Unused Limit Fee for Non-revolving Lines of Credit Calculation

Hello, gurus!
Question is about non-revolving lines of credit. In line's master we specify some additional flows besides limit, period of validity.
So when we define unused limit fee parameters in non-revolving line of credit master, the system automatically generates financial flows for this fee calculating as
(Initial Credit line Limit - Tranche Amounts + Tranche Repayments)InterestDays of calculating/Days in the Year.
Which is incorrect for Non-revolving lines which should not take in concern Tranche Repayments.
So we need to either ignore repayment flows or change calculation method for Unused Limit Fee flows.
We tried to fix this both with SPRO and ABAP but it didn't help.
Would be great to hear any ideas!
Thanks.

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Hi,
I wanted to check how optimizer calculates the cardinality/selectivity for a value which is not popular and histogram is height based histograms.
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create table t1 (
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as
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SKEW                                     80 .013973812          75
PADDING                                   1 .000154321           1
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ENDPOINT_NUMBER ENDPOINT_VALUE
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              1              9
              2             13
              3             16
              4             19
              5             21
              6             23
              7             25
              8             26
              9             28
             10             29
ENDPOINT_NUMBER ENDPOINT_VALUE
             11             31
             12             32
             13             33
             14             35
             15             36
             16             37
             17             38
             18             39
             19             40
             20             41
             21             42
ENDPOINT_NUMBER ENDPOINT_VALUE
             22             43
             23             44
             24             45
             25             46
             26             47
             27             48
             28             49
             29             50
             30             51
             32             52
             33             53
ENDPOINT_NUMBER ENDPOINT_VALUE
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             35             55
             37             56
             38             57
             39             58
             41             59
             42             60
             43             61
             45             62
             46             63
             48             64
ENDPOINT_NUMBER ENDPOINT_VALUE
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             51             66
             52             67
             54             68
             56             69
             57             70
             59             71
             60             72
             62             73
             64             74
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ENDPOINT_NUMBER ENDPOINT_VALUE
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             71             78
             73             79
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COUNT(*)
        75
Execution Plan
Plan hash value: 4273422929
| Id | Operation         | Name | Rows | Bytes | Cost (%CPU)| Time     |
|   0 | SELECT STATEMENT |       |     1 |     3 |     1   (0)| 00:00:01 |
|   1 | SORT AGGREGATE   |       |     1 |     3 |            |          |
|* 2 |   INDEX RANGE SCAN| T1_I1 |    86 |   258 |     1   (0)| 00:00:01 |
Predicate Information (identified by operation id):
   2 - access("SKEW"=75)Skipped the Statistics information for keep example short.
selectivity for 75 (popular value) = 2/75 = 0.02666
Cardinality for 75 is = selectivity * num_rows = 0.02666*3240 = 86.3784 (rounded to 86) >> Here selectivity and cardinality are correct and displayed in autotrace.
SQL> select count(*) from t1 where skew=8;
COUNT(*)
         8
Execution Plan
Plan hash value: 4273422929
| Id | Operation         | Name | Rows | Bytes | Cost (%CPU)| Time     |
|   0 | SELECT STATEMENT |       |     1 |     3 |     1   (0)| 00:00:01 |
|   1 | SORT AGGREGATE   |       |     1 |     3 |            |          |
|* 2 |   INDEX RANGE SCAN| T1_I1 |    29 |    87 |     1   (0)| 00:00:01 |
Predicate Information (identified by operation id):
   2 - access("SKEW"=8)how the cardinality is 29 calculated. I think the formula for selectivity is
select for 1(non popular value) = density * num_rows = .013973812 * num_rows (which is 45 approx) but in autotrace its 29
SQL> select count(*) from t1 where skew = 46;
COUNT(*)
        46
Execution Plan
Plan hash value: 4273422929
| Id | Operation         | Name | Rows | Bytes | Cost (%CPU)| Time     |
|   0 | SELECT STATEMENT |       |     1 |     3 |     1   (0)| 00:00:01 |
|   1 | SORT AGGREGATE   |       |     1 |     3 |            |          |
|* 2 |   INDEX RANGE SCAN| T1_I1 |    29 |    87 |     1   (0)| 00:00:01 |
Predicate Information (identified by operation id):
   2 - access("SKEW"=46)46 is also non popular value
So how the value is calculated for these values?

Your example seems to be based on Jonathan Lewis's article:
http://jonathanlewis.wordpress.com/2012/01/03/newdensity/
In this article, he does walk through the calculation of selectivity for non-popular values.
The calculation is not density but NewDensity, as seen in a 10053 trace, which takes into account the number of non-popular values AND the number of non-popular buckets
The article describes exactly how 29 is derived.Hi Dom,
Yes i used the same sample script of create the data sets. I should have checked Jonathan's blog for new density calculations. So selectivity works out as two either ways
1) selectivity(non popular) = Newdensity(took from 10053 traces) * rum_rows
or
2) non-popular rows/ non_popular values (where non-popular values can be derived from 10053 traces and non popular rows are (3240 * (74-31)/74 = ) 1883
Thanks for pointing to right blog

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Unused Limit Fee for Non-revolving Lines of Credit Calculation

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