). Is it right?
It's the bash equivalent of sprintf(3).
cypherinside wrote:
[[ $1 ]] || exit 1
I don't understand.
If $1 doesn't exist (i.e. you passed no arguments to the script), then refuse to run and exit immediately with an error.
You weren't really clear in your requirements, so I wrote it as I interpreted it. If you want to reset the numbering for each directory, scope 'i' locally:
#!/bin/bash
walk() {
local -i i=0
for src in "$1"/*; do
if [[ -d $src ]]; then
walk "$src"
continue
fi
printf -v dest '%s/%04d.jpg' "$1" "$(( ++i ))"
mv "$src" "$dest"
done
[[ $1 ]] || exit 1
walk "$1"