Sorting a combination of two longs using a comparator

Question

Hello to all,
I need to implement a comparator that will take as input an object containing two longs, combine them and sort them in the form a.b, where a is the first long and b the second, first by a and then by b. (eg.1.2, 2.8, 1.5, 2.4, 3.4, 3.3, etc... becomes 1.2, 1.5, 2.4, 2.8, 3.3, 3.4, etc..)
Is there a way to achieve this?
Thank you in advance!

Answer 1

like this?
class LongComparator implements Comparator {
  String delimiter;
  public LongComparator(String delimiter) {
    this.delimiter = delimiter;
  public int compare(Object o1, Object o2) {
    String[] s1 = ((String) o1).split(delimiter);
    String[] s2 = ((String) o2).split(delimiter);
    Long l1s1 = Long.valueOf(s1[0]);
    Long l2s1 = Long.valueOf(s1[1]);
    Long l1s2 = Long.valueOf(s2[0]);
    Long l2s2 = Long.valueOf(s2[1]);
    if (l1s1.compareTo(l1s2) == 0) {
      return l2s1.compareTo(l2s2);
    } else {
      return l1s1.compareTo(l1s2);
}