[Time].[Date].[Date] vs. [Time].[Date].Members in a Scope

Hi folks,
I'm just trying to understand how the subcubes are created using SCOPE.
Example 1:
SCOPE([Measures].[Credit Note CA]);
SCOPE([Date NextYear].[Date].[Date], [Time].[Date].Members, [Currencies].[Currency].[Currency]);
THIS = [Measures].[Credit Note LC] * [Measures].[Exchange Rate To Euro NY];
END SCOPE;
END SCOPE;
Example 2:
SCOPE([Measures].[Credit Note CA]);
SCOPE([Date NextYear].[Date].Members, [Time].[Date].Members, [Currencies].[Currency].[Currency]);
THIS = [Measures].[Credit Note LC] * [Measures].[Exchange Rate To Euro NY];
END SCOPE;
END SCOPE;
The difference between both examples is: [Date NextYear].[Date].[Date] vs. [Date NextYear].[Date].Members
If I use the 2nd one I get the results that I expected.
I should explain that the measure [Measures].[Credit Note LC] is related to the 3 dimensions: [Date NextYear], [Time] and [Currency], while the measure [Measures].[Exchange Rate To Euro NY] is only related to [Time] and [Currency].
The only different I can see if when I use the "Members" I get the set of members in the [Date] level, if not I get the same result + the All member, but I don't know exactly how this affect the subcube and my results.
Could anyone explain me that? I would really appreciate it.
Kind Regards,
Paul

Hi Paul ,
Using [Date NextYear].[Date].[Date] will return the Date members without the All member .
Using [Date NextYear].[Date].Members will return all members including the ALL member itself (assuming IsAggregatbla property set to true) .
Please refer the next short but well written post from chris webb about that topic :
http://cwebbbi.wordpress.com/2010/08/03/order-of-nested-scope-statements/
Regards, David .

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