Using javabean variable in javascript

I have a combo box:
<select name="myCombo" onchange="refreshForm(document.forms[0]);">
     <option value=rome>rome
         <option value=london>london
     <option value=paris>paris
</select>My java script refreshForm method is as follows:
function refreshForm(form) {
        form.submit();
        return true;
}So far so good, the selected value is passed to the action class, I call the form bean class and set the selected city, but when the page reloads the combo box on the page resets itself to the first city on the list 'rome'. so I added an onload method call in the body tag.
<body onload="setselect(document.forms[0]), ${myform.city});" >and the java script method;
function setselect(form, city ){
     form.myCombo.value=city;
}but it doesn't work. any ideas?
Thanks in advance.

hi :-)
there is an extra closing parenthesis afer the document.forms?
<body onload="setselect(document.forms[0]), ${myform.city});" >regards,

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ajetrumpet wrote:
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Hello,
Below I have posted code that I have on two different PHP files, tsearch12.php and votes12.php. The code works great. The file "tsearch12.php" uses AJAX to go to votes12.php to perform some functions. However, the first page has a variable called "find." These two pages only work together when the variable "find" equals "santafe." I would like them to work together regardless of what "find" equals. In other words, I would like to replace the table name "santafe" in votes12.php with the variable "find," but I want the variable "find" to equal the same value in both tsearch12.php and votes12.php. The variable "find" is going to tsearch12.php from another file, which has a simple HTML form with "<form action="tsearch12.php" method="post">" and "<input type="text" name="find" size="55"/>". Anyway, how do I use the variable "find" in votes12.php?
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On tsearch12.php, I have:
# <head>
# <script type='text/javascript' src='jquery.pack.js'></script>
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#     $("a.cell1").click(function(){
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#     //the main ajax request
#         $.ajax({
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# print "<p class=\"topic\">$table[0]</p>\n";
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#     $effectiveVote = $votes[0] - $votes[1];
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# $r = mysql_query($q);
# if($r) //voting done
#     $effectiveVote = getEffectiveVotes($id);
#     echo $effectiveVote;
# elseif(!$r) //voting failed
#     echo "Failed!";
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These forums are for development with Java. Not JavaScript, which is an entirely different language. And AJAX is JavaScript. You need to use Google and find a JavaScript forum for your question (or a PHP forum if your question is really about PHP).

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Regards,
Arie.
Please remember to mark appropriate posts as correct/helpful. For the long run, it will benefit us all.

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