Upload file input type="hidden" to server

I have a file that is on a user machine. The file is always in the same location. I want to have the user click on an upload button without selecting a file and have it sent to the server for processing. I have tried to use <input type="hidden" name="fileupload" value="c:\filepath">. When I run it this way I get no file found. Please help!

I am sorry, I will move it. Didn't notice it was in Acrobat, I was wanting Coldfusion.
Edit: Since I am unaware of how to move it I'm just going to mark it as answered.

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Passing request of file input type to a jsp

Hi i m using this script for file uploading the form is.... <html > <head> <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" /> <title>Untitled Document</title> </head> <body> <form action="uploadscript.jsp" name="filesForm" enctype="multipart/form-data" method="post">
Please specify a file, or a set of files:
<input type="file" name="userfile_parent" value="userfile_parent" >
<input type="submit" value="submit" value="Send">
</form> </body> </html> And i am tring to get the url on uploadscript.jsp by using String parentPath=request.getParameter("userfile_parent"); but i foud that its value is NULL it is not working what should i do to get the userfile_parent on uploadscript.jsp help me!!! Message was edited by: UDAY Message was edited by: UDAY
avajain
Posts: 135
From: Noida , India
Registered: 5/10/06
Read      Re: Passing response but getting NULL
Posted: Sep 20, 2006 2:43 AM in response to: UDAY in response to: UDAY
     Click to reply to this thread      Reply
Use method="GET" in place of method="post" .
Thanks
UDAY
Posts: 26
From: JAIPUR
Registered: 8/14/06
Read      Re: Passing response but getting NULL
Posted: Sep 20, 2006 3:18 AM in response to: avajain in response to: avajain
Click to edit this message...           Click to reply to this thread      Reply
now it is giving this error message by e.getMessage()
[br]the request doesn't contain a multipart/form-data or multipart/mixed stream, content type header is null
the uploadscript is this....
http://www.one.esmartstudent.com
can u please help me.

Here is sample code which we have used in one of our projects with org.apache.commons.fileupload.*.
You can find String fullName = (String) formValues.get("FULLNAMES"); at the end that gives name of file.
<%@ page import="java.util.*"%>
<%@ page import="java.util.List"%>
<%@ page import="java.util.Iterator"%>
<%@ page import="java.io.File"%>
<%@ page import="java.io.*"%>
<%@ page import="org.apache.commons.fileupload.*"%>
<%@ page import="org.apache.commons.fileupload.disk.*"%>
<%@ page import="org.apache.commons.fileupload.servlet.*"%>
<%!
     //method to return file extension
     String getFileExt(String xPath){
               //Find extension
               int dotindex = 0;     //extension character position
               dotindex = xPath.lastIndexOf('.');
               if (dotindex == -1){     // no extension
                    return "";
               int slashindex = 0;     //seperator character position
               slashindex = Math.max(xPath.lastIndexOf('/'),xPath.lastIndexOf('\\'));
               if (slashindex == -1){     // no seperator characters in string
                    return xPath.substring(dotindex);
               if (dotindex < slashindex){     //check last "." character is not before last seperator
                    return "";
               return xPath.substring(dotindex);
%>
<%
Map formValues = new HashMap();
String fileName = "";
boolean uploaded = false;
     // Check that we have a file upload request
     boolean isMultipart = FileUpload.isMultipartContent(request);
     //Create variables for path, filename and extension
     String newFilePath = CoeResourceBundle.getEmailProperties("FILE_UPLOAD_PATH");//application.getRealPath("/")+"temp";
     String newFileName ="";
     String FileExt = "";
     //System.out.println(" newFilePath"+newFilePath+"/");
     //out.println(" newFilePath"+newFilePath+"<br>");
     // Create a factory for disk-based file items
     FileItemFactory factory = new DiskFileItemFactory();
     // Create a new file upload handler
     ServletFileUpload upload = new ServletFileUpload(factory);
     // Parse the request
     List /* FileItem */ items = upload.parseRequest(request);
     // System.out.println(" newFilePath"+newFilePath+"/");
     // Process the uploaded items
     Iterator iter = items.iterator();
     //Form fields
     while (iter.hasNext()) {
     //System.out.println("in iterator");
          FileItem item = (FileItem) iter.next();
          if (item.isFormField()) {
               String name = item.getFieldName();
               String value = item.getString();
               if (name.equals("newFileName")) {
                    newFileName = value;
               //System.out.println("LOADING");
               formValues.put(name,value);
          else {
          //System.out.println("in iterator----");
               String fieldName = item.getFieldName();
               fileName = item.getName();
               int index = fileName.lastIndexOf("\\");
          if(index != -1)
                    fileName = fileName.substring(index + 1);
          else
                    fileName = fileName;
               FileExt = getFileExt(fileName);
               String contentType = item.getContentType();
               boolean isInMemory = item.isInMemory();
               long sizeInBytes = item.getSize();
               if (fileName.equals("") || sizeInBytes==0){
                    out.println("Not a valid file.<br>No upload attempted.<br><br>");
               } else {
               // out.println("ACTUAL fileName= " newFilePath"\\"+fileName+ "<br>");
                    //File uploadedFile = new File(newFilePath+"\\", newFileName+FileExt);
                    File uploadedFile = new File(newFilePath+"/",fileName);
                    File oldFile = new File(CoeResourceBundle.getEmailProperties("FILE_UPLOAD_PATH")+"/"+fileName);
                    File oldFileApproved = new File(CoeResourceBundle.getEmailProperties("APPROVED_FILE_LOCATION")+"/"+fileName);
                    try{
                         if (!oldFile.exists()&&!oldFileApproved.exists())
                              item.write(uploadedFile);
                              uploaded = true;
                         //out.println(fileName+" was successfully uploaded as "+ newFileName+FileExt +".<br><br>");
                    catch (java.lang.Exception e) {
                         out.println("Errors prevented the file upload.<br>"+fileName+ " was not uploaded.<br><br>");
     String userid = (String) formValues.get("USERID");
     String fullName = (String) formValues.get("FULLNAMES");
     String email = (String) formValues.get("EMAILID");
     String empno = (String) formValues.get("EMPNO");
     String docType = (String) formValues.get("DOCTYPE");
     String desc = (String) formValues.get("MYTEXT");
     String title = (String) formValues.get("TITLEBOX");
     String module = (String) formValues.get("MODULE");
     String techfunctype = (String) formValues.get("TECHFUNCTYPE");
%>

HELP INPUT TYPE = hidden values SEEN IN URL QUERY STRING!!!

Trying to do session management using hidden fields.
The fields that are suppose to be hidden show up in the query string of the URL.
I have included the code, the output to the web page
and the URL with the "hidden" fields please help.
HIDDEN FIELDS IN URL QUESRY STRING
http://localhost:8080/myApp/servlet/Servlet077?firstName=Sandra&item=Michael
WEB PAGE OUTPUT
Enter a name and press the button
Name:
Your list of names is:
Michael
Sandra
JAVA SOURCE CODE
import java.io.*;
import javax.servlet.*;
import javax.servlet.http.*;
public class Servlet077 extends HttpServlet{
public void doGet(HttpServletRequest req,
HttpServletResponse res)
throws ServletException, IOException{
//An array for getting and saving the values contained
// in the hidden fields named item.
String[] items = req.getParameterValues("item");
//Get the submitted name for the current GET request
String name = req.getParameter("firstName");
//Establish the type of output
res.setContentType("text/html");
//Get an output stream
PrintWriter out = res.getWriter();
//Construct an HTML form and send it back to the client
out.println("<HTML>");
out.println("<HEAD><TITLE>Servlet07</title></head>");
out.println("<BODY>");
//Substitute the name of your server or localhost in
// place of baldwin in the following statement.
out.println("<FORM METHOD=GET ACTION="
+ "\"http://localhost:8080/myApp/servlet/Servlet077\">");
out.println("Enter a name and press the button<P>");
out.println("Name: <INPUT TYPE=TEXT NAME="
+ "\"firstName\"><P>");
out.println("<INPUT TYPE=submit VALUE="
+ "\"Submit Name\">");
out.println("<BR><BR>Your list of names is:<BR>");
if(name == null){
out.println("Empty<BR>");
}//end if
if(items != null){
for(int i = 0; i < items.length; i++){
//Display names previously saved in hidden fields
out.println(items[i] + "<BR>");
//Save the names in hidden fields on form currently
// under construction.
out.println("<INPUT TYPE = hidden NAME=item "
+ "VALUE=" + items[i] + ">");
}//end for loop
}//end if
if(name != null){
//Display name submitted with current GET request
out.println(name + "<BR>");
//Save name submitted with current GET request in a
// hidden field on the form currently under
// construction
out.println("<INPUT TYPE = hidden NAME=item "
+ "VALUE=" + name + ">");
}//end if
out.println("</body></html>");
}//end doGet()
}//end class Servlet07

1. Change <form name=xxx action="your_servlet" mathod="Get"> to
<form name=xxx action="your_servlet" mathod="POST">
2. Add the following lines of code to your servlet.
public void doPost(HttpServletRequest req, HttpServletResponse res)
        throws ServletException, IOException {
        doGet(req,res);
        return;
}Sudha

Upload file of type Spreadsheet.ods to internal table

Hi Experts,
can any body give me function module to upload file of type Spreadsheet.ods into internal table
Thanks in Advance
Narendra

Hi Renu,
it is not supporting this function modules.
we r using open office and its just like excel sheet.
even function module ALSM_EXCEL_TO_INTERNAL_TABLE
not supporting.
Narendra

Get Uploaded File Mime Type and Client Filename

Anyone know how to recover an uploaded file MIME type and
client file name?
I'm writing my own cfx tag to process file uploads and pretty
much have it figured out except to determine the name of the client
file and mime type. The formfield file variable value contains the
path/filename to the CF temp directory, but I need the MIME type,
filename, etc. that is contained int he HTTP Header
(e.g. Content-Disposition: form-data; name="Image";
filename="C:\test.JPG"
Content-Type: image/pjpeg
[empty line])
I'm using the getHttpRequestData() functiont, but it only
gives me the content-type multipart/form-data, leaving out the Mime
type and Content-Disposition (which contains the client file name).

Hi Daniel,
do you use EPG, mod_plsql or APEX Listener? Have you changed the connection mechanism after upgrading to 4.2.1?
If you use the APEX Listener, which version do you use? Which browser and version do you use to upload the file? Does it reproduce with other browsers as well?
Regards
Patrick
Member of the APEX development team
My Blog: http://www.inside-oracle-apex.com
APEX Plug-Ins: http://apex.oracle.com/plugins
Twitter: http://www.twitter.com/patrickwolf

Input type hidden

What is the html equivalent for input type=hidden in netui tags, where in one can
give a name value pair.
thanks..

"Shankar B" <[email protected]> wrote:
>
I cannot use netui:anchor, as I am submittig a form using javascript.
hence need
to post some hidden values. How do we do hidden name balue pair inside
netui
form.
"Darryl" <[email protected]> wrote:
"Shankar B" <[email protected]> wrote:
What is the html equivalent for input type=hidden in netui tags, where
in one can
give a name value pair.
thanks..I've used a netui:anchor tag with a nested netui:parameter tag thatpassed
the
"hidden" field to an action in the pageflow. In the pageflow, use the
getRequest
method as below...
IN JSP:
<netui:anchor action="toNextInCatalog"><%=category.getName()%>
<netui:parameter name="categoryName" value="<%=category.getName()%>"></netui:parameter>
</netui:anchor>
IN PAGEFLOW:
String catName = this.getRequest().getParameter("categoryName");
hope this helps,
D
There is a <netui:hidden> tag which is intended to have an equivalent to the HTML
hidden fields. However I couldn't achioeve to set a defaultValue ([dataInput="dataInput"].

Input type="hidden" value="....a chain of rubbish letter......"!!

I use the browser view source function to see the html generated by jsf, and always see something like the following:
<input type="hidden" name="javax.faces.ViewState" id="javax.faces.ViewState" value="8EgC7hvJoXWgMHaUZxk5rx66APlnNueyP32ajDxbvc/i5akMf2jX5ZGyBjrnsmcbFDLXCaS8cHN169OeG5kDXxvWNcBMTAigJiokZI5Ne66G0/CILkEquml3xSn+jI4+HDkEeDEBtmlPDjjFJyOcOmZ+87klHuSTgAe5P6mMDOQOqrH0Pj9yl+
............++nBOnItypO1I+XXANTsWVuCGcV2sghVuKD42Kt/UFL7c6gh4S7KuRSQTuzsQzskJZBO7OxDOyQl0Yq1NF68G0U6T4uIj27tlXpOehNZq4LNOhvQdQH7D6ZKdmAKbVesQLrzhzo9mnY9MN0zJj1r9NhEWfhlFpRxIxYKVda+2pPzvUD9+wbS2NpmjNu5opnJ++XI9z5KpWbdblb9JKIaP6Zzxdsh2E41VBicsyuBzaOTZozbuaKZyfvJAmuJTdCe+/H9z8iOGr8SQHtmk18OUgs7l4BGSVeW3JGgo6F2EHIjEMwkhmgQIkRwDYBkboU2tAin0sPxMybTF65p98Jrn1GsVQxLhbC1F0EKHbwNbKsBvTfuvwqj7Ahik5pmDIMXrIHjmjrrGtj65UvGvkNZ5lbIFl79QTPnWy6OEoxsUJdm0dytee653YD86T4uIj27tlQB3hMxJexgDHCTV10bBgnfB2FWSo74DqQ==" />the value is a chain of meaningless letter, what is it?

Why are you always so negative in your questions/postings? In every post you're just complaining and throwing around with too much exclamation marks. It's getting annoying. You risk to become placed in the ignore list.
Anyway, you have configured JSF to use client side state saving. This isn't a default setting.

Uploading files Mime Type not correct for Office 2007 default extensions.

hi all,
My company has recently moved over to MS Office 2007 and the default extensions for word, excel etc are now .docx, xlsx etc (ie xml based).
Unfortunately now when we upload files through APEX to the database the MIME TYPE value for these files isn't being recognised and not loadeding correctly into the APEX_APPLICATION_FILES table and subsequently any future retrieval of these files fails.
I could put some logic inthe up load procedure to look at the filename in APEX_APPLICATION_FILES and hard code in the releavnt mime types but this still causes problems when retrieving the content.
Has anyone come across this and got a workround? Is it a bug in AE?
regards
James
FYI - using APEX 3.0.2 over 11G.

I have not any response to my question and not sure if it is in Apex I need to look or the tomcat server that I need to look. I have a useful application to try to show others what Apex can do for our customers to collaborate. However, most of our customers are using office 2007 so, hoping this is possible.
I am using apex 3.2.0.00.27 if that helps someone to point me where to find more info on being able to have Word 2007 or excel 2007 fire up to open a .docx or .xlss file stored in a table blob column. Word or Excel does fire up to open .doc and .xls files.
The following is the query for a report selecting the filenames uploaded into a blob column in my table:
{ SELECT s.ID, SUBSTR(s.NAME,INSTR(s.NAME, '/',1,1)+1,length(s.NAME)) SHORT_FNAME, s.SUBJECT
FROM spp_attachments s
WHERE s.PROGRAM_ID = :P2_PROGRAMID }
Below is the stored procedure called from the link on the short_fname column in report query above.
{ create or replace PROCEDURE download_file(p_file IN number) AS
v_mime VARCHAR2(48);
v_length NUMBER;
v_file_name VARCHAR2(2000);
Lob_loc BLOB;
BEGIN
APEX_APPLICATION.G_FLOW_ID :=245;
IF NOT (wwv_flow_custom_auth_std.is_session_valid) then
owa_util.status_line(404, 'Page Not Found',true);
return;
else
SELECT MIME_TYPE, BLOB_CONTENT, name,DBMS_LOB.GETLENGTH(blob_content)
INTO v_mime,lob_loc,v_file_name,v_length
FROM spp_attachments
WHERE id = p_file;
-- set up HTTP header
-- use an NVL around the mime type and
-- if it is a null set it to application/octect
-- application/octect may launch a download window from windows
owa_util.mime_header( nvl(v_mime,'application/octet'),
FALSE );
-- set the size so the browser knows how much to download
htp.p('Content-length: ' || v_length);
-- the filename will be used by the browser if the users does a save as
htp.p('Content-Disposition: attachment;
filename="'||replace(REPLACE(substr(v_file_name,instr(v_file_name,'/')+1),chr(10),NULL),chr(13),NULL)|| '"');
-- close the headers
owa_util.http_header_close;
-- download the BLOB
wpg_docload.download_file( Lob_loc );
end if;
end download_file; }
Thank you,
Mark

FireFox v22 - File Input type now shows browse on left

For some unknown reason, Firefox v22 has moved the BROWSE button on an <INPUT type="file" statement.
The Browse button appears on the left hand side - this has previously only happened in Webkit based browsers.
I can force the button to the right hand side in webkit browsers by using:
input[type="file"].file::-webkit-file-upload-button {
float: right;
position: relative;
top: -1px;
right: -90px;
However, I can't find any similar means of adjusting the layout in Firefox.

I honestly think the file input is something that Internet Explorer (still) and previous FF had right and that Safari and Chrome have wrong. Styling the colour of text for inputs is now going to be a real problem - and when you have to tell the whole world how to cope with something, that's as real a problem as a doubled margin on a float was/is in IE6 - because the text color shown inside the box of a text input is also the text colour that is shown outside the box on a file input. Black text on a black background?
If you are here, World, the solution is to put a background-color on all your inputs e.g. input {background-color: #FFF} .
The new input also removes the option to copy/paste link values, which can be a real pain if you are doing a lot of file uploading e.g. of photos identified by (long links with...) productids

Uploading files from web to db server

hi, yesterday discover article from otn about uploading file from clients filesystem to web application server.
but how about uploading from clients filesystem directly into database column? (i'm talking about forms application via web server, btw, not c/s app)
i've search through the archieve, but cant find anything useful, just alot of similar question with no useful answer. so i guess alot of people could use this feature, if it can be done.
thanks in advance
Phil

The demo titled "Forms, Reports, and Portal Integrated Demo"
has the package and a form using it.
You can download it from http://technet.oracle.com/sample_code/products/forms/content.html
Read the script and search the part where you upload an image.

Interface Mngr: Option for Uploading file from presentation or unix server

Hi all,
I want to upload file through interface manager where the file can be on the presentaion server or the unix server. How do i achieve the same? I need to create parameters for 'Filename' and 'Unix Filename'. Either of the 2 will be chosen at a time. But how do i retrieve the respective file?

Hi!
For handling a file on the apllication server (unix), you have to use the OPEN DATASET, CLOSE DATASET commands.
For handling the files on the presentation server (local PC), you have to use the upload/download method (GUI_UPLOAD, GUI_DOWNLOAD function elements).
You can make 2 parameters in your ABAP program like this:
PARAMETERS: p_f_app LIKE rlgrap-filename.
PARAMETERS: p_f_pre LIKE rlgrap-filename.
both is filled - error
IF NOT p_f_app IS INITIAL AND
NOT p_f_pre IS INITIAL.
MESSAGE E001(ZERROR).
ENDIF.
both is empty - error
IF p_f_app IS INITIAL AND
p_f_pre IS INITIAL.
MESSAGE E002(ZERROR).
ENDIF.
IF NOT p_f_app IS INITIAL. "application server
open dataset...
ENDIF.
IF NOT p_f_pre IS INITIAL. "presentation server
call function 'gui_upload'...
ENDIF.
Regards
Tamá

How to upload file from client machine to server machine?

i am developing one web application.I have one html file with browse option. client can browse any type of file. what ever file the client will browse it going to be stored in server machine. for storing the file want to use servlet. my html form is of multipart type.
can any one send me the servlet code? i am using tomcat 5.5 as web server.

[http://commons.apache.org/fileupload]
Start reading 'User Guide' and 'Frequently Asked Questions'.
Good luck :)

How to upload file to the R/3 server

Hi Experts,
I need to upload scanned documents to the R/3 server.I am using File upload UI element. can anybody tell me how to upload to a server.And at the same time how to download the uploaded content.
Awaiting for the reply.
Regards,
Ramanan.P
Edited by: Ramanan Panchabakesan on Sep 9, 2008 2:14 PM

storing:
The data of your uploaded document is stored in your context node.
Read this data, turn it into a table with one of the SCMS* functions.
store it in a table, or write it into a file. Whichever you choose.
downloading again:
read all data from your table or file
turn it into an xstring using one of the SMCS* functions
put the xstring in the context node bound to your downloadfile element
The principle is deadsimple. The only thing that really matters is where you want to store the file. And that is more of technical ABAP R/3 question, if not a functional question than a webdynpro for abap one.

Store a uploaded file of type binary into a java.sql.Blob

Hi all,
I try a File-Upload and store the file in a java.sql.Blob of a MaxDB.
My Problem is, that I'm not able to import a Model-Attribute of data type byte[]. Further I don't no how to convert the uploaded value attribute of data type binary, in a java.sql.Blob.
Regards,
Silvia Hofmann

http://www.excelsior-usa.com/jet.html
http://www.ej-technologies.com/products/exe4j/overview.html
http://jsmooth.sourceforge.net/
Distributing your Application as an executable JAR file
Google is your friend.

Setup automated Powershell to upload files to a remote ftp server with ssl

Thanks in advance for the advice!
I need to create a script to upload a file to a remote server to transfer some large files, and I've been reviewing some methods needed, and have a few questions.
Is there a best practice for sending large files?
Is the webrequest or put commands better to use?
This will be the first time we use Powershell on this server. Should I change the executive policy on the server or should I change it in the script when running for security purposes? This is a data warehouse therefore our strategic
data is else where but want to make sure everything is secure as possible.
I am able to run something similar on my laptop which works but when I try it on the server it is blocked. I'm assuming I'll have to open up port 22 for this application to work. How can I confirm that this is the port Powershell
needs open for these transfers.
Any references to learning links appreciated since I'm new to Powershell.
Thanks!

Sorry but we cannot help you with this. We suggest you contact a support tech or consultant to help you set up your system.
Start by learning how PowerShell works and how to set it up. As fro the SSL you will need to postyourscript with any issues and errors.
Start here:
http://technet.microsoft.com/en-us/scriptcenter/dd793612.aspx
¯\_(ツ)_/¯

Upload file input type="hidden" to server

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