Two billion record limit for non-partitioned HANA tables?

Is there a two billion record limit for non-partitioned HANA tables? I've seen discussion on SCN, but can't find any official SAP documentation.

Hi John,
Yes there is a limit for non-partitioned tables in HANA. In the first page of this document says: SAP HANA Database – Partitioning and Distribution of Large Tables
A non - partitioned table cannot store more than 2 billion rows. By using partitioning, this
limit may overcome by distributing the rows to several partitions. Please note, each partition must not contain more than 2 billion rows.
Cheers,
Sarhan.

Similar Messages

Is there a limit for the Account Transformation Table?

Hi Gurus,
I am anxious to know is there a limit for the or any particular number for maintaing Account Transformation table. 2) If many rules are existing in the Table, will it cause any performance issue.
Regards,
KumarMG

Hello Kumar,
I endorse the view expressed by Lokesh. Yes, there is no limit to the number of Account Transformation Rules that you can maintain in the Transformation Table. One way to limit this number is to use carefully maintained hierarchies instead of specifying individual accounts in the Rule. However, this is not always possible - but will help limit the number of entries in the Account Transformation Table. To create Cash Flow Satatement, you have to anyway use the Account Transformation Rule and surely this would stretch the number of entries in the table. For a complex requirement, these might extend to a few hundred entries. Performance will be an issue, no doubt.
Chakrapani

Partitioning Non-partitioned Exesting Tables

Hi all
i'm working with oracle apps 11i with db 8i
i have tables in GL module with rows inserted since 2003
i want to use a partitioning method to divide the tables
what are the statements i use to alter this tables in order to partition them ?
thanks

hi
A non-partitioned table can not be "converted" to a partitioned table. You will have to re-create your table with the appropriate partitioning clause
you can use this example
create table partemp(
empno number(4) not null,
ename varchar2(10),
job varchar2(9),
mgr number(4),
hiredate date,
sal number(7,2),
comm number(7,2),
deptno number(2))
partition by range(empno)
(partition partemp6 values less than (8000))
hope this helps
zekeriya
alter table partemp exchange partition partemp6 with table emp
alter table partemp split partition partemp6
at (7000)
into (partition partemp1,
partition partemp6)
alter table partemp split partition partemp6
at (7200)
into (partition partemp2,
partition partemp6)
alter table partemp split partition partemp6
at (7400)
into (partition partemp3,
partition partemp6)
alter table partemp split partition partemp6
at (7600)
into (partition partemp4,
partition partemp6)
alter table partemp split partition partemp6
at (7800)
into (partition partemp5,
partition partemp6)
/

Maximum record limit for internal table

hello all,
can any one tell me what is the maximum limit of internal table. i would like to add all records from bseg to internal table. so i can improve processing time.
thanks,
raj

hi,
Before Release 4.0A, ABAP stored the content of internal tables in a combination of main memory and file space. This means that the maximum size of all internal tables of all programs running on such an application server at one time is about 2 GB. With Release 4.0A or greater, this size decreases to about 500 MB. (Note that those values aren't fixed, but this is a good guide. This minimum of 500 MB is the lowest limit of the real value, which varies among different operating systems and even among different releases of the same operating system.)
It may sound strange that a newer release has a higher restriction on capacity. But it's a consequence of the fact that the contents of internal tables move from a reserved file to shared memory. When you process internal tables this way in Release 4.0A or greater, you pay for much better performance with a smaller potential size.
Regards,
Sourabh

Record Limit for a book

Hi experts,
from online help, it mentions that
"Any book can contain data, but for best performance, do the following:
Limit the record count to a maximum of 20,000 to 30,000."
Does that mean if we have more than 30,000 records in a book that SOD performance will be bad?
The problem is we have more than 100,000 records for each book....but we also do not want to compromise the performance.
Is there any solution to that?
Thanks,
Sab

Hi Bob,
Yes, I am using the search function on the left. I am searching for Home phone number *4491773.
But the system hang for about 5 minutes and then prompted this message:
Error: originating at /OnDemand/user/AccountList
This request was interrupted by another request by you. Please try your request again later. (RIP_WAIT_ERROR_CALCELLED).
I only did a single search at a time, not sure why it mentioned "another request".
Thanks,
Sab

Max record limit for Batch delete

Hi,
Is there a limit on the maximum number of records that can be deleted using the batch delete functionality?
If I select an Account list which has more than 200 records, so it covers more than one page of the list view. When I select batch delete, does that delete all the records or just the 100 records on the first page?
Regards,

The batch delete will delete all the records in the list. There is no upper limit on batch delete.
Edited by: bobb on May 4, 2011 7:30 AM

Move data from Non Partitioned Table to Partitioned Table

Hi Friends,
I am using Oracle 11.2.0.1 DB
Please let me know how can i copy /move the data from Non -Partitioned Oracle table to the currently created Partiotioned table.
Regards,
DB

839396 wrote:
Hi All,
Created Partitioned table but unable to copy the data from Non Partitioned table:
SQL> select * from sales;
SNO YEAR NAME
1 01-JAN-11 jan2011
1 01-FEB-11 feb2011
1 01-JAN-12 jan2012
1 01-FEB-12 feb2012
1 01-JAN-13 jan2013
1 01-FEB-13 feb2013into which partition should row immediately above ("01-FEB-13") be deposited?
[oracle@localhost ~]$ oerr ora 14400
14400, 00000, "inserted partition key does not map to any partition"
// *Cause: An attempt was made to insert a record into, a Range or Composite
//          Range object, with a concatenated partition key that is beyond
//          the concatenated partition bound list of the last partition -OR-
//          An attempt was made to insert a record into a List object with
//          a partition key that did not match the literal values specified
//          for any of the partitions.
// *Action: Do not insert the key. Or, add a partition capable of accepting
//          the key, Or add values matching the key to a partition specification>
6 rows selected.
>
SQL>
SQL> create table sales_part(sno number(3),year date,name varchar2(10))
2 partition by range(year)
3 (
4 partition p11 values less than (TO_DATE('01/JAN/2012','DD/MON/YYYY')),
5 partition p12 values less than (TO_DATE('01/JAN/2013','DD/MON/YYYY'))
6 );
Table created.
SQL> SELECT table_name,partition_name, num_rows FROM user_tab_partitions;
TABLE_NAME PARTITION_NAME NUM_ROWS
SALES_PART P11
SALES_PART P12
UNPAR_TABLE UNPAR_TABLE_12 776000
UNPAR_TABLE UNPAR_TABLE_15 5000
UNPAR_TABLE UNPAR_TABLE_MX 220000
SQL>
SQL> insert into sales_part select * from sales;
insert into sales_part select * from sales
ERROR at line 1:
ORA-14400: inserted partition key does not map to any partition
Regards,
DB

All rows in table do not qualify for specified partition

SQL> Alter Table ABC
2 Exchange Partition P1 With Table XYZ;
Table altered.
SQL> Alter Table ABC
2 Exchange Partition P2 With Table XYZ;
Exchange Partition P2 With Table XYZ
ERROR at line 2:
ORA-14099: all rows in table do not qualify for specified partition
The exchange partition works correct for the first time. However if we try to exchange 2nd partition it gives the error.
How do i solve this error?
How do i find rows which are not qualified for the specified portion. is there a query to find out the same?

stephen.b.fernandes wrote:
Is there another way?First of all, exchange is physical operation. It is not possible to append exchanged data. So solution would be to create archive table as partitioned and use non-partitioned intermediate table for exchange:
SQL> create table FLX_TIME1
2 (
3 ACCOUNT_CODE VARCHAR2(50) not null,
4 POSTING_DATE DATE not null
5 ) partition by range(POSTING_DATE) INTERVAL(NUMTOYMINTERVAL(1, 'MONTH'))
6 ( partition day0 values less than (TO_DATE('01-12-2012', 'DD-MM-YYYY') ) )
7 /
Table created.
SQL> create index FLX_TIME1_N1 on FLX_TIME1 (POSTING_DATE)
2 /
Index created.
SQL> create table FLX_TIME1_ARCHIVE
2 (
3 ACCOUNT_CODE VARCHAR2(50) not null,
4 POSTING_DATE DATE not null
5 ) partition by range(POSTING_DATE) INTERVAL(NUMTOYMINTERVAL(1, 'MONTH'))
6 ( partition day0 values less than (TO_DATE('01-12-2012', 'DD-MM-YYYY') ) )
7 /
Table created.
SQL> create table FLX_TIME2
2 (
3 ACCOUNT_CODE VARCHAR2(50) not null,
4 POSTING_DATE DATE not null
5 )
6 /
Table created.
SQL> Declare
2 days Number;
3 Begin
4 FOR days IN 1..50
5 Loop
6 insert into FLX_TIME1 values (days,sysdate+days);
7 End Loop;
8 commit;
9 END;
10 /
PL/SQL procedure successfully completed.
SQL> set linesize 132
SQL> select partition_name,high_value from user_tab_partitions where table_name='FLX_TIME1';
PARTITION_NAME                 HIGH_VALUE
DAY0                           TO_DATE(' 2012-12-01 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIAN')
SYS_P119                       TO_DATE(' 2013-01-01 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIAN')
SYS_P120                       TO_DATE(' 2013-02-01 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIAN')
Now we need to echange partition SYS_P119 to FLX_TIME2 and then echange FLX_TIME2 into FLX_TIME1_ARCHIVE:
To exchange it with FLX_TIME2:
SQL> truncate table FLX_TIME2;
Table truncated.
SQL> alter table FLX_TIME1 exchange partition SYS_P119 with table FLX_TIME2;
Table altered.To exchange FLX_TIME2 with FLX_TIME1_ARCHIVE we need to create corresponding partition in FLX_TIME1_ARCHIVE. To do than we use LOCK TABLE PARTITION FOR syntax supplying proper date value HIGH_VALUE - 1 (partition partitioning column is less than HIGH_VALUE so we subtract 1) and then use ALTER TABLE EXCHANGE PARTITION FOR syntax:
SQL> lock table FLX_TIME1_ARCHIVE
2    partition for(TO_DATE(' 2013-01-01 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIAN') - 1)
3    in share mode;
Table(s) Locked.
SQL> alter table FLX_TIME1_ARCHIVE exchange partition
2    for(TO_DATE(' 2013-01-01 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIAN') - 1)
3    with table FLX_TIME2;
Table altered.
SQL> Same way we exchange partition SYS_P120:
SQL> truncate table FLX_TIME2;
Table truncated.
SQL> alter table FLX_TIME1 exchange partition SYS_P120 with table FLX_TIME2;
Table altered.
SQL> lock table FLX_TIME1_ARCHIVE
2    partition for(TO_DATE(' 2013-01-02 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIAN') - 1)
3    in share mode;
Table(s) Locked.
SQL> alter table FLX_TIME1_ARCHIVE exchange partition
2    for(TO_DATE(' 2013-02-01 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIAN') - 1)
3    with table FLX_TIME2;
Table altered.
SQL> Now:
SQL> select count(*)
2    from FLX_TIME1 partition(day0)
3 /
COUNT(*)
         8
SQL> select count(*)
2    from FLX_TIME1 partition(sys_p119)
3 /
COUNT(*)
         0
SQL> select count(*)
2    from FLX_TIME1 partition(sys_p120)
3 /
COUNT(*)
         0
SQL> select partition_name from user_tab_partitions where table_name='FLX_TIME1_ARCHIVE';
PARTITION_NAME
DAY0
SYS_P121
SYS_P122
SQL> select count(*)
2    from FLX_TIME1_ARCHIVE partition(day0)
3 /
COUNT(*)
         0
SQL> select count(*)
2    from FLX_TIME1_ARCHIVE partition(sys_p121)
3 /
COUNT(*)
        31
SQL> select count(*)
2    from FLX_TIME1_ARCHIVE partition(sys_p122)
3 /
COUNT(*)
        11
SQL> SY.

Gathering Statistics on NON-PARTITIONED objects

Hi,
Is it possible to manually gather stats only for Non-Partitioned objects without touching any of the Partitioned objects?
Oracle Version: 11.1.0.7
Thanks,
Ishan

@Hoek and Kuljeet:
I am sorry on missing out on this info.
What I mean is that, I don't want to hard-code the NON-PARTITIONED table names or take names from USER_TABLES. Oracle should pick it up automatically like the way it does it for PARTITIONED tables.
Thanks,
Ishan
Edited by: Ishan on Jun 7, 2012 6:01 PM

Recording Routine for Tables

Hi ,
Can you please explain me about Recording Routine for Tables..
I came to know that we can get do it via SE55 tcode..
Can you please explain me the process to do this..
Regards
Parnith..

Hi Raj,
Thanks for your solution..
Can please suggest how can i solve following requirement..
I had to update the Recording Routine for one my custom tables from 'Standard recording routine' to 'No,or user,recording routine'.
I need to update and transport this..
When i went via SE55..
There are four Radio button..
Can you please let me know the exact steps to solve the above problem..
Regards,

Sql server partition parent table and reference not partition child table

Hi,
I have two tables in SQL Server 2008 R2, Parent and Child Table.
Parent has date time, and it is partitioned monthly, there is a Child table which just refer the Parent table using Foreign key relation.
is there any problem the non-partitioned child table referring to a partitioned parent table?
Thanks,
Areef

The tables will need to be offline for the operation. "Offline" here, means that you wrap the entire operation in a transaction. Ideally, this transaction would:
1) Drop the foreign key.
2) Use ALTER TABLE SWITCH to drop the old data.
3) Use ALTER PARTITION FUNCTION to drop the old empty partition.
4) Use ALTER PARTITION FUNCTION to add a new empty partition.
5) Reapply the foreign keys WITH CHECK.
All but the last operation are metadata-only operation (provided that you do them right). To perform the last operation, SQL Server must scan the child tbale and verify that all keys are present in the parent table. This can take some time for larger tables.
During the transaction, SQL Server holds Sch-M locks on the table, which means that are entirely inaccessible, even for queries running with NOLOCK.
You avoid this the scan by applying the fkey constraint WITH NOCHECK, but this can have impact on query plans, as SQL Server will not consider the constraint as trusted.
An alternative which should not be entirely dismissed is to use partitioned
views instead. With partitioned views, the foreign keys are not an issue, because each partition is a pair of tables, with its own local fkey.
As for the second question: it appears to be completely pointless to partition the parent, but not the child table. Or does the child table only have rows for a smaller set of the rows in the parent?
Erland Sommarskog, SQL Server MVP, [email protected]

Change partition type and 2 billion rows limit.

Hello experts ,
My DB's 1 table has 4 billion records , so I'm using range partition for this , I devided 10 partitions.
I want to change this range partition to hash partition.
In this time , I think I should do following .
1. execute "alter table bigtable merge partitions";
2. execute "alter table bigtable partition by hash (column1) partitons 10"
I think it will be correspond to 2 billion row limit in sequence 1.
How to execute re-partitioning in this case ? Should I unload current data to file or sometiong and load from this
Regards,
Jim

You can change the partitioning type without merging the partitions, and as you said you would hit the limit even if you did that. I would recommend stopping the SLT master job (if this is fed from SLT), then performing this operation. It will clearly take a good chunk of time to do so.
Also to note, hash will simply work on the column values that you partition on, you can't really guarantee that there will equal distributions across the 10 partitions.
Regards,
Justin

How can we do the validation for non visible records in table control.

Hi Experts,
I have a table control which displays list of material details. I have a button to upload the material details from excel file to table control directly. I have to validate all the customers which are exist in the table. But my item (Material) table control displays only 5 rows i.e only 5 entries are visible in module pool screen. The validation is done for 5 records only in PAI event, but i need to do validation for rest of the records too (Which are not visible on items table), if validation fails then needs to display error message.
How can we do the validation for non visible records in table control.
Regards,
Bujji

Hi,
try validating material before displaying it in table control...'
Rgds/Abhhi

Urgent help please, I made an file with the size 1024x768, then i made two folios, one for retina 2048x1536 and one for non retina 1024x768, i have alot of video content in it, everything works perfect on my retina ipad, but when i open it on ipad 2 an er

Urgent help please, I made an file with the size 1024x768, then i made two folios, one for retina 2048x1536 and one for non retina 1024x768, i have alot of video content in it, everything works perfect on my retina ipad, but when i open it on ipad 2 an error appears on the pages with video content?

its in german:
der Vorgang könnte nicht abgeschlossen werden.
something like the process coundnt be completed

What is the upper limit for a table to have records

Hi all,
I am having table like this.....
CLIENTPCLOG (
     LOG_ID                                   NUMBER(10)          NOT NULL,
     CREATE_DATE                              DATE,
     CREATE_USER_ID                         NUMBER(10)          NOT NULL,
     EDIT_DATE                              DATE,
     EDIT_USER_ID                         NUMBER(10),
     DELETE_DATE                              DATE,
     DELETE_USER_ID                         NUMBER(10),
     DELETE_FLG                              NUMBER(1)          NOT NULL,
     LANGUAGE_ID                              NUMBER(10)          NOT NULL,
     LOG_TYPE_ID                              NUMBER(10)          NOT NULL,
     LOG_DESCRIPTION                         VARCHAR2(1000)     NOT NULL,
     MODULENAME                              VARCHAR2(100),
     MAC_ID                                   VARCHAR2(50),
     FC_ID                                   NUMBER(10),
     CLIENT_LOG_ID                         NUMBER,
     SERIAL_NO                              VARCHAR2(100),
     CONSTRAINT FK_CLIENTPCLOG_LOGTYPEMASTER FOREIGN KEY(LOG_TYPE_ID) REFERENCES IES_IESDC3_FINAL_TEST.LOGTYPEMASTER (LOG_TYPE_ID) DISABLE NOVALIDATE ,
     CONSTRAINT PK_LOGMAINTENANCE PRIMARY KEY(LOG_ID)
          USING INDEX TABLESPACE TB_UCPS_JAP LOGGING PCTFREE 10 INITRANS 2 MAXTRANS 255
               STORAGE(INITIAL 64K NEXT 0M MINEXTENTS 1 MAXEXTENTS UNLIMITED
                    FREELISTS 1 FREELIST GROUPS 1 BUFFER_POOL DEFAULT )
TABLESPACE TB_UCPS_JAP LOGGING PCTFREE 10 PCTUSED 40 INITRANS 1 MAXTRANS 255
     STORAGE(INITIAL 64K NEXT 0M MINEXTENTS 1 MAXEXTENTS UNLIMITED
          FREELISTS 1 FREELIST GROUPS 1 BUFFER_POOL DEFAULT )
Is there any limit for records to be inserted in this table...? We are testing performance test and inserted records to this table. So please advise on this.
Thanks in advance,
Pal

It is restricted only by the space on your disk drives.
See more
http://download.oracle.com/docs/cd/B19306_01/server.102/b14237/limits003.htm#sthref4186
Gints Plivna
http://www.gplivna.eu

Two billion record limit for non-partitioned HANA tables?

Similar Messages

Maybe you are looking for