Viewing different user's indexes.
I have a doubt as to how to view a different user's indexes. If, we have to see a different user's tables, we use the syntax,
select * from username.table_name
provided we have select rights on that table of the user. Similarly, do we need view rights on the other user's indexes.Please help in solving my doubt as i need it resolved urgently.
You said "how to view a different user's indexes"
Do you mean you want to see the details of the index ?
Provided you have the privileges on the other users table
you can use
Select * from all_indexes where index_name = <index_name>
and owner = <OWNER>
OR
Select * from all_ind_columns where index_name = <index_name>
and index_owner = <OWNER>
CHeers
Ashwin N.
Similar Messages
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Viewing different user's constraints, triggers, synonyms etc.
I have a doubt as to how to view a different user's constraints, triggers, synonyms. If, we have to see a different user's tables, we use the syntax,
select * from username.table_name
provided we have select rights on that table of the user. Similarly, do we need view rights on the other user's indexes.
Please help in solving my doubt as i need it resolved urgently.do we need view rights on the other user's indexes.No, once the appropriate access to the concerned object has been granted, any indexes on that object (if appropriate) will automatically be used by the database.
Once you have access to the other users tables, the indexes on that table automatically are visible to you.
You could see the objects using ALL_OBJECTS or the ALL_INDEXES dictionary view. -
How to compare index names and columns from different user?
I am using below query to compare two indexes from 2 different users but even though index name and columns are same... result shows me they are different.. what I am doing wrong? Thanks
WITH t AS
(SELECT COUNT (DISTINCT index_owner || index_name || indexed_cols)
cnt
FROM ( SELECT index_owner,
index_name,
listagg (column_name, ',')
WITHIN GROUP (ORDER BY column_position)
indexed_cols
FROM dba_ind_columns
WHERE index_name='XPKTBL_A'
GROUP BY index_owner, index_name))
SELECT CASE
WHEN cnt > 1 THEN 'Indexes are different'
WHEN cnt = 0 THEN 'Indexes dont exist'
WHEN cnt > 1 THEN 'Indexes are identical'
END
commnt
FROM t
Result:
Indexes are different
but Actually if you check below they are same After when I run this query:
SELECT index_owner,
index_name,
listagg (column_name, ',') WITHIN GROUP (ORDER BY column_position)
indexed_cols
FROM dba_ind_columns
WHERE index_name='XPKTBL_A'
GROUP BY index_owner, index_name;
Result:
Index_owner
Index_name
Index_cols
USER1
XPKTBL_A
FIELD_A1
USER2
XPKTBL_A
FIELD_A1Hi,
Erhan_toronto wrote:
I am using below query to compare two indexes from 2 different users but even though index name and columns are same... result shows me they are different.. what I am doing wrong? Thanks
WITH t AS
(SELECT COUNT (DISTINCT index_owner || index_name || indexed_cols)
So index_owner is 'USER1' in one case, and 'USER2' in the other; right?
A string that starts with 'USER1' will be distinct from a string that starts with 'USER2', no matter what the rest of the string contains. Maybe you don't want to compare the owners, or maybe you meant to use some other column (such as table_name) instead of index_owner).
I hope this answers your question.
If not, post a little sample data (CREATE TABLE, CREATE INDEX and CONNECT statements), and also post the results you want from that data.
Explain, using specific examples, how you get those results from that data.
Always say which version of Oracle you're using (e.g., 11.2.0.2.0).
See the forum FAQ: https://forums.oracle.com/message/9362002 -
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Hi All,
How can a user see the View of a query created for a different user??
I would like some info about how to give access ( if it is a access problem) or tell me the steps to do that.
Regards, FedericoHi all,
Maybe I didn't explain me as i should or maybe you dont know what is a Query View. Lets try again, showing you the steps to open a "Query view".
This way is from Bex Analyzer (Excel)
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This way is from Bex Web:
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The problem that we have is that the views created for a user, can NOT be found by other user. The only user who can is the owner.
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After login, you call securytest.jsp. Here, depending of the user you can
redirect him to the right page.
Romuald RICHARD
Developer Relations Engineer
BEA Support
"Scott" <[email protected]> wrote in message
news:[email protected]..
>
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"Romuald RICHARD" <[email protected]> wrote:
After your users are logged in, you can call a jsp which will do the
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"Scott Rodenhiser" <[email protected]> wrote in message
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Hi,
I have a requirement for two different users. User1 gets to enter everything into the database and User2 should only see what is in the database. User1 is ok. But, user2 if I give only select privilege on those tables, form doesn't work because it can't generate a new record. Could you suggest the right way of doing this? Thank you,
SrilakshmiOk. Let me try again.
I have a requirement for two different users.
User1 gets to enter everything into the database and
User2 should only read what is in the database.
User1 is ok.
But, user2 if I give only select privilege on those tables, form doesn't work.
Could you suggest the right way of achieving this? Thank you,
Srilakshmi -
Different users values from v$object_usage
Hi Gurus,
I have X_BANK user who is application user who owns all the tables of database.
We started index monitoring for all the indexes of X_BANK user.
But when we loggin to database / as sysdba, we are not able to see results of X_BANK and when we login to database with X_BANK then we see objects usage in v$object_usage.
Why we cann't see different users v$object_usage with /as sysdba
Please advice me and help me
Thanks & Regardsoramnts wrote:
Hi Gurus,
I have X_BANK user who is application user who owns all the tables of database.
We started index monitoring for all the indexes of X_BANK user.
But when we loggin to database / as sysdba, we are not able to see results of X_BANK and when we login to database with X_BANK then we see objects usage in v$object_usage.
Why we cann't see different users v$object_usage with /as sysdba
The object is a per user kind of object. Its not a centralized kind of view. Here is the same kind of thing in my test db,
REM- I am using here Sys user and would query the view. Also I shall create couple of tables and indexes in another schema and would see what the view shows in that schema.
Session-1(Sys)
SQL> select * from V$object_usage;
no rows selected
SQL> /
no rows selected
SQL> sbow use
SP2-0042: unknown command "sbow use" - rest of line ignored.
SQL> sho user
USER is "SYS"
SQL> exit
Session--2
Connected to:
Oracle Database 10g Enterprise Edition Release 10.2.0.1.0 - Production
With the Partitioning, OLAP and Data Mining options
SQL> create table test_ou(a number);
Table created.
SQL> create index testidx on test_ou(a);
Index created.
SQL> select * from V$object_usage;
no rows selected
SQL> alter index testidx monitoring usage;
Index altered.
SQL> select * from V$object_usage;
INDEX_NAME TABLE_NAME MON USE
START_MONITORING END_MONITORING
TESTIDX TEST_OU YES NO
09/18/2009 21:56:56
SQL> create table test2(a number);
Table created.
SQL> create index testidx2 on test2(a);
Index created.
SQL> alter index testidx2 monitoring usage;
Index altered.
SQL> select * from V$object_usage;
INDEX_NAME TABLE_NAME MON USE
START_MONITORING END_MONITORING
TESTIDX TEST_OU YES NO
09/18/2009 21:56:56
TESTIDX2 TEST2 YES NO
09/18/2009 21:57:26
SQL>Works exactly as it should be.
HTH
Aman.... -
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Can anyone suggest something to try next?
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so here ya go.
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AdapterDeviceID: 0x2a02
AdapterVendorID: 0x8086
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BuildID: 20120713134347
CrashTime: 1342655269
EMCheckCompatibility: true
Email: [email protected]
FramePoisonBase: 7ffffffff0dea000
FramePoisonSize: 4096
InstallTime: 1342655256
Notes: AdapterVendorID: 0x8086, AdapterDeviceID: 0x2a02GL Context? GL Context+ GL Layers? GL Layers+
ProductID: {ec8030f7-c20a-464f-9b0e-13a3a9e97384}
ProductName: Firefox
ReleaseChannel: release
StartupTime: 1342655256
Theme: classic/1.0
Throttleable: 1
URL: http://www.mozilla.org/en-US/firefox/14.0.1/whatsnew/?oldversion=rv:1.9.2.13
Vendor: Mozilla
Version: 14.0.1
This report also contains technical information about the state of the application when it crashed. -
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