Urgent help of the person who coded this...

Question

could the person who posted this code pls get back to me..cuz i can't seem to find u
cuz i would like to use this code of urs but i'm not sure exactly how it works out.
import java.awt.*;
public class DrawArrows
     public void drawArrow(Graphics g,int x1,int y1,int x2,int y2,int headLength,int headwidth)
     double theta;     
     double theta2;     
     int deltaX;     
     int deltaY;     
     int lengthdeltaX;     
     int lengthdeltaY;     
     int widthdeltaX;     
     int widthdeltaY;     
          deltaX=(x2-x1);     
          deltaY=(y2-y1);     
          theta=Math.atan((double)(deltaY)/(double)(deltaX));     
     if(deltaX<0.0)theta2=theta+Math.PI;     
     else theta2=theta;     
     lengthdeltaX=-(int)(Math.cos(theta2)*headLength);     
     lengthdeltaY=-(int)(Math.sin(theta2)*headLength);     
     widthdeltaX=(int)(Math.sin(theta2)*headwidth);     
     widthdeltaY=(int)(Math.cos(theta2)*headwidth);     
     g.drawLine(x1,y1,x2,y2);          
     g.drawLine(x2,y2,x2+lengthdeltaX+widthdeltaX,y2+lengthdeltaY-widthdeltaY);     
     g.drawLine(x2,y2,x2+lengthdeltaX-widthdeltaX,y2+lengthdeltaY+widthdeltaY);   
}i could only work out till the line
                                           deltaX=(x2-x1);     
          deltaY=(y2-y1);     
          theta=Math.atan((double)(deltaY)/(double)(deltaX));    pls let me know if u are still reading this or anyone else who can figure out the later part of the code.
thnx n cheerz

Answer 1

i could only work out till the line
deltaX=(x2-x1);
deltaY=(y2-y1);
theta=Math.atan((double)(deltaY)/(double)(deltaX));
I'm not the poster but these lines seem to compute the
angle of the arrow line.
BTW (to the posters): wouldn't the use of a
Polygon be better suited for this purpose ?Looks indeed like it is calculating the angle to the origin of a line segment.