String concatenate

Question

i am trying to concatenate the string with a ; if it is not present.
But i am getting error...PLS-00363
Can somebody help me. Is there any other way of doing this.
Procedure Servstr(String1 IN varchar2 ......)
Begin
select nvl( nvl(length (String1),0) - nvl(length (replace (String1,';')),0),0) into v_cnt from dual;
If v_cnt<1 Then
String1:=String1||';';
End If;
End;
......

Answer 1

Hi,
If String1 is na IN parameter, then you can't change it.
Depending on what you want to do, you can make a local variable that starts out as a copy of String1, but can be changed. Declare it like this:
local_String1   VARCHAR2 (32767) := String1;
sunil_dba wrote:i am trying to concatenate the string with a ; if it is not present.
But i am getting error...PLS-00363
Can somebody help me. Is there any other way of doing this.
Procedure Servstr(String1 IN varchar2 ......)
Begin
select nvl( nvl(length (String1),0) - nvl(length (replace (String1,';')),0),0) into v_cnt from dual;In PL/SQL, you don't have to use the dual table very much.
The statement above can be done like this:
v_cnt := LENGTH ('X' || String1)
       - LENGTH (REPLACE ( 'X' || String1
             );Concatenating the 'X' guartantees that LENGTH will never return NULL.
Starting in Oracle 11, you can use REGEXP_COUNT to make it even simpler:
v_cnt := REGEXP_COUNT (String1, ';');However, if the only reason you are calculating v_cnt is to see if String1 contains a ';' or not, you can simply say
IF  String1  LIKE '%;%'  THEN
    ...