To avoid putting a field in group by clause

hi all
i have the following query with me
SELECT   SUM ( (NVL (f.calc_cement_sk, f.calc_amount) * NVL (f.item_price, 0)
              - ( NVL (f.calc_cement_sk, f.calc_amount)
                 * NVL (f.item_price, 0)
                 * (NVL (f.dis_per, 0) / 100)
             ) total,
         h.slurry_type, h.stage_id, h.slurry_vol_actual
    FROM xxnp_opn_joblog_est_002 f,
         xxnp_opn_joblog_001 j,
         xxnp_opn_joblog_slurry_003 h,
         qp_secu_list_headers_v qw
   WHERE j.opn_job_desc = 'K/D/KD43/UG187/1338/D/0211/1'
     AND f.opn_joblog_001_id = j.opn_joblog_001_id
     AND j.contract = qw.NAME
     AND h.opn_joblog_001_id = j.opn_joblog_001_id
     AND h.opn_joblog_007_id = f.opn_joblog_007_id
     AND h.opn_joblog_006_id = f.opn_joblog_006_id
GROUP BY h.stage_id, h.slurry_type, h.slurry_vol_actualthe output i get is
TOTAL     SLURRY_TYPE     STAGE_ID     SLURRY_VOL_ACTUAL
9,562.59     Lead     1      490
2,184.84     Tail     1      80
1,091.73     Top Up     1      56
3,431.64     Tail     2      100
when i add f.item_number to the above query as shown below
SELECT   SUM ( (NVL (f.calc_cement_sk, f.calc_amount) * NVL (f.item_price, 0)
              - ( NVL (f.calc_cement_sk, f.calc_amount)
                 * NVL (f.item_price, 0)
                 * (NVL (f.dis_per, 0) / 100)
             ) total,f.item_number,
         h.slurry_type, h.stage_id, h.slurry_vol_actual
    FROM xxnp_opn_joblog_est_002 f,
         xxnp_opn_joblog_001 j,
         xxnp_opn_joblog_slurry_003 h,
         qp_secu_list_headers_v qw
   WHERE j.opn_job_desc = 'K/D/KD43/UG187/1338/D/0211/1'
     AND f.opn_joblog_001_id = j.opn_joblog_001_id
     AND j.contract = qw.NAME
     AND h.opn_joblog_001_id = j.opn_joblog_001_id
     AND h.opn_joblog_007_id = f.opn_joblog_007_id
     AND h.opn_joblog_006_id = f.opn_joblog_006_id
GROUP BY h.stage_id, h.slurry_type, h.slurry_vol_actual,f.item_number
the field total gets split and gives value corresponding to each item_number
i am giving the ouptut for stage 1TOTAL     ITEM_NUMBER     SLURRY_TYPE     STAGE_ID     SLURRY_VOL_ACTUAL
5011.5     1020101001     Lead      1     490
1308.93     1020102002     Lead      1     490
127.215     1020111001     Lead      1     490
138.92     1020112001     Lead      1     490
686     1020113001     Lead     1     490
550.5     1020113002     Lead 1     490
1739.52     1020222010     Lead      1     490
1517.1     1020101001     Tail     1     80
379.5     1020102003     Tail     1     80
83.2     1020103001      Tail     1     80
166.53     1020104001     Tail     1 80
38.511     1020111001     Tail     1     80
1064.7     1020101001     Top Up     1     56
27.027     1020111001     Top Up     1 56
if we sum values in total field corresponding to lead ,tail,top up we get 9562.59,2184.84,1091.73 respectively
kindly guide
to get total value as initial query even if item_number is added
thanking in advance
Edited by: makdutakdu on Jul 16, 2012 2:12 PM
Edited by: makdutakdu on Jul 16, 2012 2:14 PM
Edited by: makdutakdu on Jul 16, 2012 2:16 PM

hi
when i comment j.opn_job_desc = 'K/D/KD43/UG187/1338/D/0211/1'
this query returns value for all opn_job_desc and it gives incorrect value as h.slurry_type of lead ,tail ,top_up is there for all values of opn_job_desc
if i do partition by opn_job_desc i get sum of 5616.485
1091.727 and 9562.585 ie 16270.797
with t
as
SELECT   SUM ( (NVL (f.calc_cement_sk, f.calc_amount) * NVL (f.item_price, 0)
              - ( NVL (f.calc_cement_sk, f.calc_amount)
                 * NVL (f.item_price, 0)
                 * (NVL (f.dis_per, 0) / 100)
             ) total,f.item_number,
         h.slurry_type, h.stage_id, h.slurry_vol_actual,j.opn_job_desc
    FROM xxnp_opn_joblog_est_002 f,
         xxnp_opn_joblog_001 j,
         xxnp_opn_joblog_slurry_003 h,
         qp_secu_list_headers_v qw
   WHERE --j.opn_job_desc = 'K/D/KD43/UG187/1338/D/0211/1'
     f.opn_joblog_001_id = j.opn_joblog_001_id
     AND j.contract = qw.NAME
     AND h.opn_joblog_001_id = j.opn_joblog_001_id
     AND h.opn_joblog_007_id = f.opn_joblog_007_id
     AND h.opn_joblog_006_id = f.opn_joblog_006_id
GROUP BY h.stage_id, h.slurry_type, h.slurry_vol_actual,f.item_number,j.opn_job_desc
select sum(total) over(partition by opn_job_desc) total, item_number, slurry_type, stage_id, slurry_vol_actual,opn_job_desc
from tis there any way to include item_number in query but the total remains as such
kindly guide
thanking in advance
Edited by: makdutakdu on Jul 16, 2012 2:37 PM

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