Unable to find Submit button in iExpences OAF Page

Hi Everyone,
I want to know the functionality behind the submit button of iExpences OAF Page.
Navigation is
IExpences - Create Expence report -Review - Submit button.
button i am unable to find the submit button in personalization.
Could you any one help on this!!
Thanks in Advance!!
With Best Regards

Check in About this Page, if the Button Name is present.
Sometimes depending on the condition, there might be a change in the text of the button .. so donot go by the button name ...
Just check the surrounding fields and try to zero in to a button.
You can also download the page and CO and check where the button is more clearly.
To download the page, usr JDR_UTILS package in an anonymous block.
The CO class file can be downloaded from Unix box and decompiled using a Decompiler.
Regards
Srikanth K

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Unable to capture the submit button event in OAF

Hi
I am facing a problem extending the NavigationCO controller on "/oracle/apps/per/selfservice/review/webui/ReviewPG". I just want to throw some exception when the user clicks the submit button in the PFR. I have used the following code but i did not find any solution. Can anyone help me out in this issue. When i used the first method its displaying some error on submitting the page but where as in the second method its commiting the data instead of throwing an exception.
I tried the following methods:
public class XXXNavigationCO extends NavigationCO {
public void processFormRequest(OAPageContext pageContext, OAWebBean webBean)
if (pageContext.getParameter("HrSubmit") != null)
super.processFormRequest(pageContext, webBean);
pageContext.forwardImmediatelyToCurrentPage(null,true, "Y");
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else{
super.processFormRequest(pageContext, webBean);
2.
public class XXXNavigationCO extends NavigationCO {
public void processFormRequest(OAPageContext pageContext, OAWebBean webBean)
if ("HrSubmit".equals(pageContext.getParameter(EVENT_PARAM)))
throw new OAException("gsgfshghjgashfa");
super.processFormRequest(pageContext, webBean);
}

Hi Gaurav,
Thanks for the repsonse. I tried the same code but its not throwing the exception its directly launching me the confirmation page. Actaully the controller is redirecting to confirmation page on submit. But now i want to check some condition on submit and throw an exception if the condition is not satisfied. If the condition is satisfied i want the seeded controller action to take place.
I tried using "pageContext.forwardImmediatelyToCurrentPage" and "pageContext.forwardURLToCurrentPage" but i did not achieve success in it.
If the above mentioned "pageContext.forwardURLToCurrentPage" is right could you please give me an example to get thjis resolved.

How to trap Submit button event in OAF

Hello,
I'm doing controller extension for create account button in Customer UI.
Issue: I'm not able to trap the table action to add extra validation logic.
I tried to use pageContext.getParameters("CreateButton") but it didn't work i.e. debug message was not printed written inside if statement.
Button Structure:
TableAction
Flowlayout
Submit button.
Code:
public void processFormRequest(OAPageContext pageContext,
                                   OAWebBean webBean) {
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        OAApplicationModule am = pageContext.getApplicationModule(webBean);
        ArrayList exceptions = new ArrayList();
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            (OAFlowLayoutBean)webBean.findChildRecursive("TableActionsRN");
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        String s1 = pageContext.getParameter(vbuttonBean.getName());
            if (s.equalsIgnoreCase("CreateAccount")) {
            OAViewObject vo =
                (OAViewObject)am.findViewObject("HzPuiAccountTableVO");
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                if (row != null) {
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                        (String)row.getAttribute("PartyId").toString();
                    pageContext.writeDiagnostics("Jai-3", "PartyId" + partyid,
                                                 1);
                    int PartyNum = Integer.parseInt(partyid);
                    String partyacctcnt = null;
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                        pageContext.writeDiagnostics("Jai-4", "Inside Try", 1);
                        String query =
                            "SELECT count(1) lcount FROM HZ_CUST_ACCOUNTS WHERE party_id=:1";
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                                                         1);
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                                                     1);
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                                                       null, OAException.ERROR,
                                                       null));
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                                                     10);
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Please suggest the how to overcome with above mention issue.

Hi Kiranmai,
You can capture the event of the radio button in the following way in oninputprocessing.
DATA: event             TYPE REF TO if_htmlb_data,
               radioButton_event TYPE REF TO CL_HTMLB_EVENT_RADIOBUTTON.
         event = cl_htmlb_manager=>get_event( request ).
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event->event_type
event->event_server_name
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Programatically Created Button Placement on OAF Page

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I created a submit button using the below code. But it was placed below the page. I have 3 buttons on the page. How Can I keep this new button next to these buttons. Please let me know.
Thanks,
HP.
OASubmitButtonBean oasb= (OASubmitButtonBean)paramOAPageContext.getWebBeanFactory().createWebBean(paramOAPageContext,"BUTTON_SUBMIT");
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Edited by: user1147940 on Sep 19, 2010 7:53 PM

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Hi,
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1. Is it possible to use submit 3 times like here?
<input type="submit" name="btnSub" value="Modify">
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Unable to find Submit button in iExpences OAF Page

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